JP4031249B2

JP4031249B2 - Inclined part high-speed escalator

Info

Publication number: JP4031249B2
Application number: JP2002014654A
Authority: JP
Inventors: 学小倉; 敬湯村; 康雅治田; 達也吉川; 長屋　　真司; 丈一中村
Original assignee: Mitsubishi Electric Corp
Current assignee: Mitsubishi Electric Corp
Priority date: 2002-01-23
Filing date: 2002-01-23
Publication date: 2008-01-09
Anticipated expiration: 2022-01-23
Also published as: CN1433955A; US6588573B1; CN1221461C; KR100467549B1; EP1331195B1; ATE509877T1; KR20030064260A; JP2003212465A; EP1331195A3; EP1331195A2

Abstract

An escalator with a high speed inclined section in which a position of a link connection point is determined by the following equations: <DF>XM=X1+L1cosä beta - gamma ü, </DF> and <DF>YM=Y1+L1sinä beta - gamma ü </DF> (where beta =tan<-1>ä(Y1-Y2)/(X1-X2)ü; gamma =cos<-1>ä(L1<2>-L2<2>+W<2>)/2L1Wü; W= 2ROOT ä(X1-X2)+(Y1-Y2)ü; XM: horizontal coordinate of the link connection point; YM: vertical coordinate of the link connection point; L1: a distance from axis of an upper-step-side step link roller shaft to the link connection point; and L2: a distance from axis of a lower-step-side step link roller shaft to the link connection point). <IMAGE>

Description

【０００１】
【発明の属する技術分野】
この発明は、中間傾斜部における踏段の移動速度が上側乗降口部及び下側乗降口部における踏段の移動速度よりも速い傾斜部高速エスカレーターに関するものである。
【０００２】
【従来の技術】
図１１は例えば特開昭５１−１１６５８６号公報に示された従来の傾斜部高速エスカレーターの要部を示す側面図である。図において、主枠１には、無端状に連結され循環移動される複数の踏段２が設けられている。各踏段２は、踏板３、踏板３の下段側一端部に屈曲形成されているライザー４、踏板３の幅方向に延びる駆動ローラ軸５、駆動ローラ軸５を中心として回転可能な一対の駆動ローラ６、駆動ローラ軸５に平行に延びる追従ローラ軸７、及び追従ローラ軸７を中心として回転可能な一対の追従ローラ８を有している。
【０００３】
互いに隣接する踏段２の駆動ローラ軸５は、一対のリンク機構９により互いに連結されている。各リンク機構９には、補助ローラ１０が設けられている。
【０００４】
主枠１には、踏段２の循環路を形成し駆動ローラ６を案内する一対の駆動レール１１、追従ローラ７を案内し踏段２の姿勢を制御するための一対の追従レール１２、及び補助ローラ１０を案内し隣接する踏段２の間隔を変化させるための一対の補助レール１３が設けられている。
【０００５】
このような従来の傾斜部高速エスカレーターでは、補助レール１３の形状に応じて駆動ローラ軸５に対して補助ローラ１０が変位されることにより、リンク機構９が屈伸するように変態され、隣接する駆動ローラ軸５の間隔が変化される。これにより、踏段２の移動速度が循環路内の位置に応じて変化される。即ち、上側及び下側乗降口部では低速運行され、中間傾斜部では高速運行される。
【０００６】
【発明が解決しようとする課題】
上記のように構成された従来の傾斜部高速エスカレーターにおいては、ライザー４が平面状の形状を有しているのに対して、変速領域の補助レール１３の形状が滑らかな円弧状になっている。このため、互いに隣接する踏段２の段差が変化する過程で、踏板３の端部が、上段側に隣接する踏段２のライザー４の表面に沿う軌跡で変位せず、ライザー４と干渉したり、ライザー４との間に隙間が生じるなどの問題があった。
【０００７】
この発明は、上記のような問題点を解決することを課題としてなされたものであり、隣接する踏段の段差が変化する過程で、隣接する踏段のライザーに踏板が干渉したり、ライザーと踏板との間に隙間が生じたりするのを防止することができる傾斜部高速エスカレーターを得ることを目的とする。
【０００８】
【課題を解決するための手段】
この発明に係る傾斜部高速エスカレーターは、主枠、主枠に設けられ、上側乗降口部と、下側乗降口部と、上側乗降口部と下側乗降口部との間に位置する中間傾斜部と、上側乗降口部と中間傾斜部との間に位置する上曲部と、下側乗降口部と中間傾斜部との間に位置する下曲部とを含む循環路を形成する駆動レール、駆動ローラ軸と、駆動ローラ軸を中心として回転可能であり、駆動レールに案内されて転動する駆動ローラとをそれぞれ有し、無端状に連結され循環路に沿って循環移動される複数の踏段、駆動ローラ軸に回動自在に連結されている第１のリンクと、第１のリンクのリンク連結点及び隣接する踏段の駆動ローラ軸に回動自在に連結されている第２のリンクとをそれぞれ有し、屈伸動作を行うことにより駆動ローラ軸の間隔を変化させる複数のリンク機構、各リンク機構にそれぞれ設けられている回転自在の補助ローラ、及び主枠に設けられ、補助ローラの移動を案内しリンク機構を屈伸動作させ、踏段の移動速度を上側変速部と下側変速部とで変化させる補助レールを備え、隣接する駆動ローラ軸の軸心が上側変速部にあって、その駆動ローラ軸の軸心の水平方向及び垂直方向の相対座標を（Ｘ_Ｓ，Ｙ_Ｓ）、上曲部における駆動ローラ軸の軸心の移動軌跡の曲率半径をＲ_１、駆動ローラ軸の軸心の移動軌跡の上側乗降口部と上曲部との境界点から垂直方向に−Ｒ_１だけ離れた点を座標の原点として、Ｙ_Ｓの範囲が−Ｒ_１＋√（Ｒ_１ ^２−Ｘ_Ｓ ^２）≦Ｙ_Ｓ＜０であるとき、上側変速部における隣接する駆動ローラの相対位置と、上段側の駆動ローラ軸の軸心の水平方向の座標Ｘ_１、上段側の駆動ローラ軸の軸心の水平方向の座標Ｙ_１、下段側の駆動ローラ軸の軸心の水平方向の座標Ｘ_２、及び下段側の駆動ローラ軸の軸心の水平方向の座標Ｙ_２との関係は、式Ｘ_１＝−Ｘ_Ｓ＋√（−２Ｒ_１・Ｙ_Ｓ−Ｙ_Ｓ ^２）、Ｙ_１＝Ｒ_１、Ｘ_２＝Ｘ_１＋Ｘ_Ｓ、及びＹ_２＝Ｙ_１＋Ｙ_Ｓで表され、リンク連結点の位置は、式Ｘ_Ｍ＝Ｘ_１＋Ｌ_１ｃｏｓ｛β−γ｝、及びＹ_Ｍ＝Ｙ_１＋Ｌ_１ｓｉｎ｛β−γ｝（ただし、β＝ｔａｎ^−１｛（Ｙ_１−Ｙ_２）／（Ｘ_１−Ｘ_２）｝、γ＝ｃｏｓ^−１｛（Ｌ_１ ^２−Ｌ_２ ^２＋Ｗ^２）／２Ｌ_１Ｗ｝、Ｗ＝√｛（Ｘ_１−Ｘ_２）^２＋（Ｙ_１−Ｙ_２）^２｝、Ｘ_Ｍ：リンク連結点の水平方向の座標、Ｙ_Ｍ：リンク連結点の垂直方向の座標、Ｌ_１：上段側の駆動ローラ軸の軸心からリンク連結点までの長さ、Ｌ_２：下段側の駆動ローラ軸の軸心からリンク連結点までの長さ）により設定されている。
【０００９】
また、この発明に係る傾斜部高速エスカレーターは、主枠、主枠に設けられ、上側乗降口部と、下側乗降口部と、上側乗降口部と下側乗降口部との間に位置する中間傾斜部と、上側乗降口部と中間傾斜部との間に位置する上曲部と、下側乗降口部と中間傾斜部との間に位置する下曲部とを含む循環路を形成する駆動レール、駆動ローラ軸と、駆動ローラ軸を中心として回転可能であり、駆動レールに案内されて転動する駆動ローラとをそれぞれ有し、無端状に連結され循環路に沿って循環移動される複数の踏段、駆動ローラ軸に回動自在に連結されている第１のリンクと、第１のリンクのリンク連結点及び隣接する踏段の駆動ローラ軸に回動自在に連結されている第２のリンクとをそれぞれ有し、屈伸動作を行うことにより駆動ローラ軸の間隔を変化させる複数のリンク機構、各リンク機構にそれぞれ設けられている回転自在の補助ローラ、及び主枠に設けられ、補助ローラの移動を案内しリンク機構を屈伸動作させ、踏段の移動速度を上側変速部と下側変速部とで変化させる補助レールを備え、隣接する駆動ローラ軸の軸心が上側変速部にあって、その駆動ローラ軸の軸心の水平方向及び垂直方向の相対座標を（Ｘ_Ｓ，Ｙ_Ｓ）、上曲部における駆動ローラ軸の軸心の移動軌跡の曲率半径をＲ_１、中間傾斜部の斜度をα_ｍ、駆動ローラ軸の軸心の移動軌跡の上側乗降口部と上曲部との境界点から垂直方向に−Ｒ_１だけ離れた点を座標の原点として、Ｙ_Ｓの範囲がＲ_１ｃｏｓα_ｍ−√｛（Ｒ_１ｃｏｓα_ｍ）^２＋（２Ｒ_１ｓｉｎα_ｍ・Ｘ_Ｓ−Ｘ_Ｓ ^２）｝≦Ｙ_Ｓ＜−Ｒ_１＋√（Ｒ_１ ^２−Ｘ_Ｓ ^２）であるとき、上側変速部における隣接する駆動ローラの相対位置と、上段側の駆動ローラ軸の軸心の水平方向の座標Ｘ_１、上段側の駆動ローラ軸の軸心の水平方向の座標Ｙ_１、下段側の駆動ローラ軸の軸心の水平方向の座標Ｘ_２、及び下段側の駆動ローラ軸の軸心の水平方向の座標Ｙ_２との関係は、式Ｘ_１＝[−ｐ_１ｑ_１＋√{(ｐ_１ｑ_１)^２−(ｐ_１ ^２＋１)(ｑ_１ ^２−Ｒ_１ ^２)}]／(ｐ_１ ^２＋１)、Ｙ_１＝√（Ｒ_１ ^２−Ｘ₁ ^２）、Ｘ_２＝Ｘ_１＋Ｘ_Ｓ、及びＹ_２＝Ｙ_１＋Ｙ_Ｓ（ただし、ｐ_１＝Ｘ_Ｓ／Ｙ_Ｓ、ｑ_１＝（Ｘ_Ｓ ^２＋Ｙ_Ｓ ^２）／２Ｙ_Ｓ）で表され、リンク連結点の位置は、式Ｘ_Ｍ＝Ｘ_１＋Ｌ_１ｃｏｓ｛β−γ｝）、及びＹ_Ｍ＝Ｙ_１＋Ｌ_１ｓｉｎ｛β−γ｝（ただし、β＝ｔａｎ^−１｛（Ｙ_１−Ｙ_２）／（Ｘ_１−Ｘ_２）｝、γ＝ｃｏｓ^−１｛（Ｌ_１ ^２−Ｌ_２ ^２＋Ｗ^２）／２Ｌ_１Ｗ｝、Ｗ＝√｛（Ｘ_１−Ｘ_２）^２＋（Ｙ_１−Ｙ_２）^２｝、Ｘ_Ｍ：リンク連結点の水平方向の座標、Ｙ_Ｍ：リンク連結点の垂直方向の座標、Ｌ_１：上段側の駆動ローラ軸の軸心からリンク連結点までの長さ、Ｌ_２：下段側の駆動ローラ軸の軸心からリンク連結点までの長さ）により設定されているものである。
【００１０】
