The On-Line Encyclopedia of Integer Sequences (OEIS)

Revision History for A039623 (Bold, blue-underlined text is an addition; faded, red-underlined text is a ~~deletion~~.)
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A039623

a(n) = n^2*(n^2+3)/4.
(history; published version)

#91 by Peter Luschny at Sun Nov 26 06:55:34 EST 2023

STATUS

reviewed

approved

#90 by Stefano Spezia at Sun Nov 26 04:05:57 EST 2023

STATUS

proposed

reviewed

#89 by Detlef Meya at Sun Nov 26 02:41:41 EST 2023

STATUS

editing

proposed

#88 by Detlef Meya at Sun Nov 26 02:40:44 EST 2023

FORMULA

a(n) = binomial(n,2)*binomial(n+1,2) + binomial(n,1)^2 = A006011(n) + A000290(n). - Detlef Meya, Nov 23 2023

STATUS

proposed

editing

#87 by Kevin Ryde at Fri Nov 24 19:11:22 EST 2023

STATUS

editing

proposed

Discussion

Sat Nov 25

04:36

Peter Luschny: Another way to write your formula is: a(n) = A006011(n) + A000290(n).

11:11

Detlef Meya: @Peter Luschny: Should i publish your solution under my name?

12:29

Peter Luschny: Yes of course, just add it with '=' directly to your formula. But also note Kevin's remark: writing binomial(n,1) for n will not be accepted.

#86 by Kevin Ryde at Fri Nov 24 19:10:51 EST 2023

FORMULA

a(n) = binomial(n,2)*binomial(n+1,2) + binomial(n,1)^2. - Detlef Meya, Nov 23 2023

Discussion

Fri Nov 24

19:11

Kevin Ryde: binomial(n,1) is just n ?

#85 by Kevin Ryde at Fri Nov 24 19:08:44 EST 2023

MATHEMATICA

a[n_]:=Binomial[n, 2]*Binomial[n+1, 2]+Binomial[n, 1]^2; Flatten[Table[a[n], {n, 1, 37}]] (* Detlef Meya, Nov 23 2023 *)

STATUS

proposed

editing

Discussion

Fri Nov 24

19:09

Kevin Ryde: yes, doesn't improve on existing

#84 by Michel Marcus at Fri Nov 24 01:49:32 EST 2023

STATUS

editing

proposed

#83 by Michel Marcus at Fri Nov 24 01:49:06 EST 2023

PROG

(PARI) lista(nn) = fora(n) =1, nn, print1( (1/4)*n^2*(n^2+3), ", ")); \\ Altug Alkan, Apr 16 2016

STATUS

proposed

editing

#82 by Detlef Meya at Thu Nov 23 22:27:56 EST 2023

STATUS

editing

proposed

Discussion

Fri Nov 24

01:47

Michel Marcus: the formula works but having a program based on this formula does not seem ok for me