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Revision History for A062707 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
Table by antidiagonals of n*k*(k+1)/2.
(history; published version)
#16 by Charles R Greathouse IV at Thu Sep 08 08:45:03 EDT 2022
PROG

(MAGMAMagma) [k*Binomial(n-k+1, 2): k in [0..n], n in [0..12]]; // G. C. Greubel, Sep 02 2019

Discussion
Thu Sep 08
08:45
OEIS Server: https://oeis.org/edit/global/2944
#15 by Joerg Arndt at Tue Sep 03 02:54:21 EDT 2019
STATUS

reviewed

approved

#14 by Michel Marcus at Tue Sep 03 01:29:36 EDT 2019
STATUS

proposed

reviewed

#13 by G. C. Greubel at Mon Sep 02 21:40:23 EDT 2019
STATUS

editing

proposed

#12 by G. C. Greubel at Mon Sep 02 21:39:33 EDT 2019
DATA

0, 0, 0, 0, 1, 0, 0, 3, 2, 0, 0, 6, 6, 3, 0, 0, 10, 12, 9, 4, 0, 0, 15, 20, 18, 12, 5, 0, 0, 21, 30, 30, 24, 15, 6, 0, 0, 28, 42, 45, 40, 30, 18, 7, 0, 0, 36, 56, 63, 60, 50, 36, 21, 8, 0, 0, 45, 72, 84, 84, 75, 60, 42, 24, 9, 0, 0, 55, 90, 108, 112, 105, 90, 70, 48, 27, 10, 0, 0, 66

LINKS

G. C. Greubel, <a href="/A062707/b062707.txt">Antidiagonals n = 0..100, flattened</a>

MAPLE

seq(seq(k*binomial(n-k+1, 2), k=0..n), n=0..12); # G. C. Greubel, Sep 02 2019

MATHEMATICA

Table[k*Binomial[n-k+1, 2], {n, 0, 12}, {k, 0, n}]//Flatten (* G. C. Greubel, Sep 02 2019 *)

PROG

(PARI) T(n, k) = k*binomial(n-k+1, 2);

for(n=0, 12, for(k=0, n, print1(T(n, k), ", "))) \\ G. C. Greubel, Sep 02 2019

(MAGMA) [k*Binomial(n-k+1, 2): k in [0..n], n in [0..12]]; // G. C. Greubel, Sep 02 2019

(Sage) [[k*binomial(n-k+1, 2) for k in (0..n)] for n in (0..12)] # G. C. Greubel, Sep 02 2019

(GAP) Flat(List([0..12], n-> List([0..n], k-> k*Binomial(n-k+1, 2)))); # G. C. Greubel, Sep 02 2019

STATUS

approved

editing

#11 by Joerg Arndt at Tue Dec 08 08:51:45 EST 2015
STATUS

proposed

approved

#10 by Michel Marcus at Tue Dec 08 06:33:30 EST 2015
STATUS

editing

proposed

#9 by Michel Marcus at Tue Dec 08 06:33:23 EST 2015
NAME

Table by antidiagonals of nkn*k*(k+1)/2.

FORMULA

T(n, k) = T(n, 1)*T(1, k) = A001477(n)*A000217(k) = A057145(n+2, k+1)-(k+1).

T(n, k) = A057145(n+2, k+1)-(k+1).

Discussion
Tue Dec 08
06:33
Michel Marcus: ok ?
#8 by Michel Marcus at Tue Dec 08 06:32:09 EST 2015
FORMULA

T(n, k) = T(n, 1)*T(1, k) = A001477(n)*A000217(k) = A057145(n+2, k+1)-(k+1).

STATUS

reviewed

editing

#7 by R. J. Mathar at Tue Dec 08 06:25:40 EST 2015
STATUS

proposed

reviewed