また、この発明に係る傾斜部高速エスカレーターは、主枠、主枠に設けられ、上側乗降口部と、下側乗降口部と、上側乗降口部と下側乗降口部との間に位置する中間傾斜部と、上側乗降口部と中間傾斜部との間に位置する上曲部と、下側乗降口部と中間傾斜部との間に位置する下曲部とを含む循環路を形成する駆動レール、駆動ローラ軸と、駆動ローラ軸を中心として回転可能であり、駆動レールに案内されて転動する駆動ローラとをそれぞれ有し、無端状に連結され循環路に沿って循環移動される複数の踏段、駆動ローラ軸に回動自在に連結されている第１のリンクと、第１のリンクのリンク連結点及び隣接する踏段の駆動ローラ軸に回動自在に連結されている第２のリンクとをそれぞれ有し、屈伸動作を行うことにより駆動ローラ軸の間隔を変化させる複数のリンク機構、各リンク機構にそれぞれ設けられている回転自在の補助ローラ、及び主枠に設けられ、補助ローラの移動を案内しリンク機構を屈伸動作させ、踏段の移動速度を上側変速部と下側変速部とで変化させる補助レールを備え、隣接する駆動ローラ軸の軸心が上側変速部にあって、その駆動ローラ軸の軸心の水平方向及び垂直方向の相対座標を（Ｘ_Ｓ，Ｙ_Ｓ）、上曲部における駆動ローラ軸の軸心の移動軌跡の曲率半径をＲ_１、中間傾斜部の斜度をα_ｍ、駆動ローラ軸の軸心の移動軌跡の上側乗降口部と上曲部との境界点から垂直方向に−Ｒ_１だけ離れた点を座標の原点として、Ｙ_Ｓの範囲が−Ｘ_Ｓｔａｎα_ｍ≦Ｙ_Ｓ＜Ｒ_１ｃｏｓα_ｍ−√｛（Ｒ_１ｃｏｓα_ｍ）^２＋（２Ｒ_１ｓｉｎα_ｍ・Ｘ_Ｓ−Ｘ_Ｓ ^２）｝であるとき、上側変速部における隣接する駆動ローラの相対位置と、上段側の駆動ローラ軸の軸心の水平方向の座標Ｘ_１、上段側の駆動ローラ軸の軸心の水平方向の座標Ｙ_１、下段側の駆動ローラ軸の軸心の水平方向の座標Ｘ_２、及び下段側の駆動ローラ軸の軸心の水平方向の座標Ｙ_２との関係は、式Ｘ_１＝［−ｐ_２ｓ−√{(ｐ_２ｓ)^２−(ｐ_２ ^２＋１)(ｓ^２−Ｒ^２)}］／(ｐ_２ ^２＋１)、Ｙ_１＝√（Ｒ_１ ^２−Ｘ₁ ^２）、Ｘ_２＝Ｘ_１＋Ｘ_Ｓ、及びＹ_２＝Ｙ_１＋Ｙ_Ｓ（ただし、ｐ_２＝−ｔａｎα_ｍ、ｑ_２＝Ｒ_１（ｃｏｓα_ｍ＋ｓｉｎα_ｍ・ｔａｎα_ｍ）、ｓ＝ｐ_２Ｘ_Ｓ＋ｑ_２−Ｙ_Ｓ）で表され、リンク連結点の位置は、式Ｘ_Ｍ＝Ｘ_１＋Ｌ_１ｃｏｓ｛β−γ｝）、及びＹ_Ｍ＝Ｙ_１＋Ｌ_１ｓｉｎ｛β−γ｝（ただし、β＝ｔａｎ^−１｛（Ｙ_１−Ｙ_２）／（Ｘ_１−Ｘ_２）｝、γ＝ｃｏｓ^−１｛（Ｌ_１ ^２−Ｌ_２ ^２＋Ｗ^２）／２Ｌ_１Ｗ｝、Ｗ＝√｛（Ｘ_１−Ｘ_２）^２＋（Ｙ_１−Ｙ_２）^２｝、Ｘ_Ｍ：リンク連結点の水平方向の座標、Ｙ_Ｍ：リンク連結点の垂直方向の座標、Ｌ_１：上段側の駆動ローラ軸の軸心からリンク連結点までの長さ、Ｌ_２：下段側の駆動ローラ軸の軸心からリンク連結点までの長さ）により設定されているものである。
【００１１】
また、この発明に係る傾斜部高速エスカレーターは、主枠、主枠に設けられ、上側乗降口部と、下側乗降口部と、上側乗降口部と下側乗降口部との間に位置する中間傾斜部と、上側乗降口部と中間傾斜部との間に位置する上曲部と、下側乗降口部と中間傾斜部との間に位置する下曲部とを含む循環路を形成する駆動レール、駆動ローラ軸と、駆動ローラ軸を中心として回転可能であり、駆動レールに案内されて転動する駆動ローラとをそれぞれ有し、無端状に連結され循環路に沿って循環移動される複数の踏段、駆動ローラ軸に回動自在に連結されている第１のリンクと、第１のリンクのリンク連結点及び隣接する踏段の駆動ローラ軸に回動自在に連結されている第２のリンクとをそれぞれ有し、屈伸動作を行うことにより駆動ローラ軸の間隔を変化させる複数のリンク機構、各リンク機構にそれぞれ設けられている回転自在の補助ローラ、及び主枠に設けられ、補助ローラの移動を案内しリンク機構を屈伸動作させ、踏段の移動速度を上側変速部と下側変速部とで変化させる補助レールを備え、隣接する駆動ローラ軸の軸心が下側変速部にあって、その駆動ローラ軸の軸心の水平方向及び垂直方向の相対座標を（Ｘ_Ｓ，Ｙ_Ｓ）、下曲部における駆動ローラ軸の軸心の移動軌跡の曲率半径をＲ_２、駆動ローラ軸の軸心の移動軌跡の下側乗降口部と下曲部との境界点から垂直方向にＲ_２だけ離れた点を座標の原点として、Ｙ_Ｓの範囲が−Ｒ_２＋√（Ｒ_２ ^２−Ｘ_Ｓ ^２）≦Ｙ_Ｓ＜０であるとき、下側変速部における隣接する駆動ローラの相対位置と、上段側の駆動ローラ軸の軸心の水平方向の座標Ｘ_１、上段側の駆動ローラ軸の軸心の水平方向の座標Ｙ_１、下段側の駆動ローラ軸の軸心の水平方向の座標Ｘ_２、及び下段側の駆動ローラ軸の軸心の水平方向の座標Ｙ_２との関係は、式Ｘ_１＝−√（２Ｒ_２・Ｙ_Ｓ−Ｙ_Ｓ ^２）、Ｙ_１＝−√（Ｒ_２ ^２−Ｘ₁ ^２）、Ｘ_２＝Ｘ_１＋Ｘ_Ｓ、及びＹ_２＝Ｙ_１＋Ｙ_Ｓで表され、リンク連結点の位置は、式Ｘ_Ｍ＝Ｘ_１＋Ｌ_１ｃｏｓ｛β−γ｝）、及びＹ_Ｍ＝Ｙ_１＋Ｌ_１ｓｉｎ｛β−γ｝（ただし、β＝ｔａｎ^−１｛（Ｙ_１−Ｙ_２）／（Ｘ_１−Ｘ_２）｝、γ＝ｃｏｓ^−１｛（Ｌ_１ ^２−Ｌ_２ ^２＋Ｗ^２）／２Ｌ_１Ｗ｝、Ｗ＝√｛（Ｘ_１−Ｘ_２）^２＋（Ｙ_１−Ｙ_２）^２｝、Ｘ_Ｍ：リンク連結点の水平方向の座標、Ｙ_Ｍ：リンク連結点の垂直方向の座標、Ｌ_１：上段側の駆動ローラ軸の軸心からリンク連結点までの長さ、Ｌ_２：下段側の駆動ローラ軸の軸心からリンク連結点までの長さ）により設定されているものである。
【００１２】
また、この発明に係る傾斜部高速エスカレーターは、主枠、主枠に設けられ、上側乗降口部と、下側乗降口部と、上側乗降口部と下側乗降口部との間に位置する中間傾斜部と、上側乗降口部と中間傾斜部との間に位置する上曲部と、下側乗降口部と中間傾斜部との間に位置する下曲部とを含む循環路を形成する駆動レール、駆動ローラ軸と、駆動ローラ軸を中心として回転可能であり、駆動レールに案内されて転動する駆動ローラとをそれぞれ有し、無端状に連結され循環路に沿って循環移動される複数の踏段、駆動ローラ軸に回動自在に連結されている第１のリンクと、第１のリンクのリンク連結点及び隣接する踏段の駆動ローラ軸に回動自在に連結されている第２のリンクとをそれぞれ有し、屈伸動作を行うことにより駆動ローラ軸の間隔を変化させる複数のリンク機構、各リンク機構にそれぞれ設けられている回転自在の補助ローラ、及び主枠に設けられ、補助ローラの移動を案内しリンク機構を屈伸動作させ、踏段の移動速度を上側変速部と下側変速部とで変化させる補助レールを備え、隣接する駆動ローラ軸の軸心が下側変速部にあって、その駆動ローラ軸の軸心の水平方向及び垂直方向の相対座標を（Ｘ_Ｓ，Ｙ_Ｓ）、下曲部における駆動ローラ軸の軸心の移動軌跡の曲率半径をＲ_２、中間傾斜部の斜度をα_ｍ、駆動ローラ軸の軸心の移動軌跡の下側乗降口部と下曲部との境界点から垂直方向にＲ_２だけ離れた点を座標の原点として、Ｙ_Ｓの範囲がＲ_２ｃｏｓα_ｍ−√｛（Ｒ_２ｃｏｓα_ｍ）^２＋（２Ｒ_２ｓｉｎα_ｍ・Ｘ_Ｓ−Ｘ_Ｓ ^２）｝≦Ｙ_Ｓ＜−Ｒ_２＋√（Ｒ_２ ^２−Ｘ_Ｓ ^２）であるとき、下側変速部における隣接する駆動ローラの相対位置と、上段側の駆動ローラ軸の軸心の水平方向の座標Ｘ_１、上段側の駆動ローラ軸の軸心の水平方向の座標Ｙ_１、下段側の駆動ローラ軸の軸心の水平方向の座標Ｘ_２、及び下段側の駆動ローラ軸の軸心の水平方向の座標Ｙ_２との関係は、式Ｘ_１＝[−ｐ_３ｑ_３−√{(ｐ_３ｑ_３)^２−(ｐ_３ ^２＋１)(ｑ_３ ^２−Ｒ_２ ^２)}]／(ｐ_３ ^２＋１)、Ｙ_１＝−√（Ｒ_２ ^２−Ｘ₁ ^２）、Ｘ_２＝Ｘ_１＋Ｘ_Ｓ、及びＹ_２＝Ｙ_１＋Ｙ_Ｓ（ただし、ｐ_３＝Ｘ_Ｓ／Ｙ_Ｓ、ｑ_３＝（Ｘ_Ｓ ^２＋Ｙ_Ｓ ^２）／２Ｙ_Ｓ）で表され、リンク連結点の位置は、式Ｘ_Ｍ＝Ｘ_１＋Ｌ_１ｃｏｓ｛β−γ｝）、及びＹ_Ｍ＝Ｙ_１＋Ｌ_１ｓｉｎ｛β−γ｝（ただし、β＝ｔａｎ^−１｛（Ｙ_１−Ｙ_２）／（Ｘ_１−Ｘ_２）｝、γ＝ｃｏｓ^−１｛（Ｌ_１ ^２−Ｌ_２ ^２＋Ｗ^２）／２Ｌ_１Ｗ｝、Ｗ＝√｛（Ｘ_１−Ｘ_２）^２＋（Ｙ_１−Ｙ_２）^２｝、Ｘ_Ｍ：リンク連結点の水平方向の座標、Ｙ_Ｍ：リンク連結点の垂直方向の座標、Ｌ_１：上段側の駆動ローラ軸の軸心からリンク連結点までの長さ、Ｌ_２：下段側の駆動ローラ軸の軸心からリンク連結点までの長さ）により設定されているものである。
【００１３】
また、この発明に係る傾斜部高速エスカレーターは、主枠、主枠に設けられ、上側乗降口部と、下側乗降口部と、上側乗降口部と下側乗降口部との間に位置する中間傾斜部と、上側乗降口部と中間傾斜部との間に位置する上曲部と、下側乗降口部と中間傾斜部との間に位置する下曲部とを含む循環路を形成する駆動レール、駆動ローラ軸と、駆動ローラ軸を中心として回転可能であり、駆動レールに案内されて転動する駆動ローラとをそれぞれ有し、無端状に連結され循環路に沿って循環移動される複数の踏段、駆動ローラ軸に回動自在に連結されている第１のリンクと、第１のリンクのリンク連結点及び隣接する踏段の駆動ローラ軸に回動自在に連結されている第２のリンクとをそれぞれ有し、屈伸動作を行うことにより駆動ローラ軸の間隔を変化させる複数のリンク機構、各リンク機構にそれぞれ設けられている回転自在の補助ローラ、及び主枠に設けられ、補助ローラの移動を案内しリンク機構を屈伸動作させ、踏段の移動速度を上側変速部と下側変速部とで変化させる補助レールを備え、隣接する駆動ローラ軸の軸心が下側変速部にあって、その駆動ローラ軸の軸心の水平方向及び垂直方向の相対座標を（Ｘ_Ｓ，Ｙ_Ｓ）、下曲部における駆動ローラ軸の軸心の移動軌跡の曲率半径をＲ_２、中間傾斜部の斜度をα_ｍ、駆動ローラ軸の軸心の移動軌跡の下側乗降口部と下曲部との境界点から垂直方向にＲ_２だけ離れた点を座標の原点として、Ｙ_Ｓの範囲が−Ｘ_Ｓｔａｎα_ｍ≦Ｙ_Ｓ＜Ｒ_２ｃｏｓα_ｍ−√｛（Ｒ_２ｃｏｓα_ｍ）^２＋（２Ｒ_２ｓｉｎα_ｍ・Ｘ_Ｓ−Ｘ_Ｓ ^２）｝であるとき、下側変速部における隣接する駆動ローラの相対位置と、上段側の駆動ローラ軸の軸心の水平方向の座標Ｘ_１、上段側の駆動ローラ軸の軸心の水平方向の座標Ｙ_１、下段側の駆動ローラ軸の軸心の水平方向の座標Ｘ_２、及び下段側の駆動ローラ軸の軸心の水平方向の座標Ｙ_２との関係は、式Ｘ_１＝{−(ｐ_４ｑ_４＋ｐ_４Ｙ_Ｓ＋Ｘ_ｓ)＋√Ａ_１}／(ｐ_４ ^２＋１)、Ａ_１＝(ｐ_４ｑ_４＋ｐ_４Ｙ_Ｓ＋Ｘ_Ｓ)^２−(ｐ_４ ^２＋１){(ｑ_４＋Ｙ_ｓ)^２−Ｒ_２ ^２＋Ｘ_Ｓ ^２}、Ｙ_１＝ｐ_４Ｘ_１＋ｑ_４Ｘ_２＝Ｘ_１＋Ｘ_Ｓ、及びＹ_２＝Ｙ_１＋Ｙ_Ｓ（ただし、ｐ_４＝−ｔａｎα_ｍ、ｑ_４＝−Ｒ_２（ｃｏｓα_ｍ＋ｓｉｎα_ｍ・ｔａｎα_ｍ））で表され、リンク連結点の位置は、式Ｘ_Ｍ＝Ｘ_１＋Ｌ_１ｃｏｓ｛β−γ｝）、及びＹ_Ｍ＝Ｙ_１＋Ｌ_１ｓｉｎ｛β−γ｝（ただし、β＝ｔａｎ^−１｛（Ｙ_１−Ｙ_２）／（Ｘ_１−Ｘ_２）｝、γ＝ｃｏｓ^−１｛（Ｌ_１ ^２−Ｌ_２ ^２＋Ｗ^２）／２Ｌ_１Ｗ｝、Ｗ＝√｛（Ｘ_１−Ｘ_２）^２＋（Ｙ_１−Ｙ_２）^２｝、Ｘ_Ｍ：リンク連結点の水平方向の座標、Ｙ_Ｍ：リンク連結点の垂直方向の座標、Ｌ_１：上段側の駆動ローラ軸の軸心からリンク連結点までの長さ、Ｌ_２：下段側の駆動ローラ軸の軸心からリンク連結点までの長さ）により設定されているものである。
【００１４】
また、第１のリンクは、その一部が屈曲した形状を有しており、隣接する駆動ローラの相対位置から、補助ローラの軸心の位置は、式Ｘ_Ｎ＝Ｘ_１＋Ｖｃｏｓ｛β−γ−δ｝、及びＹ_Ｎ＝Ｙ_１＋Ｖｓｉｎ｛β−γ−δ｝（ただし、Ｖ＝√（Ｌ_１ ^２＋Ｌ_３ ^２−２Ｌ_１Ｌ_３ｃｏｓθ）、δ＝ｓｉｎ^−１（Ｌ_３ｓｉｎθ／Ｖ）、Ｘ_Ｎ：補助ローラの軸心の水平方向の座標、Ｙ_Ｎ：補助ローラの軸心の垂直方向の座標、Ｌ_３：リンク連結点から補助ローラの軸心までの長さ、θ：上段側の駆動ローラ軸の軸心とリンク連結点とを結ぶ線分と、補助ローラの軸心とリンク連結点とを結ぶ線分とのなす角度の大きさ）により設定されている。
【００１５】
【発明の実施の形態】
以下、この発明の実施の形態を図について説明する。
実施の形態１．
図１はこの発明の実施の形態１による傾斜部高速エスカレーターを示す側面図である。図において、図において、主枠１には、無端状に連結された複数の踏段２が設けられている。踏段２は、駆動ユニット１４により駆動され、循環移動される。主枠１には、踏段２の循環路を形成する一対の駆動レール２１、踏段２の姿勢を制御するための一対の追従レール２２、及び隣接する踏段２の間隔を変化させるための一対の補助レール２３が設けられている。
【００１６】
駆動レール２１により形成される踏段２の循環路は、往路側区間、帰路側区間、上側反転部及び下側反転部を有している。また、循環路の往路側区間は、水平な上側乗降口部（上側水平部）Ａ、上側変速部である上曲部Ｂ、傾斜角度が一定の中間傾斜部（一定傾斜部）Ｃ、下側変速部である下曲部Ｄ、及び水平な下側乗降口部（下側水平部）Ｅを含んでいる。
【００１７】
中間傾斜部Ｃは、上側乗降口部Ａと下側乗降口部Ｅとの間に位置している。上曲部Ｂは、上側乗降口部Ａと中間傾斜部Ｃとの間に位置している。下曲部Ｄは、下側乗降口部Ｅと中間傾斜部Ｃとの間に位置している。
【００１８】
図２は図１の上側反転部付近を拡大して示す側面図である。各踏段２は、乗客を乗せる踏板３、踏板３の下段側端部に屈曲形成されたライザー４、踏板３の幅方向に沿って延びる駆動ローラ軸５、駆動ローラ軸５を中心として回転自在な一対の駆動ローラ６、駆動ローラ軸５と平行に延びる追従ローラ軸７、及び追従ローラ軸７を中心として回転自在な一対の追従ローラ８を有している。駆動ローラ６は、駆動レール２１に沿って転動する。追従ローラ８は、追従レール２２に沿って転動する。
【００１９】
互いに隣接する踏段２の駆動ローラ軸５は、一対のリンク機構（屈折リンク）２４により互いに連結されている。各リンク機構２４は、第１及び第２のリンク２５，２６を有している。
【００２０】
第１のリンク２５の一端部は、駆動ローラ軸５に回動自在に連結されている。第１のリンク２５の他端部には、回転自在の補助ローラ２７が設けられている。補助ローラ２７は、補助レール２３に沿って転動する。第２のリンク２６の一端部は、第１のリンク２５の中間部に位置するリンク連結点に、軸２８を介して回動自在に連結されている。また、第２のリンク２６の他端部は、下段側に隣接する踏段２の駆動ローラ軸５に回動自在に連結されている。
【００２１】
第１のリンク２５は、リンク連結点を中心として屈曲されたくの字状の形状を有している。また、第２のリンク２６は、直線状の形状を有している。
【００２２】
補助ローラ２７が補助レール２３で案内されることにより、リンク機構２４が屈伸するように変態し、駆動ローラ軸５の間隔、即ち隣接する踏段２相互の間隔が変化される。逆に言えば、隣接する踏段２相互の間隔が変化するように、補助レール２３の軌道が設計されている。
【００２３】
次に、動作について説明する。踏段２の循環路の往路側区間のうち、上側乗降口部Ａ及び下側乗降口部Ｅでは、駆動ローラ軸５の間隔が最小になっている。この状態から、駆動レール２１と補助レール２３との間の間隔が小さくなると、第１及び第２のリンク２５，２６のなす角度が大きくなり、駆動ローラ軸５の間隔が大きくなる。中間傾斜部Ｃでは、駆動レール２１と補助レール２３との間の間隔が最小であり、駆動ローラ軸５の間隔が最大になっている。
【００２４】
踏段２の速度は、駆動ローラ軸５の間隔を変化させることにより変化される。即ち、乗客が乗り降りする上側及び下側乗降口部Ａ、Ｅでは、駆動ローラ軸５の間隔が最小となり、踏段２は低速で移動される。また、中間傾斜部Ｃでは、駆動ローラ軸５の間隔が最大となり、踏段２は高速で移動される。さらに、上曲部Ｂ及び下曲部Ｄでは、駆動ローラ軸５の間隔が変化され、踏段２は加減速される。
【００２５】
次に、図３〜図９により、実施の形態１によるリンク連結点の位置の設定方法について説明する。図３は図１の上側乗降口部Ａ及び上曲部Ｂ付近の駆動ローラ軸５の軸心の移動軌跡を示す説明図である。図において、上曲部Ｂにおける駆動ローラ軸５の軸心の移動軌跡の曲率半径はＲ_１である。また、座標の原点は、駆動ローラ軸５の軸心の移動軌跡３上の上側乗降口部Ａと上曲部Ｂとの境界点２９から垂直方向（ｙ方向）に−Ｒ_１だけ離れた点にとっている。
【００２６】
ここで、上段側の踏段２の駆動ローラ６ａの軸心（駆動ローラ軸５の軸心）は、上側乗降口部Ａに位置し、その座標は（Ｘ_１，Ｘ_２）であるとする。また、下段側の踏段２の駆動ローラ６ｂの軸心（駆動ローラ軸５の軸心）は、上曲部Ｂに位置し、その座標は（Ｘ_２，Ｘ_２）であるとする。さらに、上段側の踏段２の駆動ローラ６ａの軸心に対する下段側の踏段の駆動ローラ６ｂの軸心の相対位置は（Ｘ_Ｓ，Ｙ_Ｓ）であるとする。
【００２７】
このときの上側乗降口部Ａにおける駆動ローラ６ａの軸心の移動軌跡は、
ｙ＝Ｒ_１
と表されるので、上段側の駆動ローラ軸６ａの軸心の座標の関係は、
Ｙ_１＝Ｒ_１・・・（１）
である。また、上曲部Ｂでは、
ｙ^２＝Ｒ_１ ^２−ｘ^２
の関係が成り立ち、下段側の踏段の駆動ローラ６ｂの軸心の座標は、
（Ｘ_２，Ｙ_２）＝（Ｘ_１＋Ｘ_Ｓ，Ｙ_１＋Ｙ_Ｓ）
である。このため、下段側の駆動ローラ６ｂの軸心の座標の関係は、
（Ｙ_１＋Ｙ_Ｓ）^２＝Ｒ_１ ^２−（Ｘ_１＋Ｘ_Ｓ）^２・・・（２）
である。
【００２８】
ここで、（１）式及び（２）式の双方を満たす（Ｘ_１，Ｙ_１）が、上段側の踏段２の駆動ローラ６ａの軸心に対する下段側の踏段２の駆動ローラ６ｂの軸心の相対位置が（Ｘ_Ｓ，Ｙ_Ｓ）のときの上段側の駆動ローラ６ａの軸心の座標であるので、（１）式及び（２）式を連立させて、Ｘ_１を求める。
【００２９】
まず、（２）式に（１）式を代入して変形すると、次の（３）式が求められる。
Ｘ_１ ^２＋２Ｘ_ＳＸ_１＋（Ｘ_Ｓ ^２＋２Ｒ_１Ｙ_Ｓ＋Ｙ_Ｓ ^２）＝０・・・（３）
次に、（３）式を二次方程式の解の公式でＸ_１について解く。
Ｘ_１＝−Ｘ_Ｓ＋√（−２Ｒ_１・Ｙ_Ｓ−Ｙ_Ｓ ^２）・・・（４）
そのＹ座標は（３）式より
Ｙ_１＝Ｒ
であり、下段側の踏段の駆動ローラ６ｂの軸心の座標は、（Ｘ_１＋Ｘ_Ｓ，Ｙ_１＋Ｙ_Ｓ）である。
【００３０】
ただし、この関係は、下段側の駆動ローラ６ｂの軸心が境界点２９に位置するときと、上段側の駆動ローラ６ａの軸心が境界点２９に位置するときとの間の領域（上段側の駆動ローラ軸５の軸心が上側乗降口部Ａに、下段側の駆動ローラ軸５の軸心が上曲部Ｂに位置している状態）で適用される。下段側の駆動ローラ６ｂの軸心が境界点２９に位置する状態は、（２）式を適用できる上曲部Ｂの上側乗降口部Ａ側の限界点である。また、上段側の駆動ローラ６ａの軸心が境界点２９に位置する状態は、（１）式を適用できる上側乗降口部Ａの上曲部Ｂ側の限界点である。
【００３１】
下段側の駆動ローラ６ｂの軸心が上側乗降口部Ａと上曲部Ｂとの境界点２９に位置するときは、（２）式においてＹ_１＝Ｒ_１、（Ｘ_１＋Ｘ_Ｓ）＝０であるので、これらを（２）式に代入してＹ_Ｓを求めればよい。即ち、
（Ｒ_１＋Ｙ_Ｓ）^２＝Ｒ_１ ^２
Ｙ_Ｓ（Ｙ_Ｓ＋２Ｒ_１）＝０
となる。よって、
Ｙ_Ｓ＝０（Ｙ_Ｓ＝−２Ｒ_１は、不適）・・・（６）
となる。
【００３２】
また、上段側の駆動ローラ６ａの軸心が上側乗降口部Ａと上曲部Ｂとの境界点２９に位置するときは、（２）式においてＸ_１＝０、Ｙ_１＝Ｒ_１であるので、これらを（２）式に代入してＹ_Ｓを求めればよい。即ち、
（Ｒ_１＋Ｙ_Ｓ）^２＝Ｒ_１ ^２−Ｘ_Ｓ ^２
Ｙ_Ｓ ^２＋２Ｒ_１Ｙ_Ｓ＋Ｘ_Ｓ ^２＝０
となる。よって、
Ｙ_Ｓ＝−Ｒ_１＋√（Ｒ_１ ^２−Ｘ_Ｓ ^２）
（Ｙ_Ｓ＝−Ｒ_１−√（Ｒ_１ ^２−Ｘ_Ｓ ^２）は不適）・・・（７）
となる。
【００３３】
従って、（４）式は、上段側の踏段２の駆動ローラ６ａの軸心に対する下段側の踏段２の駆動ローラ６ｂの軸心のｙ方向の相対位置Ｙ_Ｓが、
−Ｒ_１＋√（Ｒ_１ ^２−Ｘ_Ｓ ^２）≦Ｙ_Ｓ＜０
の範囲で適用される。
【００３４】
図４は図３よりも中間傾斜部Ｃ側の区間における駆動ローラ軸５の軸心の移動軌跡を示す説明図である。図において、上段側の踏段２の駆動ローラ６ａの軸心と下段側の踏段２の駆動ローラ６ｂの軸心とは、共に上曲部Ｂに位置し、その座標をそれぞれ（Ｘ_１，Ｘ_２）、（Ｘ_２，Ｘ_２）とする。また、上段側の踏段２の駆動ローラ６ａの軸心に対する下段側の踏段２の駆動ローラ６ｂの軸心の相対位置は、（Ｘ_Ｓ，Ｙ_Ｓ）であるとする。
【００３５】
このときの上曲部Ｂにおける駆動ローラ６ａ，６ｂの軸心の移動軌跡は、
ｙ^２＝Ｒ_１ ^２−ｘ^２
と表される。従って、上段側の駆動ローラ６ａの軸心の座標の関係は、
Ｙ_１ ^２＝Ｒ_１ ^２−Ｘ_１ ^２・・・（８）
Ｙ_１＝√（Ｒ_１ ^２−Ｘ₁ ^２）
（Ｙ_１＝−√（Ｒ_１ ^２−Ｘ₁ ^２）は不適）・・・（８）’
であり、下段側の駆動ローラ６ｂの軸心の座標の関係は、
（Ｙ_１＋Ｙ_Ｓ）^２＝Ｒ_１ ^２−（Ｘ_１＋Ｘ_Ｓ）^２・・・（９）
である。
【００３６】
ここで、（８）式及び（９）式の双方を満たす（Ｘ_１，Ｙ_１）が、上段側の踏段２の駆動ローラ６ａの軸心に対する下段側の踏段２の駆動ローラ６ｂの軸心の相対位置が（Ｘ_Ｓ，Ｙ_Ｓ）のときの上段側の駆動ローラ６ａの軸心の座標であるので、（８）式と（９）式とを連立させて、Ｘ_１を求める。
【００３７】
まず、（９）式を展開する。
Ｙ_１ ^２＋２Ｙ_Ｓ・Ｙ_１＋Ｙ_Ｓ ^２＝Ｒ_１ ^２−Ｘ_１ ^２−２Ｘ_Ｓ・Ｘ_１−Ｘ_Ｓ ^２・・・（９）’
次に、（９）’式に（８）’式を代入する。
Ｙ_１ ^２＋２Ｙ_Ｓ√（Ｒ_１ ^２−Ｘ₁ ^２）＋Ｙ_Ｓ ^２＝Ｙ_１ ^２−２Ｘ_Ｓ・Ｘ_１−Ｘ_Ｓ ^２
２Ｙ_Ｓ√（Ｒ_１ ^２−Ｘ₁ ^２）＝−２Ｘ_Ｓ・Ｘ_１−（Ｘ_Ｓ ^２＋Ｙ_Ｓ）
√（Ｒ_１ ^２−Ｘ₁ ^２）＝−（Ｘ_Ｓ／Ｙ_Ｓ）Ｘ_１−（Ｘ_Ｓ ^２＋Ｙ_Ｓ ^２）／２Ｙ_Ｓ
【００３８】
ここで、ｐ_１＝−Ｘ_Ｓ／Ｙ_Ｓ、ｑ_１＝−（Ｘ_Ｓ ^２＋Ｙ_Ｓ ^２）／２Ｙ_Ｓとおくと、
√（Ｒ_１ ^２−Ｘ₁ ^２）＝ｐ_１Ｘ_１＋ｑ_１
となる。両辺を二乗して変形すると、
（ｐ_１ ^２＋１）Ｘ_１ ^２＋２ｐ_１ｑ_１・Ｘ_１＋（ｑ_１ ^２−Ｒ_１ ^２）＝０・・・（１０）
【００３９】
（１０）式を二次方程式の解の公式でＸ_１について解くと、
Ｘ_１＝[−ｐ_１ｑ_１＋√{(ｐ_１ｑ_１)^２−(ｐ_１ ^２＋１)(ｑ_１ ^２−Ｒ_１ ^２)}]／(ｐ_１ ^２＋１)・・・（１１）
（Ｘ_１＝[−ｐ_１ｑ_１−√{(ｐ_１ｑ_１)^２−(ｐ_１ ^２＋１)(ｑ_１ ^２−Ｒ_１ ^２)}]／(ｐ_１ ^２＋１)は不適）
となる。ただし、ｐ_１＝Ｘ_Ｓ／Ｙ_Ｓ、ｑ_１＝（Ｘ_Ｓ ^２＋Ｙ_Ｓ ^２）／２Ｙ_Ｓ（符号省略可）
【００４０】
そのＹ座標は、（３）式より、
Ｙ_１＝√（Ｒ_１ ^２−Ｘ₁ ^２）
であり、下段側の踏段の駆動ローラ６ｂの軸心の座標は（Ｘ_１＋Ｘ_Ｓ，Ｙ_１＋Ｙ_Ｓ）である。
【００４１】
ただし、この関係は、上段側の駆動ローラ６ａの軸心が境界点２９に位置するときと、下段側の駆動ローラ６ｂの軸心が上曲部Ｂと中間傾斜部Ｃとの境界点３０に位置するときとの間の領域（上段側の駆動ローラ軸５の軸心と下段側の駆動ローラ軸５の軸心との両方が上曲部Ｂに位置している状態）で適用される。上段側の駆動ローラ６ａの軸心が境界点２９に位置する状態は、（８）式を適用できる上曲部Ｂの上側乗降口部Ａ側の限界点である。下段側の駆動ローラ６ｂの軸心が境界点３０に位置する状態は、（９）式を適用できる上曲部Ｂの中間傾斜部Ｃ側の限界点である。
【００４２】
上曲部Ｂと中間傾斜部Ｃとの境界点３０の座標は、（Ｒ_１ｓｉｎα_ｍ，Ｒ_１ｃｏｓα_ｍ）であるので、境界点３０上に下段側の駆動ローラ６ｂの軸心が位置するときは、次の式が成り立つ。
Ｘ_１＝Ｒ_１ｓｉｎα_ｍ−Ｘ_Ｓ・・・（１２）
Ｙ_１＝Ｒ_１ｃｏｓα_ｍ−Ｙ_Ｓ・・・（１３）
【００４３】
（１２）式及び（１３）式を（８）式に代入し、変形する。
（Ｒ_１ｃｏｓα_ｍ−Ｙ_Ｓ）^２＝Ｒ_１ ^２−（Ｒ_１ｓｉｎα_ｍ−Ｘ_Ｓ）^２
Ｒ_１ ^２ｃｏｓ^２α_ｍ−２Ｒ_１ｃｏｓα_ｍ・Ｙ_Ｓ＋Ｙ_Ｓ ^２
＝Ｒ_１ ^２−Ｒ_１ ^２ｓｉｎ^２α_ｍ＋２Ｒ_１ｓｉｎα_ｍ・Ｘ_Ｓ−Ｘ_Ｓ ^２
Ｙ_Ｓ ^２−２Ｒ_１ｃｏｓα_ｍ・Ｙ_Ｓ−（２Ｒ_１ｓｉｎα_ｍ・Ｘ_Ｓ−Ｘ_Ｓ ^２）＝０・・・（１４）
【００４４】
（１４）式を二次方程式の解の公式でＹ_Ｓについて解き、下段側の駆動ローラ６ｂの軸心が境界点３０に位置するときのＹ_Ｓを求める。
Ｙ_Ｓ＝Ｒ_１ｃｏｓα_ｍ−√｛（Ｒ_１ｃｏｓα_ｍ）^２＋（２Ｒ_１ｓｉｎα_ｍ・Ｘ_Ｓ−Ｘ_Ｓ ^２）｝・・・（１５）
（Ｙ_Ｓ＝Ｒ_１ｃｏｓα_ｍ＋√｛（Ｒ_１ｃｏｓα_ｍ）^２＋（２Ｒ_１ｓｉｎα_ｍ・Ｘ_Ｓ−Ｘ_Ｓ ^２）｝は、不適）
【００４５】
上段側の駆動ローラ６ａの軸心が上側乗降口部Ａと上曲部Ｂとの境界点２９に位置するときのＹ_Ｓは、（７）式で既に求めているので、その式を採用すると、（１１）式は、上段側の踏段の駆動ローラ６ａの軸心に対する下段側の踏段の駆動ローラ６ｂの軸心のｙ方向の相対位置Ｙ_Ｓが
Ｒ_１ｃｏｓα_ｍ−√｛（Ｒ_１ｃｏｓα_ｍ）^２＋（２Ｒ_１ｓｉｎα_ｍ・Ｘ_Ｓ−Ｘ_Ｓ ^２）｝≦Ｙ_Ｓ＜−Ｒ_１＋√（Ｒ_１ ^２−Ｘ_Ｓ ^２）
の範囲のときに適用される。
【００４６】
図５は図４よりも中間傾斜部Ｃ側の区間における駆動ローラ軸５の軸心の移動軌跡を示す説明図である。ここで、上段側の踏段２の駆動ローラ６ａの軸心は上曲部Ｂに位置し、その座標は（Ｘ_１，Ｘ_２）、下段側の踏段２の駆動ローラ６ｂの軸心は中間傾斜部Ｃに位置し、その座標は（Ｘ_２，Ｘ_２）、上段側の踏段２の駆動ローラ６ａの軸心に対する下段側の踏段２の駆動ローラ６ｂの軸心の相対位置は（Ｘ_Ｓ，Ｙ_Ｓ）であるとする。
【００４７】
このときの上側乗降口部Ａにおける駆動ローラ６ａの軸心の移動軌跡は、
ｙ^２＝Ｒ_１ ^２−ｘ^２
と表されるので、上段側の駆動ローラ軸の軸心の座標の関係は、
Ｙ_１ ^２＝Ｒ_１ ^２−Ｘ_１ ^２・・・（１６）
である。中間傾斜部Ｂにおける駆動ローラ軸の軸心の移動軌跡の直線は、
ｙ＝ｐ_２ｘ＋ｑ２
で、表されるので、
（Ｙ_１＋Ｙ_Ｓ）＝ｐ_２（Ｘ_１＋Ｘ_Ｓ）＋ｑ_２・・・（１７）
Ｙ_１＝ｐ_２（Ｘ_１＋Ｘ_Ｓ）＋（ｑ_２−Ｙ_Ｓ）・・・（１７）’
となる。
【００４８】
この直線は、上曲部Ｂと中間傾斜部Ｃとの境界点３０の座標（Ｒｓｉｎα_ｍ，Ｒｃｏｓα_ｍ）を通る勾配ｐの直線であり、ここでは、
ｐ_２＝−ｔａｎα_ｍ、ｑ_２＝Ｒ_１（ｃｏｓα_ｍ＋ｓｉｎα_ｍ・ｔａｎα_ｍ）
である。
【００４９】
ここで、（１６）式及び（１７）式の双方を満たす（Ｘ_１，Ｙ_１）が、上段側の踏段２の駆動ローラ６ａの軸心に対する下段側の踏段２の駆動ローラ６ｂの軸心の相対位置が（Ｘ_Ｓ，Ｙ_Ｓ）のときの上段側の駆動ローラ６ａの軸心の座標であるので、（１６）式と（１７）式を連立させて、Ｘ_１を求める。
【００５０】
まず、（１７）’式の両辺を二乗して（１８）式を求める。
Ｙ_１ ^２＝｛ｐ_２（Ｘ_１＋Ｘ_Ｓ）｝^２＋２ｐ_２（Ｘ_１＋Ｘ_Ｓ）（ｑ_２−Ｙ_Ｓ）＋（ｑ_２−Ｙ_Ｓ）^２・・・（１８）
次に、（１６）式を（１８）式に代入して変形する。
Ｒ_１ ^２−Ｘ_１ ^２＝｛ｐ_２（Ｘ_１＋Ｘ_Ｓ）｝^２＋２ｐ_２（Ｘ_１＋Ｘ_Ｓ）（ｑ_２−Ｙ_Ｓ）＋（ｑ_２−Ｙ_Ｓ）^２
（ｐ_２ ^２＋１）Ｘ_１ ^２＋２ｐ_２ｓＸ_１＋（ｓ^２−Ｒ_１ ^２）｝＝０・・・（１９）
ただし、ｓ＝ｐ_２Ｘ_Ｓ＋ｑ_２−Ｙ_Ｓ
【００５１】
（１９）式を二次方程式の解の公式を用いてＸ_１にてついて解く。
Ｘ_１＝［−ｐ_２ｓ−√{(ｐ_２ｓ)^２−(ｐ_６ ^２＋１)(ｓ^２−Ｒ_１ ^２)}］／(ｐ_２ ^２＋１) ・・・（２０）
（Ｘ_１＝［−ｐ_２ｓ＋√{(ｐ_２ｓ)^２−(ｐ_６ ^２＋１)(ｓ^２−Ｒ_１ ^２)}］／(ｐ_２ ^２＋１)は、不適）
ただし、ｐ_２＝−ｔａｎα_ｍ、ｑ_２＝Ｒ_１（ｃｏｓα_ｍ＋ｓｉｎα_ｍ・ｔａｎα_ｍ）、ｓ＝ｐ_２Ｘ_Ｓ＋ｑ_２−Ｙ_Ｓ
である。
【００５２】
そのＹ座標は、（１６）式より、
Ｙ_１＝√（Ｒ_１ ^２−Ｘ₁ ^２）
（Ｙ_１＝−√（Ｒ_１ ^２−Ｘ₁ ^２）は、不適）
である。また、下段側の踏段２の駆動ローラ６ｂの軸心の座標は（Ｘ_１＋Ｘ_Ｓ，Ｙ_１＋Ｙ_Ｓ）である。
【００５３】
ただし、この関係は、下段側の駆動ローラ６ｂの軸心が上曲部Ｂと中間傾斜部Ｃとの境界点３０に位置するときと、上段側の駆動ローラ６ａの軸心が上曲部Ｂと中間傾斜部Ｃとの境界点３０に位置するときとの間の領域（上段側の駆動ローラ軸５の軸心が上曲部Ｂに、下段側の駆動ローラ軸５の軸心が中間傾斜部Ｃに位置している状態）で適用される。下段側の駆動ローラ６ｂの軸心が境界点３０に位置する状態は、下段側の駆動ローラ６ｂの軸心が（１６）式を適用できる上曲部の中間傾斜部Ｃ側の限界点である。上段側の駆動ローラ６ａの軸心が境界点３０に位置する状態は、（１７）式を適用できる中間傾斜部Ｃの上曲部Ｂ側の限界点である。
【００５４】
上曲部Ｂと中間傾斜部Ｃとの境界点３０の座標は、（Ｒ_１ｓｉｎα_ｍ，Ｒ_１ｃｏｓα_ｍ）であるので、境界点３０上に上段側の駆動ローラ６ａの軸心が位置するときは次の式が成り立つ。
Ｘ_１＝Ｒ_１ｓｉｎα_ｍ・・・（２１）
Ｙ_１＝Ｒ_１ｃｏｓα_ｍ・・・（２２）
（２１）式及び（２２）式を（１７）式に代入する。
（Ｒ_１ｃｏｓα_ｍ＋Ｙ_Ｓ）＝ｐ_２（Ｒ_１ｓｉｎα_ｍ＋Ｘ_Ｓ）＋ｑ_２
ｐ_２＝−ｔａｎα_ｍ、ｑ_２＝Ｒ_１（ｃｏｓα_ｍ＋ｓｉｎα_ｍ・ｔａｎα_ｍ）
であるので、
（Ｒ_１ｃｏｓα_ｍ＋Ｙ_Ｓ）＝
−ｔａｎα_ｍ（Ｒ_１ｓｉｎα_ｍ＋Ｘ_Ｓ）＋Ｒ_１（ｃｏｓα_ｍ＋ｓｉｎα_ｍ・ｔａｎα_ｍ）
Ｙ_Ｓ＝−Ｘ_Ｓ．ｔａｎα_ｍ
【００５５】
下段側の駆動ローラ６ｂの軸心が上曲部Ｂと中間傾斜部Ｃの境界点３０に位置するときのＹ_Ｓは、（１５）式で既に求めているので、その式を採用すると、（２０）式は、上段側の踏段２の駆動ローラ６ａの軸心に対する下段側の踏段２の駆動ローラ６ｂの軸心のｙ方向の相対位置Ｙ_Ｓが、
−Ｘ_Ｓ．ｔａｎα_ｍ≦Ｙ_Ｓ
＜Ｒ_１ｃｏｓα_ｍ−√{（Ｒ_１ｃｏｓα_ｍ）^２＋（２Ｒ_１ｓｉｎα_ｍ・Ｘ_Ｓ−Ｘ_Ｓ ^２）}
の範囲のときに適用される。
【００５６】
図６は図１の下側乗降口部Ｅ及び下曲部Ｄ付近の駆動ローラ軸５の軸心の移動軌跡を示す説明図である。図において、下曲部Ｄにおける駆動ローラ軸５の軸心の移動軌跡５ａの曲率半径はＲ₂である。また、座標の原点は、駆動ローラ軸５の軸心の移動軌跡５ａの下側乗降口部Ｅと下曲部Ｄとの境界点３１から垂直方向（ｙ方向）にＲ₂だけ離れた点にとっている。
【００５７】
ここで、上段側の踏段２の駆動ローラ６ａの軸心は、下曲部Ｄに位置し、その座標は（Ｘ_１，Ｘ_２）であるとする。また、下段側の踏段２の駆動ローラ６ｂの軸心は、下側乗降口部Ｅに位置し、その座標は（Ｘ_２，Ｘ_２）であるとする。さらに、上段側の踏段２の駆動ローラ６ａの軸心に対する下段側の踏段２の駆動ローラ６ｂの軸心の相対位置は（Ｘ_Ｓ，Ｙ_Ｓ）であるとする。
【００５８】
このときの下曲部Ｄにおける駆動ローラ６ａの軸心の移動軌跡は、
ｙ^２＝Ｒ_２ ^２−ｘ^２
と表される。このため、上段側の駆動ローラ軸５の軸心の座標の関係は、
Ｙ_１ ^２＝Ｒ_２ ^２−Ｘ_１ ^２・・・（２３）
である。また、下側乗降口部Ｅでは、
ｙ＝−Ｒ_２
の関係が成り立ち、下段側の踏段２の駆動ローラ６ｂの軸心の座標は、
（Ｙ_１＋Ｙ_Ｓ）＝−Ｒ_２・・・（２４）
Ｙ_１＝−Ｒ_２−Ｙ_Ｓ・・・（２４）'
である。
【００５９】
ここで、（２３）式及び（２４）式の双方を満たす（Ｘ_１，Ｙ_１）が、上段側の踏段２の駆動ローラ６ａの軸心に対する下段側の踏段２の駆動ローラ６ｂの軸心の相対位置が（Ｘ_Ｓ，Ｙ_Ｓ）のときの上段側の駆動ローラ６ａの軸心の座標であるので、（２３）式及び（２４）式を連立させて、Ｘ_１を求める。
【００６０】
（２３）式に（２４）'式を代入して変形すると次の（２５）式が求められる。
Ｘ_１ ^２＝２Ｒ_２Ｙ_Ｓ−Ｙ_Ｓ ^２・・・（２５）
よって、
Ｘ_１＝−√（２Ｒ_２・Ｙ_Ｓ−Ｙ_Ｓ ^２）・・・（２６）
（Ｘ_１＝＋√（２Ｒ_２・Ｙ_Ｓ−Ｙ_Ｓ ^２）は、不適）
そのＹ座標は、（２３）式より、
Ｙ_１＝−√（Ｒ_２ ^２−Ｘ₁ ^２）
（Ｙ_１＝√（Ｒ_２ ^２−Ｘ₁ ^２）は、不適）
である。従って、下段側の踏段２の駆動ローラ６ｂの軸心の座標は、（Ｘ_１＋Ｘ_Ｓ，Ｙ_１＋Ｙ_Ｓ）である。
【００６１】
ただし、この関係は、上段側の駆動ローラ６ａの軸心が下側乗降口部Ｅと下曲部Ｄとの境界点３１に位置するときと、下段側の駆動ローラ６ｂの軸心が境界点３１に位置するときのと間の領域（上段側の駆動ローラ軸５の軸心が下曲部Ｄに、下段側の駆動ローラ軸５の軸心が下側乗降口部Ｅに位置している状態）で適用される。上段側の駆動ローラ６ａの軸心が境界点３１に位置する状態は、（２３）式を適用できる下曲部Ｄの下側乗降口部Ｅ側の限界点である。下段側の駆動ローラ６ｂの軸心が境界点３１に位置する状態は、（２４）式を適用できる下側乗降口部Ｅの下曲部Ｄ側の限界点である。
【００６２】
上段側の駆動ローラ６ａの軸心が下側乗降口部Ｅと下曲部Ｄとの境界点３１に位置するときは、Ｙ_１＝−Ｒであるので、これを（２４）式に代入してＹ_Ｓを求めると、
Ｙ_Ｓ＝０・・・（２７）
となる。また下段側の駆動ローラ６ｂの軸心が下側乗降口部Ｅと下曲部Ｄとの境界点３１に位置するときは、
Ｘ_１＋Ｘ_Ｓ＝０であり、Ｘ_１＝−Ｘ_Ｓ・・・（２８）
Ｙ_１＋Ｙ_Ｓ＝−Ｒ_２、Ｙ_１＝−（Ｒ_２＋Ｙ_Ｓ）・・・（２９）
さらに（２８）式と（２９）式を（２３）式に代入すると
（Ｒ_２＋Ｙ_Ｓ）^２＝Ｒ_２ ^２−Ｘ_Ｓ ^２
Ｙ_Ｓ ^２＋２Ｒ_２・Ｙ_Ｓ−Ｘ_Ｓ ^２＝０・・・（３０）
【００６３】
（３０）式を二次方程式の解の公式を用いてＹ_Ｓにてついて解くと
Ｙ_Ｓ＝−Ｒ_２＋√（Ｒ_２ ^２−Ｘ_Ｓ ^２）・・・（３１）
（Ｙ_Ｓ＝Ｒ_２−√（Ｒ_２ ^２−Ｘ_Ｓ ^２）は、不適）
となる。従って、（２６）式は、上段側の踏段２の駆動ローラ６ａの軸心に対する下段側の踏段２の駆動ローラ６ｂの軸心のｙ方向の相対位置Ｙ_Ｓが（２７）式と（３１）式の間の
−Ｒ_２＋√（Ｒ_２ ^２−Ｘ_Ｓ ^２）≦Ｙ_Ｓ＜０
の範囲で適用される。
【００６４】
図７は図６よりも中間傾斜部Ｃ側の区間における駆動ローラ軸５の軸心の移動軌跡を示す説明図である。図において、上段側の踏段２の駆動ローラ６ａの軸心と下段側の踏段２の駆動ローラ６ｂの軸心とは、共に下曲部Ｄに位置し、その座標はそれぞれ（Ｘ_１，Ｘ_２）、（Ｘ_２，Ｘ_２）であるとする。また、上段側の踏段２の駆動ローラ６ａの軸心に対する下段側の踏段２の駆動ローラ６ｂの軸心の相対位置は（Ｘ_Ｓ，Ｙ_Ｓ）であるとする。
【００６５】
このときの下曲部Ｄにおける駆動ローラ６ａ，６ｂの軸心の移動軌跡は、
ｙ^２＝Ｒ_２ ^２−ｘ^２
と表される。従って、上段側の駆動ローラ６ａの軸心の座標の関係は、
Ｙ_１ ^２＝Ｒ_２ ^２−Ｘ_１ ^２・・・（３２）
Ｙ_１＝−√（Ｒ_２ ^２−Ｘ_１ ^２）
（Ｙ_１＝√（Ｒ_２ ^２−Ｘ_１ ^２）は不適）・・・（３２）'
であり、下段側の駆動ローラ６ｂの軸心の座標の関係は、
（Ｙ_１＋Ｙ_Ｓ）^２＝Ｒ_２ ^２−（Ｘ_１＋Ｘ_Ｓ）^２・・・（３３）
である。
【００６６】
ここで、（３２）式及び（３３）式の双方を満たす（Ｘ_１，Ｙ_１）が、上段側の踏段の駆動ローラ６ａの軸心に対する下段側の踏段の駆動ローラ６ｂの軸心の相対位置が（Ｘ_Ｓ，Ｙ_Ｓ）のときの上段側の駆動ローラ６ａの軸心の座標であるので、（３２）式及び（３３）式を連立させて、Ｘ_１を求める。
【００６７】
まず、（３３）式を展開する。
Ｙ_１ ^２＋２Ｙ_Ｓ・Ｙ_１＋Ｙ_Ｓ ^２＝Ｒ_２ ^２−Ｘ_１ ^２−２Ｘ_Ｓ・Ｘ_１−Ｘ_Ｓ ^２・・・（３３）'
次に、（３３）'式'に（３２）'式を代入する。
Ｙ_１ ^２−２Ｙ_Ｓ√（Ｒ_２ ^２−Ｘ_１ ^２）＋Ｙ_Ｓ ^２＝Ｙ_１ ^２−２Ｘ_Ｓ・Ｘ_１−Ｘ_Ｓ ^２
−２Ｙ_Ｓ√（Ｒ_２ ^２−Ｘ_１ ^２）＝−２Ｘ_Ｓ・Ｘ_１−（Ｘ_Ｓ ^２＋Ｙ_Ｓ）
√（Ｒ_２ ^２−Ｘ_１ ^２）＝（Ｘ_Ｓ／Ｙ_Ｓ）Ｘ_１＋（Ｘ_Ｓ ^２＋Ｙ_Ｓ ^２）／２Ｙ_Ｓ
【００６８】
ここで、ｐ_３＝Ｘ_Ｓ／Ｙ_Ｓ、ｑ₁＝（Ｘ_Ｓ ^２＋Ｙ_Ｓ ^２）／２Ｙ_Ｓとおくと、
√（Ｒ_２ ^２−Ｘ_１ ^２）＝ｐ₁Ｘ_１＋ｑ₁
となる。両辺を二乗して変形すると、
（ｐ₁ ^２＋１）Ｘ_１ ^２＋２ｐ₁ｑ₁．Ｘ_１＋（ｑ₁ ^２−Ｒ₂ ^２）＝０・・・（３４）
となる。（１０）式を二次方程式の解の公式でＸ_１について解く。
Ｘ_１＝［−ｐ_３ｑ_３−√{(ｐ_３ｑ_３)^２−(ｐ_３ ^２＋１)(ｑ_３ ^２−Ｒ_２ ^２)}］／(ｐ_３ ^２＋１)・・・（３５）
（Ｘ_１＝［−ｐ_３ｑ_３＋√{(ｐ_３ｑ_３)^２−(ｐ_３ ^２＋１)(ｑ_３ ^２−Ｒ_２ ^２)}］／(ｐ_３ ^２＋１)は不適）
ただしｐ_３＝Ｘ_Ｓ／Ｙ_Ｓ、ｑ_３＝（Ｘ_Ｓ ^２＋Ｙ_Ｓ ^２）／２Ｙ_Ｓ
そのＹ座標は（３２）'式より
Ｙ_１＝−√（Ｒ_２ ^２−Ｘ₁ ^２）
（Ｙ_１＝√（Ｒ_２ ^２−Ｘ₁ ^２）は、不適）
であり、下段側の踏段の駆動ローラ６ｂの軸心の座標は（Ｘ_１＋Ｘ_Ｓ，Ｙ_１＋Ｙ_Ｓ）である。
【００６９】
ただし、この関係は、下段側の駆動ローラ６ｂの軸心が下側乗降口部Ｅと下曲部Ｄとの境界点３１に位置するときと、上段側の駆動ローラ６ａの軸心が下曲部Ｄと中間傾斜部Ｃとの境界点３２に位置するときの間の領域（上段側の駆動ローラ軸５の軸心と下段側の駆動ローラ軸５の軸心とも下曲部Ｄに位置している状態）で適用される。下段側の駆動ローラ６ｂの軸心が境界点３１に位置する状態は、（３２）式を適用できる下曲部Ｄの下側乗降口部Ｅ側の限界点である。上段側の駆動ローラ６ａの軸心が境界点３２に位置する状態は、（３３）式の適用できる下曲部Ｄの中間傾斜部Ｃ側の限界点である。
【００７０】
下曲部Ｄと中間傾斜部Ｃとの境界点３２の座標は、（−Ｒ_２ｓｉｎα_ｍ，−Ｒ_２ｃｏｓα_ｍ）であるので、境界点３２上に上段側の駆動ローラ６ａの軸心が位置するときは、次の式が成り立つ。
Ｘ_１＝−Ｒ_２ｓｉｎα_ｍ・・・（３６）
Ｙ_１＝−Ｒ_２ｃｏｓα_ｍ・・・（３７）
（３６）式、（３７）式を（３２）式に代入し、変形する。
（−Ｒ_２ｃｏｓα_ｍ＋Ｙ_Ｓ）^２＝Ｒ_２ ^２−（−Ｒ_２ｓｉｎα_ｍ＋Ｘ_Ｓ）^２
Ｒ_２ ^２ｃｏｓ^２α_ｍ−２Ｒ_２ｃｏｓα_ｍ．Ｙ_Ｓ＋Ｙ_Ｓ ^２＝Ｒ_２ ^２−Ｒ_２ ^２ｓｉｎ^２α_ｍ＋２Ｒ_２ｓｉｎα_ｍ．Ｘ_Ｓ−Ｘ_Ｓ ^２
Ｙ_Ｓ ^２−２Ｒ_２ｃｏｓα_ｍ．Ｙ_Ｓ−（２Ｒ_２ｓｉｎα_ｍ．Ｘ_Ｓ−Ｘ_Ｓ ^２）＝０・・・（３８）
【００７１】
（３８）式を二次方程式の解の公式でＹ_Ｓについて解き、上段側の駆動ローラ６ａの軸心が下曲部Ｄと中間傾斜部Ｃとの境界点３２に位置するときのＹ_Ｓを求める。
Ｙ_Ｓ＝Ｒ_２ｃｏｓα_ｍ−√{（Ｒ_２ｃｏｓα_ｍ）^２＋（２Ｒ_２ｓｉｎα_ｍ・Ｘ_Ｓ−Ｘ_Ｓ ^２）}・・・（３９）
（Ｙ_Ｓ＝Ｒ_２ｃｏｓα_ｍ＋√{（Ｒ_２ｃｏｓα_ｍ）^２＋（２Ｒ_２ｓｉｎα_ｍ・Ｘ_Ｓ−Ｘ_Ｓ ^２）}は、不適）
【００７２】
下段側の駆動ローラ６ｂの軸心が下側乗降口部Ｅと下曲部Ｄとの境界点３１に位置するときのＹ_Ｓは、（３１）式で既に求めているので、その式を採用すると、（３５）式は上段側の踏段の駆動ローラ６ａの軸心に対する下段側の踏段の駆動ローラ６ｂの軸心のｙ方向の相対位置Ｙ_Ｓが
Ｒ_２ｃｏｓα_ｍ−√{（Ｒ_２ｃｏｓα_ｍ）^２＋（２Ｒ_２ｓｉｎα_ｍ・Ｘ_Ｓ−Ｘ_Ｓ ^２）}≦Ｙ_Ｓ＜−Ｒ_２＋√（Ｒ_２ ^２−Ｘ_Ｓ ^２）
の範囲で適用される。
【００７３】
図８は図７よりも中間傾斜部Ｃ側の区間における駆動ローラ軸５の軸心の移動軌跡を示す説明図である。図において、上段側の踏段２の駆動ローラ６ａの軸心は、中間傾斜部Ｃに位置し、その座標は（Ｘ_１，Ｘ_２）であるとする。また、下段側の踏段２の駆動ローラ６ｂの軸心は、下曲部Ｄに位置し、その座標は（Ｘ_２，Ｘ_２）であるとする。さらに、上段側の踏段２の駆動ローラ６ａの軸心に対する下段側の踏段２の駆動ローラ６ｂの軸心の相対位置は、（Ｘ_Ｓ，Ｙ_Ｓ）であるとする。
【００７４】
中間傾斜部Ｃにおける駆動ローラ軸の軸心の移動軌跡の直線は、
ｙ＝ｐ_４ｘ＋ｑ_４
で表される。従って、中間傾斜部Ｃに位置する上段側駆動ローラ６ａの軸心の座標は、
Ｙ_１＝ｐ_４Ｘ_１＋ｑ_４・・・（４０）
この直線は、下曲部Ｄと中間傾斜部Ｃとの境界点３２の座標（−Ｒ_２ｓｉｎα_ｍ，−Ｒ_２ｃｏｓα_ｍ）を通る勾配ｐ_４の直線であり、ここでは、
ｐ_４＝−ｔａｎα_ｍ、ｑ_２＝−Ｒ_２（ｃｏｓα_ｍ−ｓｉｎα_ｍ・ｔａｎα_ｍ）
である。
【００７５】
さらに、下側曲部Ｄにおける下段側駆動ローラ６ｂの軸心の移動軌跡は、
ｙ^２＝Ｒ_２ ^２−ｘ^２
と表される。従って、下段側の駆動ローラ６ｂの軸心の座標の関係は、
（Ｙ_１＋Ｙ_Ｓ）^２＝Ｒ_２ ^２−（Ｘ_１＋Ｘ_Ｓ）^２・・・（４１）
である。（４１）式を展開して（４０）式を代入して変形すると、
（ｐ_４ ^２＋１）Ｘ_１ ^２＋２（ｐ_４ｑ_４＋ｐ_４Ｙ_Ｓ＋Ｘ_Ｓ）Ｘ_１＋｛（ｑ_４＋Ｙ_Ｓ）^２−Ｒ_２ ^２＋Ｘ_Ｓ ^２｝＝０・・・（４２）
【００７６】
（４２）式を二次方程式の解の公式を用いてＸ_１について解く。
Ｘ_１＝{−(ｐ_４ｑ_４＋ｐ_４Ｙ_Ｓ＋Ｘ_ｓ)＋√Ａ_１}／(ｐ_４ ^２＋１)
Ａ_１＝(ｐ_４ｑ_４＋ｐ_４Ｙ_Ｓ＋Ｘ_Ｓ)^２−(ｐ_４ ^２＋１){(ｑ_４＋Ｙ_ｓ)^２−Ｒ_２ ^２＋Ｘ_Ｓ ^２}・・・（４３）
（Ｘ_１＝{−(ｐ_４ｑ_４＋ｐ_４Ｙ_Ｓ＋Ｘ_ｓ)−√Ａ_１}／(ｐ_４ ^２＋１)は、不適）
ただし、ｐ_４＝−ｔａｎα_ｍ、ｑ_２＝−Ｒ_２（ｃｏｓα_ｍ＋ｓｉｎα_ｍ・ｔａｎα_ｍ）である。
そのときのＹ座標は（４０）式より
Ｙ_１＝ｐ_４Ｘ_１＋ｑ_４
であり、下段側の踏段の駆動ローラ６ｂの軸心の座標は（Ｘ_１＋Ｘ_Ｓ，Ｙ_１＋Ｙ_Ｓ）である。
【００７７】
ただし、この関係は、上段側の駆動ローラ６ａの軸心が下曲部Ｄと中間傾斜部Ｃとの境界点３２に位置するときと、下段側の駆動ローラ６ｂの軸心が境界点３２に位置するときとの間の領域（上段側の駆動ローラ軸５の軸心が中間傾斜部Ｃに、下段側の駆動ローラ軸５の軸心が下曲部Ｄに位置している状態）で適用される。上段側の駆動ローラ６ａの軸心が境界点３２に位置する状態は、（４０）式を適用できる中間傾斜部Ｃの下曲部Ｄ側の限界点である。下段側の駆動ローラ６ｂの軸心が境界点３２に位置する状態は、（４１）式を適用できる下曲部Ｄの中間傾斜部Ｃ側の限界点である。
【００７８】
下曲部Ｄと中間傾斜部Ｃとの境界点３２の座標は（−Ｒ_２ｓｉｎα_ｍ，−Ｒ_２ｃｏｓα_ｍ）であるので、境界点３２上に下段側の駆動ローラ６ａの軸心が位置するときは次の式が成り立つ。
Ｘ_１＋Ｘ_Ｓ＝−Ｒ_２ｓｉｎα_ｍより、Ｘ_１＝−Ｒ_２ｓｉｎα_ｍ−Ｘ_Ｓ・・・（４４）
Ｙ_１＋Ｙ_Ｓ＝−Ｒ_２ｃｏｓα_ｍより、Ｙ_１＝−Ｒ_２ｃｏｓα_ｍ−Ｙ_Ｓ・・・（４５）
（４４）式と（４５）式を（４０）式に代入して変形すると
−Ｒ_２ｃｏｓα_ｍ−Ｙ_Ｓ＝ｐ_４（−Ｒ_２ｓｉｎα_ｍ−Ｘ_Ｓ）＋ｑ_４・・・（４６）
【００７９】
ここで、ｐ_４＝−ｔａｎα_ｍ、ｑ_２＝−Ｒ_２（ｃｏｓα_ｍ＋ｓｉｎα_ｍ・ｔａｎα_ｍ）であるから、
−Ｒ_２ｃｏｓα_ｍ−Ｙ_Ｓ＝Ｒ_２ｓｉｎα_ｍ．ｔａｎα_ｍ＋Ｘ_Ｓｔａｎα_ｍ−Ｒ_２ｃｏｓα_ｍ−Ｒ_２ｓｉｎα_ｍ・ｔａｎα_ｍ
Ｙ_Ｓ＝−Ｘ_Ｓｔａｎα_ｍ
となる。
【００８０】
下段側の駆動ローラ６ｂの軸心が下曲部Ｄと中間傾斜部Ｃとの境界点３２に位置するときのＹ_Ｓは、（３９）式で既に求めているので、その式を採用すると、（４３）式は上段側の踏段２の駆動ローラ６ａの軸心に対する下段側の踏段２の駆動ローラ６ｂの軸心のｙ方向の相対位置Ｙ_Ｓが、
−Ｘ_Ｓｔａｎα_ｍ≦Ｙ_Ｓ＜Ｒ_２ｃｏｓα_ｍ−√{（Ｒ_２ｃｏｓα_ｍ）^２＋（２Ｒ_２ｓｉｎα_ｍ・Ｘ_Ｓ−Ｘ_Ｓ ^２）}
の範囲で適用される。
【００８１】
以上の方法により、踏段２の段差が変化する上曲部Ｂと下曲部Ｄとにおいて、隣接する駆動ローラ軸５の軸心の相対座標より、上段側の駆動ローラ６ａの軸心座標と下段側の駆動ローラ６ｂの軸心座標とを求めることができる。
【００８２】
次に、図９は図１の傾斜部高速エスカレーターにおける駆動ローラ軸の軸心の位置、リンク連結点の位置、及び補助ローラの軸心の位置の関係を示す説明図である。ここでは、上記の手順によって求められた隣接する駆動ローラ軸５の軸心Ｇ，Ｆの位置から、リンク連結点Ｍ（軸２８）の位置を求める手順を説明する。
【００８３】
上段側の駆動ローラ軸５（駆動ローラ６ａ）の軸心Ｇの座標を（Ｘ_Ｇ，Ｙ_Ｇ）と下段側の駆動ローラ軸５（駆動ローラ６ｂ）の軸心Ｆの座標を（Ｘ_Ｆ，Ｙ_Ｆ）とすると、それらの軸心間距離Ｗは、
Ｗ＝√{（Ｘ_Ｇ−Ｘ_Ｆ）^２＋（Ｙ_Ｇ−Ｙ_Ｆ）^２}
である。また、その２つの軸心を結んだ線分ＦＧと水平線のなす角度βは、
β＝ｔａｎ^―１{（Ｙ_Ｆ−Ｙ_Ｇ）／（Ｘ_Ｆ−Ｘ_Ｇ）}
である。
【００８４】
ここで、上段側の駆動ローラ軸５の軸心Ｇからリンク連結点Ｍまでの線分ＧＭの距離をＬ_１、下段側の駆動ローラ軸５の軸心Ｆからリンク連結点Ｍまでの線分ＦＭの長さをＬ_２とすると、線分ＧＦと線分ＧＭとのなす角度γは、
γ＝ｃｏｓ^―１{(Ｌ_１ ^２−Ｌ_２ ^２＋Ｗ^２)／２Ｌ_１Ｗ}・・・第二余弦定理
である。線分ＦＭの水平線に対する角度は、β−γであるから、リンク連結点Ｍの座標（Ｘ_Ｍ，Ｙ_Ｍ）は、
Ｘ_Ｍ＝Ｘ_Ｆ＋Ｌ_１ｃｏｓ｛β−γ｝
Ｙ_Ｍ＝Ｙ_Ｆ＋Ｌ_１ｓｉｎ｛β−γ｝
として求めることができ、駆動ローラ軸５の軸心の相対位置とリンク連結点の位置との関係を得ることができる。
【００８５】
また、リンク連結点Ｍの座標（Ｘ_Ｍ，Ｙ_Ｍ）を駆動ローラ軸５の軸心の相対座標の移動軌跡に沿って逐次計算すれば、リンク連結点Ｍの移動軌跡を求めることができる。さらに、リンク連結点Ｍの移動軌跡から、補助ローラ２７の軸心Ｎの移動軌跡も求めることができる。そして、求めた補助ローラ２７の軸心Ｎの移動軌跡を補助ローラ２７の半径分オフセットした形状を、補助レール２３の形状とすることができる。
【００８６】
また、ライザー４の形状を隣接する駆動ローラ軸５の軸心の移動軌跡に略一致させておけば、隣接する踏段２の段差が変化する過程で、隣接する踏段２のライザー４に踏板３が干渉したり、ライザー４と踏板３との間に隙間が生じたりするのを防止することができる。即ち、駆動ローラ軸５の軌跡とリンク連結点の軌跡とを別々に設定することも可能ではあるが、その場合、干渉や隙間が発生してしまう。これに対し、駆動ローラ軸５の軌跡とリンク連結点の軌跡とに上記のような関係を持たせることで、干渉や隙間の発生を防止できる。
【００８７】
次に、補助ローラ２７の軸心の位置の設定方法について説明する。図９において、補助ローラ２７の軸心Ｎの座標を（Ｘ_Ｎ，Ｙ_Ｎ）とする。また、軸心Ｎからリンク連結点Ｍまでの線分ＭＮの長さをＬ_３とする。さらに、線分ＭＮと長さＬ_１の線分ＧＭとのなす角度をθとする。このとき、上段側の駆動ローラ軸５の軸心Ｇの座標と補助ローラ２７の軸心Ｎとを結んだ線分ＧＮの長さＶは、
Ｖ_２ ^２＝Ｌ_１ ^２＋Ｌ_３ ^２−２Ｌ_１Ｌ_３ｃｏｓθ・・・第二余弦定理
から、
Ｖ＝√（Ｌ_１ ^２＋Ｌ_３ ^２−２Ｌ_１Ｌ_３ｃｏｓθ）
となる。また、θは、
Ｖ／ｓｉｎθ＝Ｌ_３／ｓｉｎδ・・・正弦定理
から、
δ＝ｓｉｎ^―１（Ｌ_３ｓｉｎθ／Ｖ）
となる。
【００８８】
ここで、線分ＧＮの水平線に対する角度は、β−γ−δである。従って、補助ローラ２７の軸心Ｎの座標は、
Ｘ_Ｎ＝Ｘ_１＋Ｖｃｏｓ｛β−γ−δ｝
Ｙ_Ｎ＝Ｙ_１＋Ｌ_１ｓｉｎ｛β−γ−δ｝
として求めることができる。
【００８９】
このような軸心Ｎの座標（Ｘ_Ｎ，Ｙ_Ｎ）を駆動ローラ軸５の軸心の相対座標の移動軌跡に沿って逐次計算して求めれば、補助ローラ２７の軸心Ｎの移動軌跡を求めることができる。そして、補助ローラ２７の軸心の移動軌跡を駆動ローラ２７の半径分オフセットすることにより、補助レール２３の形状を求めることができる。
【００９０】
実施の形態２．
なお、実施の形態１では、第１及び第２のリンク２５，２６を有するリンク機構２４を用いたが、例えば図１０に示すようなパンタグラフ式４連リンク機構を構成するリンク機構４１を用いてもよい。図１０において、リンク機構４１は、第１ないし第５のリンク４２〜４６を有している。
【００９１】
第１のリンク４２の一端部は、駆動ローラ軸５に回動自在に連結されている。第１のリンク４２の他端部は、第３のリンク４４の中間部に軸４７を介して回動自在に連結されている。第２のリンク４３の一端部は、隣接する踏段２の駆動ローラ軸５に回動自在に連結されている。第２のリンク４３の他端部は、第３のリンク４４の中間部に軸４７を介して回動自在に連結されている。
【００９２】
第１のリンク４２の中間部には、第４のリンク４５の一端部が回動自在に連結されている。第２のリンク４３の中間部には、第５のリンク４６の一端部が回動自在に連結されている。第４及び第５のリンク４５，４６の他端部は、摺動軸４８を介して第３のリンク４４の一端部に連結されている。
【００９３】
第３のリンク４４の一端部には、第３のリンク４４の長手方向への摺動軸４８の摺動を案内する案内溝４４ａが設けられている。第３のリンク４４の他端部には、回転自在の補助ローラ２７が設けられている。
【００９４】
このようなリンク機構４２を用いる場合でも、実施の形態１と同様に、上段側の駆動ローラ６ａの軸心及び下段側の駆動ローラ６ｂの軸心の相対位置から、リンク連結点（軸４７）の位置を求め、リンク連結点の移動軌跡を求めることができる。また、リンク連結点の移動軌跡から、補助ローラ２７の軸心の移動軌跡も求めることができる。さらに、ライザー４の形状を隣接する駆動ローラ軸５の軸心の移動軌跡に略一致させておけば、隣接する踏段２の段差が変化する過程で、隣接する踏段２のライザー４に踏板３が干渉したり、ライザー４と踏板３との間に隙間が生じたりするのを防止することができる。
【００９５】
なお、実施の形態１、２では、隣接する駆動ローラ軸５の軸心の相対位置の移動軌跡にライザー４の形状を略一致させるようにしたが、まずライザー４の形状を決定した後に、隣接する駆動ローラ軸５の軸心の相対位置の移動軌跡をそれに合わせるように決定する手順としてもよい。
【００９６】
【発明の効果】
以上説明したように、この発明の傾斜部高速エスカレーターによれば、隣接する駆動ローラ軸心の相対位置の移動軌跡からリンク連結点の位置を求め、補助ローラレールの形状を設定することができ、ライザー形状を駆動ローラ軸心の相対位置の移動軌跡に略一致させておけば、隣接する踏段のライザーに踏板が干渉したり、ライザーと踏板との間に隙間が生じたりすることのない傾斜部高速エスカレーターを構成することができる。
【図面の簡単な説明】
【図１】この発明の実施の形態１による傾斜部高速エスカレーターを示す側面図である。
【図２】図１の上側反転部付近を拡大して示す側面図である。
【図３】図１の上側乗降口部及び上曲部付近の駆動ローラ軸の軸心の移動軌跡を示す説明図である。
【図４】図３よりも中間傾斜部側の区間における駆動ローラ軸の軸心の移動軌跡を示す説明図である。
【図５】図４よりも中間傾斜部側の区間における駆動ローラ軸の軸心の移動軌跡を示す説明図である。
【図６】図１の下側乗降口部及び下曲部付近の駆動ローラ軸の軸心の移動軌跡を示す説明図である。
【図７】図６よりも中間傾斜部側の区間における駆動ローラ軸の軸心の移動軌跡を示す説明図である。
【図８】図７よりも中間傾斜部側の区間における駆動ローラ軸の軸心の移動軌跡を示す説明図である。
【図９】図１の傾斜部高速エスカレーターにおける駆動ローラ軸の軸心の位置、リンク連結点の位置、及び補助ローラの軸心の位置の関係を示す説明図である。
【図１０】この発明の実施の形態２による傾斜部高速エスカレーターの要部を示す側面図である。
【図１１】従来の傾斜部高速エスカレーターの一例の要部を示す側面図である。
【符号の説明】
１主枠、２踏段、５駆動ローラ軸、６駆動ローラ、２１駆動レール、２３補助レール、２４リンク機構、２５第１のリンク、２６第２のリンク、２７補助ローラ。[0001]
BACKGROUND OF THE INVENTION
The present invention relates to an inclined portion high-speed escalator in which a moving speed of a step in an intermediate inclined portion is faster than a moving speed of a step in an upper entrance / exit portion and a lower entrance / exit portion.
[0002]
[Prior art]
FIG. 11 is a side view showing a main part of a conventional inclined portion high-speed escalator disclosed in, for example, Japanese Patent Laid-Open No. 51-116586. In the figure, a main frame 1 is provided with a plurality of steps 2 connected endlessly and circulated. Each step 2 includes a step plate 3, a riser 4 that is bent at one end on the lower side of the step plate 3, a drive roller shaft 5 that extends in the width direction of the step plate 3, and a pair of drive rollers that can rotate about the drive roller shaft 5. 6, a follower roller shaft 7 extending in parallel to the drive roller shaft 5, and a pair of follower rollers 8 rotatable about the follower roller shaft 7.
[0003]
The drive roller shafts 5 of the steps 2 adjacent to each other are connected to each other by a pair of link mechanisms 9. Each link mechanism 9 is provided with an auxiliary roller 10.
[0004]
In the main frame 1, a pair of drive rails 11 for forming a circulation path for the steps 2 and guiding the drive rollers 6, a pair of follower rails 12 for guiding the follower rollers 7 and controlling the posture of the steps 2, and auxiliary rollers A pair of auxiliary rails 13 are provided for guiding 10 and changing the interval between adjacent steps 2.
[0005]
In such a conventional inclined high-speed escalator, when the auxiliary roller 10 is displaced with respect to the drive roller shaft 5 according to the shape of the auxiliary rail 13, the link mechanism 9 is transformed so as to bend and extend, and the adjacent drive The interval of the roller shaft 5 is changed. Thereby, the moving speed of the step 2 is changed according to the position in the circulation path. That is, the upper and lower entrances are operated at a low speed, and the intermediate inclined part is operated at a high speed.
[0006]
[Problems to be solved by the invention]
In the conventional inclined high-speed escalator configured as described above, the riser 4 has a planar shape, whereas the auxiliary rail 13 in the speed change region has a smooth arc shape. . For this reason, in the process in which the steps of the steps 2 adjacent to each other change, the end portion of the step plate 3 is not displaced along the trajectory along the surface of the riser 4 of the steps 2 adjacent to the upper step, and interferes with the riser 4 There was a problem such as a gap between the riser 4 and the like.
[0007]
The present invention has been made to solve the above problems, and in the process of changing the steps of the adjacent steps, the step plate interferes with the riser of the adjacent step, or the riser and the step plate. It is an object of the present invention to obtain an inclined portion high-speed escalator capable of preventing a gap from being generated between the two.
[0008]
[Means for Solving the Problems]
The inclined portion high-speed escalator according to the present invention is provided in the main frame, the main frame, and the intermediate inclination located between the upper entrance / exit portion, the lower entrance / exit portion, and the upper entrance / exit portion and the lower entrance / exit portion. Rail which forms a circulation path including an upper curved portion located between the upper portion, the upper entrance / exit portion and the intermediate inclined portion, and a lower curved portion located between the lower entrance / exit portion and the intermediate inclined portion A plurality of drive rollers each having a drive roller shaft and a drive roller that is rotatable about the drive roller shaft and that is guided by the drive rail and rolls, and is endlessly connected and circulated along the circulation path A first link rotatably connected to the step and the drive roller shaft, and a second link rotatably connected to the link connection point of the first link and the drive roller shaft of the adjacent step The distance between the drive roller shafts can be changed by bending and stretching. A plurality of link mechanisms, a rotatable auxiliary roller provided in each link mechanism, and a main frame, which guides the movement of the auxiliary roller, causes the link mechanism to bend and extend, and sets the moving speed of the step to the upper transmission unit And an auxiliary rail that changes between the lower transmission unit and the shaft center of the adjacent drive roller shaft is in the upper transmission unit, and the horizontal and vertical relative coordinates of the axis of the drive roller shaft are expressed as (X_S, Y_S), The radius of curvature of the movement locus of the axis of the drive roller shaft at the upper curved portion is R₁-R in the vertical direction from the boundary point between the upper entrance / exit portion and the upper curved portion of the movement locus of the axis of the drive roller shaft₁A point that is only a distance away from the origin of coordinates_SRange is -R₁+ √ (R₁ ²-X_S ²) ≦ Y_SWhen <0, the relative position of the adjacent drive roller in the upper transmission unit and the horizontal coordinate X of the axis of the upper drive roller shaft₁, Horizontal coordinate Y of the axis of the upper drive roller shaft₁, Horizontal coordinate X of the axis of the lower drive roller shaft₂, And the horizontal coordinate Y of the axis of the lower drive roller shaft₂Is the relationship X₁= -X_S+ √ (−2R₁・ Y_S-Y_S ²), Y₁= R₁, X₂= X₁+ X_SAnd Y₂= Y₁+ Y_SThe position of the link connection point is expressed by the formula X_M= X₁+ L₁cos {β-γ} and Y_M= Y₁+ L₁sin {β-γ} (where β = tan^-1{(Y₁-Y₂) / (X₁-X₂)}, Γ = cos^-1{(L₁ ²-L₂ ²+ W²) / 2L₁W}, W = √ {(X₁-X₂)²+ (Y₁-Y₂)²}, X_M: Horizontal coordinate of link connection point, Y_M: Vertical coordinate of link connection point, L₁: Length from the axis of the upper drive roller shaft to the link connection point, L₂: The length from the axis of the lower drive roller shaft to the link connection point).
[0009]
The inclined portion high-speed escalator according to the present invention is provided in the main frame, the main frame, and is located between the upper entrance / exit part, the lower entrance / exit part, and the upper entrance / exit part. A circulation path including an intermediate inclined portion, an upper curved portion positioned between the upper entrance / exit portion and the intermediate inclined portion, and a lower curved portion positioned between the lower entrance / exit portion and the intermediate inclined portion is formed. A drive rail, a drive roller shaft, and a drive roller that can rotate around the drive roller shaft and roll while being guided by the drive rail, are connected endlessly and circulate along the circulation path. A first link rotatably connected to a plurality of steps and a drive roller shaft; a second link rotatably connected to a link connection point of the first link and a drive roller shaft of an adjacent step; Each of which has a link between the drive roller shafts. A plurality of link mechanisms that change the speed, a rotatable auxiliary roller that is provided in each link mechanism, and a main frame that guides the movement of the auxiliary roller, causes the link mechanism to bend and extend, and increases the moving speed of the step. Auxiliary rails that change between the transmission unit and the lower transmission unit are provided, the axis of the adjacent drive roller shaft is in the upper transmission unit, and the horizontal and vertical relative coordinates of the axis of the drive roller shaft are expressed as ( X_S, Y_S), The radius of curvature of the movement locus of the axis of the drive roller shaft at the upper curved portion is R₁, The slope of the intermediate slope is α_m-R in the vertical direction from the boundary point between the upper entrance / exit portion and the upper curved portion of the movement locus of the axis of the drive roller shaft₁A point that is only a distance away from the origin of coordinates_SRange is R₁cosα_m−√ {(R₁cosα_m)²+ (2R₁sinα_m・ X_S-X_S ²)} ≦ Y_S<-R₁+ √ (R₁ ²-X_S ²), The relative position of the adjacent drive roller in the upper transmission unit and the horizontal coordinate X of the axis of the upper drive roller shaft₁, Horizontal coordinate Y of the axis of the upper drive roller shaft₁, Horizontal coordinate X of the axis of the lower drive roller shaft₂, And the horizontal coordinate Y of the axis of the lower drive roller shaft₂Is the relationship X₁= [-P₁q₁+ √ {(p₁q₁)²− (P₁ ²+1) (q₁ ²-R₁ ²)}] / (P₁ ²+1), Y₁= √ (R₁ ²-X₁ ²), X₂= X₁+ X_SAnd Y₂= Y₁+ Y_S(However, p₁= X_S/ Y_S, Q₁= (X_S ²+ Y_S ²) / 2Y_S), And the position of the link connection point is represented by the formula X_M= X₁+ L₁cos {β-γ}), and Y_M= Y₁+ L₁sin {β-γ} (where β = tan^-1{(Y₁-Y₂) / (X₁-X₂)}, Γ = cos^-1{(L₁ ²-L₂ ²+ W²) / 2L₁W}, W = √ {(X₁-X₂)²+ (Y₁-Y₂)²}, X_M: Horizontal coordinate of link connection point, Y_M: Vertical coordinate of link connection point, L₁: Length from the axis of the upper drive roller shaft to the link connection point, L₂: The length from the axis of the lower drive roller shaft to the link connection point).
[0010]
The inclined portion high-speed escalator according to the present invention is provided in the main frame, the main frame, and is located between the upper entrance / exit part, the lower entrance / exit part, and the upper entrance / exit part. A circulation path including an intermediate inclined portion, an upper curved portion positioned between the upper entrance / exit portion and the intermediate inclined portion, and a lower curved portion positioned between the lower entrance / exit portion and the intermediate inclined portion is formed. A drive rail, a drive roller shaft, and a drive roller that can rotate around the drive roller shaft and roll while being guided by the drive rail, are connected endlessly and circulate along the circulation path. A first link rotatably connected to a plurality of steps and a drive roller shaft; a second link rotatably connected to a link connection point of the first link and a drive roller shaft of an adjacent step; Each of which has a link between the drive roller shafts. A plurality of link mechanisms that change the speed, a rotatable auxiliary roller that is provided in each link mechanism, and a main frame that guides the movement of the auxiliary roller, causes the link mechanism to bend and extend, and increases the moving speed of the step. An auxiliary rail that changes between the transmission unit and the lower transmission unit is provided, and the axis of the adjacent drive roller shaft is in the upper transmission unit, and the horizontal and vertical relative coordinates of the axis of the drive roller shaft are expressed as ( X_S, Y_S), The radius of curvature of the movement locus of the axis of the drive roller shaft at the upper curved portion is R₁, The slope of the intermediate slope is α_m-R in the vertical direction from the boundary point between the upper entrance / exit portion and the upper curved portion of the movement locus of the axis of the drive roller shaft₁A point that is only a distance away from the origin of coordinates_SRange is -X_Stanα_m≦ Y_S<R₁cosα_m−√ {(R₁cosα_m)²+ (2R₁sinα_m・ X_S-X_S ²)}, The relative position of the adjacent drive roller in the upper transmission unit and the horizontal coordinate X of the axis of the upper drive roller shaft₁, Horizontal coordinate Y of the axis of the upper drive roller shaft₁, Horizontal coordinate X of the axis of the lower drive roller shaft₂, And the horizontal coordinate Y of the axis of the lower drive roller shaft₂Is the relationship X₁= [-P₂s-√ {(p₂s)²− (P₂ ²+1) (s²-R²)}] / (P₂ ²+1), Y₁= √ (R₁ ²-X₁ ²), X₂= X₁+ X_SAnd Y₂= Y₁+ Y_S(However, p₂= -Tan α_m, Q₂= R₁(Cosα_m+ Sin α_m・ Tanα_m), S = p₂X_S+ Q₂-Y_S), And the position of the link connection point is represented by the formula X_M= X₁+ L₁cos {β-γ}), and Y_M= Y₁+ L₁sin {β-γ} (where β = tan^-1{(Y₁-Y₂) / (X₁-X₂)}, Γ = cos^-1{(L₁ ²-L₂ ²+ W²) / 2L₁W}, W = √ {(X₁-X₂)²+ (Y₁-Y₂)²}, X_M: Horizontal coordinate of link connection point, Y_M: Vertical coordinate of link connection point, L₁: Length from the axis of the upper drive roller shaft to the link connection point, L₂: The length from the axis of the lower drive roller shaft to the link connection point).
[0011]
The inclined portion high-speed escalator according to the present invention is provided in the main frame, the main frame, and is located between the upper entrance / exit part, the lower entrance / exit part, and the upper entrance / exit part. A circulation path including an intermediate inclined portion, an upper curved portion positioned between the upper entrance / exit portion and the intermediate inclined portion, and a lower curved portion positioned between the lower entrance / exit portion and the intermediate inclined portion is formed. A drive rail, a drive roller shaft, and a drive roller that can rotate around the drive roller shaft and roll while being guided by the drive rail, are connected endlessly and circulate along the circulation path. A first link rotatably connected to a plurality of steps and a drive roller shaft; a second link rotatably connected to a link connection point of the first link and a drive roller shaft of an adjacent step; Each of which has a link between the drive roller shafts. A plurality of link mechanisms that change the speed, a rotatable auxiliary roller that is provided in each link mechanism, and a main frame that guides the movement of the auxiliary roller, causes the link mechanism to bend and extend, and increases the moving speed of the step. There is an auxiliary rail that changes between the transmission unit and the lower transmission unit, and the axis of the adjacent drive roller shaft is in the lower transmission unit, and the horizontal and vertical relative coordinates of the axis of the drive roller shaft are determined. (X_S, Y_S), The radius of curvature of the movement locus of the axis of the drive roller shaft at the lower curved portion is R₂, R in the vertical direction from the boundary point between the lower entrance / exit part and the lower curved part of the movement locus of the axis of the drive roller shaft₂A point that is only a distance away from the origin of coordinates_SRange is -R₂+ √ (R₂ ²-X_S ²) ≦ Y_SWhen <0, the horizontal position X of the relative position of the adjacent drive roller in the lower transmission unit and the axis of the upper drive roller shaft₁, Horizontal coordinate Y of the axis of the upper drive roller shaft₁, Horizontal coordinate X of the axis of the lower drive roller shaft₂, And the horizontal coordinate Y of the axis of the lower drive roller shaft₂Is the relationship X₁= -√ (2R₂・ Y_S-Y_S ²), Y₁= -√ (R₂ ²-X₁ ²), X₂= X₁+ X_SAnd Y₂= Y₁+ Y_SThe position of the link connection point is expressed by the formula X_M= X₁+ L₁cos {β-γ}), and Y_M= Y₁+ L₁sin {β-γ} (where β = tan^-1{(Y₁-Y₂) / (X₁-X₂)}, Γ = cos^-1{(L₁ ²-L₂ ²+ W²) / 2L₁W}, W = √ {(X₁-X₂)²+ (Y₁-Y₂)²}, X_M: Horizontal coordinate of link connection point, Y_M: Vertical coordinate of link connection point, L₁: Length from the axis of the upper drive roller shaft to the link connection point, L₂: The length from the axis of the lower drive roller shaft to the link connection point).
[0012]
The inclined portion high-speed escalator according to the present invention is provided in the main frame, the main frame, and is located between the upper entrance / exit part, the lower entrance / exit part, and the upper entrance / exit part. A circulation path including an intermediate inclined portion, an upper curved portion positioned between the upper entrance / exit portion and the intermediate inclined portion, and a lower curved portion positioned between the lower entrance / exit portion and the intermediate inclined portion is formed. A drive rail, a drive roller shaft, and a drive roller that can rotate around the drive roller shaft and roll while being guided by the drive rail, are connected endlessly and circulate along the circulation path. A first link rotatably connected to a plurality of steps and a drive roller shaft; a second link rotatably connected to a link connection point of the first link and a drive roller shaft of an adjacent step; Each of which has a link between the drive roller shafts. A plurality of link mechanisms that change the speed, a rotatable auxiliary roller that is provided in each link mechanism, and a main frame that guides the movement of the auxiliary roller, causes the link mechanism to bend and extend, and increases the moving speed of the step. There is an auxiliary rail that changes between the transmission unit and the lower transmission unit, and the axis of the adjacent drive roller shaft is in the lower transmission unit, and the horizontal and vertical relative coordinates of the axis of the drive roller shaft are determined. (X_S, Y_S), The radius of curvature of the movement locus of the axis of the drive roller shaft at the lower curved portion is R₂, The slope of the intermediate slope is α_m, R in the vertical direction from the boundary point between the lower entrance / exit part and the lower curved part of the movement locus of the axis of the drive roller shaft₂A point that is only a distance away from the origin of coordinates_SRange is R₂cosα_m−√ {(R₂cosα_m)²+ (2R₂sinα_m・ X_S-X_S ²)} ≦ Y_S<-R₂+ √ (R₂ ²-X_S ²), The relative position of adjacent drive rollers in the lower transmission unit and the horizontal coordinate X of the axis of the upper drive roller shaft₁, Horizontal coordinate Y of the axis of the upper drive roller shaft₁, Horizontal coordinate X of the axis of the lower drive roller shaft₂, And the horizontal coordinate Y of the axis of the lower drive roller shaft₂Is the relationship X₁= [-P₃q₃−√ {(p₃q₃)²− (P₃ ²+1) (q₃ ²-R₂ ²)}] / (P₃ ²+1), Y₁= -√ (R₂ ²-X₁ ²), X₂= X₁+ X_SAnd Y₂= Y₁+ Y_S(However, p₃= X_S/ Y_S, Q₃= (X_S ²+ Y_S ²) / 2Y_S), And the position of the link connection point is represented by the formula X_M= X₁+ L₁cos {β-γ}), and Y_M= Y₁+ L₁sin {β-γ} (where β = tan^-1{(Y₁-Y₂) / (X₁-X₂)}, Γ = cos^-1{(L₁ ²-L₂ ²+ W²) / 2L₁W}, W = √ {(X₁-X₂)²+ (Y₁-Y₂)²}, X_M: Horizontal coordinate of link connection point, Y_M: Vertical coordinate of link connection point, L₁: Length from the axis of the upper drive roller shaft to the link connection point, L₂: The length from the axis of the lower drive roller shaft to the link connection point).
[0013]
The inclined portion high-speed escalator according to the present invention is provided in the main frame, the main frame, and is located between the upper entrance / exit part, the lower entrance / exit part, and the upper entrance / exit part. A circulation path including an intermediate inclined portion, an upper curved portion positioned between the upper entrance / exit portion and the intermediate inclined portion, and a lower curved portion positioned between the lower entrance / exit portion and the intermediate inclined portion is formed. A drive rail, a drive roller shaft, and a drive roller that can rotate around the drive roller shaft and roll while being guided by the drive rail, are connected endlessly and circulate along the circulation path. A first link rotatably connected to a plurality of steps and a drive roller shaft; a second link rotatably connected to a link connection point of the first link and a drive roller shaft of an adjacent step; Each of which has a link between the drive roller shafts. A plurality of link mechanisms that change the speed, a rotatable auxiliary roller that is provided in each link mechanism, and a main frame that guides the movement of the auxiliary roller, causes the link mechanism to bend and extend, and increases the moving speed of the step. There is an auxiliary rail that changes between the transmission unit and the lower transmission unit, and the axis of the adjacent drive roller shaft is in the lower transmission unit, and the horizontal and vertical relative coordinates of the axis of the drive roller shaft are determined. (X_S, Y_S), The radius of curvature of the movement locus of the axis of the drive roller shaft at the lower curved portion is R₂, The slope of the intermediate slope is α_m, R in the vertical direction from the boundary point between the lower entrance / exit part and the lower curved part of the movement locus of the axis of the drive roller shaft₂A point that is only a distance away from the origin of coordinates_SRange is -X_Stanα_m≦ Y_S<R₂cosα_m−√ {(R₂cosα_m)²+ (2R₂sinα_m・ X_S-X_S ²)}, The relative position of adjacent drive rollers in the lower transmission unit and the horizontal coordinate X of the axis of the upper drive roller shaft₁, Horizontal coordinate Y of the axis of the upper drive roller shaft₁, Horizontal coordinate X of the axis of the lower drive roller shaft₂, And the horizontal coordinate Y of the axis of the lower drive roller shaft₂Is the relationship X₁= {-(P₄q₄+ P₄Y_S+ X_s) + √A₁} / (P₄ ²+1), A₁= (P₄q₄+ P₄Y_S+ X_S)²− (P₄ ²+1) {(q₄+ Y_s)²-R₂ ²+ X_S ²}, Y₁= P₄X₁+ Q₄X₂= X₁+ X_SAnd Y₂= Y₁+ Y_S(However, p₄= -Tan α_m, Q₄= -R₂(Cosα_m+ Sin α_m・ Tanα_m)), And the position of the link connection point is expressed by the formula X_M= X₁+ L₁cos {β-γ}), and Y_M= Y₁+ L₁sin {β-γ} (where β = tan^-1{(Y₁-Y₂) / (X₁-X₂)}, Γ = cos^-1{(L₁ ²-L₂ ²+ W²) / 2L₁W}, W = √ {(X₁-X₂)²+ (Y₁-Y₂)²}, X_M: Horizontal coordinate of link connection point, Y_M: Vertical coordinate of link connection point, L₁: Length from the axis of the upper drive roller shaft to the link connection point, L₂: The length from the axis of the lower drive roller shaft to the link connection point).
[0014]
Further, the first link has a shape in which a part thereof is bent. From the relative position of the adjacent drive roller, the position of the axis of the auxiliary roller is expressed by the formula X_N= X₁+ V cos {β-γ-δ}, and Y_N= Y₁+ Vsin {β-γ-δ} (where V = √ (L₁ ²+ L₃ ²-2L₁L₃cos θ), δ = sin^-1(L₃sin θ / V), X_N: Horizontal coordinate of auxiliary roller axis, Y_N: Vertical coordinate of auxiliary roller axis, L₃: Length from the link connection point to the axis of the auxiliary roller, θ: line connecting the axis of the upper drive roller shaft and the link connection point, and line connecting the axis of the auxiliary roller and the link connection point (The size of the angle between the minute and the minute).
[0015]
DETAILED DESCRIPTION OF THE INVENTION
Embodiments of the present invention will be described below with reference to the drawings.
Embodiment 1 FIG.
1 is a side view showing an inclined high-speed escalator according to Embodiment 1 of the present invention. In the figure, the main frame 1 is provided with a plurality of steps 2 connected endlessly. The step 2 is driven by the drive unit 14 and is circulated. The main frame 1 includes a pair of drive rails 21 that form a circulation path for the steps 2, a pair of tracking rails 22 for controlling the posture of the steps 2, and a pair of assists for changing the interval between adjacent steps 2. Rails 23 are provided.
[0016]
The circulation path of the step 2 formed by the drive rail 21 has an outward path section, a return path section, an upper inversion section, and a lower inversion section. Further, the forward side section of the circulation path includes a horizontal upper entrance / exit part (upper horizontal part) A, an upper curved part B as an upper transmission part, an intermediate inclined part (constant inclined part) C having a constant inclination angle, and a lower side. A lower curved portion D that is a transmission portion and a horizontal lower entrance / exit portion (lower horizontal portion) E are included.
[0017]
The intermediate inclined portion C is located between the upper entrance / exit portion A and the lower entrance / exit portion E. The upper curved part B is located between the upper entrance / exit part A and the intermediate inclined part C. The lower curved portion D is located between the lower entrance / exit portion E and the intermediate inclined portion C.
[0018]
FIG. 2 is an enlarged side view showing the vicinity of the upper inversion portion in FIG. Each step 2 is rotatable around a step plate 3 on which passengers are placed, a riser 4 bent at the lower end of the step plate 3, a drive roller shaft 5 extending along the width direction of the step plate 3, and the drive roller shaft 5. A pair of driving rollers 6, a following roller shaft 7 extending in parallel with the driving roller shaft 5, and a pair of following rollers 8 that are rotatable about the following roller shaft 7 are provided. The drive roller 6 rolls along the drive rail 21. The follower roller 8 rolls along the follower rail 22.
[0019]
The drive roller shafts 5 of the steps 2 adjacent to each other are connected to each other by a pair of link mechanisms (refractive links) 24. Each link mechanism 24 has first and second links 25 and 26.
[0020]
One end of the first link 25 is rotatably connected to the drive roller shaft 5. A rotatable auxiliary roller 27 is provided at the other end of the first link 25. The auxiliary roller 27 rolls along the auxiliary rail 23. One end portion of the second link 26 is rotatably connected to a link connection point located at the intermediate portion of the first link 25 via a shaft 28. The other end of the second link 26 is rotatably connected to the drive roller shaft 5 of the step 2 adjacent to the lower side.
[0021]
The first link 25 has a dogleg shape bent around the link connection point. The second link 26 has a linear shape.
[0022]
When the auxiliary roller 27 is guided by the auxiliary rail 23, the link mechanism 24 is transformed so as to bend and extend, and the interval between the drive roller shafts 5, that is, the interval between the adjacent steps 2 is changed. In other words, the track of the auxiliary rail 23 is designed so that the interval between the adjacent steps 2 changes.
[0023]
Next, the operation will be described. In the forward side section of the circulation path of the step 2, the distance between the drive roller shafts 5 is the smallest in the upper entrance / exit part A and the lower entrance / exit part E. If the distance between the drive rail 21 and the auxiliary rail 23 is reduced from this state, the angle formed by the first and second links 25 and 26 is increased, and the distance between the drive roller shafts 5 is increased. In the intermediate inclined portion C, the interval between the drive rail 21 and the auxiliary rail 23 is the minimum, and the interval between the drive roller shafts 5 is the maximum.
[0024]
The speed of the step 2 is changed by changing the interval between the drive roller shafts 5. That is, at the upper and lower entrances A and E where passengers get on and off, the distance between the drive roller shafts 5 is minimized, and the step 2 is moved at a low speed. In the intermediate inclined portion C, the distance between the drive roller shafts 5 is maximized, and the step 2 is moved at a high speed. Further, in the upper curved portion B and the lower curved portion D, the distance between the drive roller shafts 5 is changed, and the step 2 is accelerated or decelerated.
[0025]
Next, a method for setting the position of the link connection point according to the first embodiment will be described with reference to FIGS. FIG. 3 is an explanatory view showing the movement locus of the axis of the drive roller shaft 5 in the vicinity of the upper entrance / exit part A and the upper curved part B of FIG. In the figure, the curvature radius of the movement locus of the axis of the drive roller shaft 5 at the upper curved portion B is R₁It is. The origin of the coordinates is −R in the vertical direction (y direction) from the boundary point 29 between the upper entrance / exit part A and the upper curved part B on the movement locus 3 of the axis of the drive roller shaft 5.₁I'm just at a point away.
[0026]
Here, the axis of the driving roller 6a of the upper step 2 (the axis of the driving roller shaft 5) is located at the upper entrance / exit part A, and its coordinates are (X₁, X₂). The axis of the driving roller 6b of the lower step 2 (the axis of the driving roller shaft 5) is located in the upper curved portion B, and its coordinates are (X₂, X₂). Further, the relative position of the axis of the drive roller 6b of the lower step with respect to the axis of the drive roller 6a of the upper step 2 is (X_S, Y_S).
[0027]
At this time, the movement locus of the axis of the drive roller 6a in the upper entrance / exit part A is:
y = R₁
Therefore, the relationship of the coordinates of the axis of the upper drive roller shaft 6a is
Y₁= R₁... (1)
It is. In the upper part B,
y²= R₁ ²-X²
And the coordinates of the axis of the drive roller 6b of the lower step are:
(X₂, Y₂) = (X₁+ X_S, Y₁+ Y_S)
It is. For this reason, the relationship of the coordinates of the axis of the lower drive roller 6b is
(Y₁+ Y_S)²= R₁ ²-(X₁+ X_S)²... (2)
It is.
[0028]
Here, both the expressions (1) and (2) are satisfied (X₁, Y₁) Is the relative position of the axis of the drive roller 6b of the lower step 2 with respect to the axis of the drive roller 6a of the upper step 2 (X)._S, Y_S), The coordinates of the axis of the upper drive roller 6a are expressed as follows.₁Ask for.
[0029]
First, when the equation (1) is substituted into the equation (2) and transformed, the following equation (3) is obtained.
X₁ ²+ 2X_SX₁+ (X_S ²+ 2R₁Y_S+ Y_S ²) = 0 ... (3)
Next, formula (3) is expressed as X₁Solve about.
X₁= -X_S+ √ (−2R₁・ Y_S-Y_S ²(4)
The Y coordinate is from equation (3).
Y₁= R
And the coordinate of the axis of the driving roller 6b of the lower step is (X₁+ X_S, Y₁+ Y_S).
[0030]
However, this relationship is a region between the time when the axis of the lower drive roller 6b is located at the boundary point 29 and the time when the axis of the upper drive roller 6a is located at the boundary point 29 (upper side). The shaft center of the drive roller shaft 5 is applied to the upper entrance / exit portion A, and the shaft center of the lower drive roller shaft 5 is applied to the upper curved portion B). The state where the axis of the lower drive roller 6b is located at the boundary point 29 is a limit point on the upper entrance / exit part A side of the upper curved part B to which the expression (2) can be applied. The state where the axis of the upper drive roller 6a is located at the boundary point 29 is a limit point on the upper curved portion B side of the upper entrance / exit portion A to which the equation (1) can be applied.
[0031]
When the axis of the lower drive roller 6b is located at the boundary point 29 between the upper entrance / exit part A and the upper curved part B, Y in Formula (2)₁= R₁, (X₁+ X_S) = 0, so these are substituted into the equation (2) and Y_SYou can ask for. That is,
(R₁+ Y_S)²= R₁ ²
Y_S(Y_S+ 2R₁) = 0
It becomes. Therefore,
Y_S= 0 (Y_S= -2R₁Is unsuitable) (6)
It becomes.
[0032]
Further, when the axis of the upper drive roller 6a is located at the boundary point 29 between the upper entrance / exit part A and the upper curved part B, X in Expression (2)₁= 0, Y₁= R₁Therefore, by substituting these into equation (2), Y_SYou can ask for. That is,
(R₁+ Y_S)²= R₁ ²-X_S ²
Y_S ²+ 2R₁Y_S+ X_S ²= 0
It becomes. Therefore,
Y_S= -R₁+ √ (R₁ ²-X_S ²)
(Y_S= -R₁-√ (R₁ ²-X_S ²) Is unsuitable) (7)
It becomes.
[0033]
Therefore, the expression (4) is expressed by the relative position Y in the y direction of the axis of the drive roller 6b of the lower step 2 with respect to the axis of the drive roller 6a of the upper step 2._SBut,
-R₁+ √ (R₁ ²-X_S ²) ≦ Y_S<0
It is applied in the range.
[0034]
FIG. 4 is an explanatory view showing the movement locus of the axis of the drive roller shaft 5 in the section closer to the intermediate inclined portion C than FIG. In the figure, the axis of the drive roller 6a of the upper step 2 and the axis of the drive roller 6b of the lower step 2 are both located in the upper curved portion B, and their coordinates are (X₁, X₂), (X₂, X₂). The relative position of the axis of the drive roller 6b of the lower step 2 with respect to the axis of the drive roller 6a of the upper step 2 is (X_S, Y_S).
[0035]
At this time, the movement locus of the axis of the drive rollers 6a and 6b in the upper curved portion B is as follows:
y²= R₁ ²-X²
It is expressed. Therefore, the relationship of the coordinates of the axis of the upper drive roller 6a is:
Y₁ ²= R₁ ²-X₁ ²... (8)
Y₁= √ (R₁ ²-X₁ ²)
(Y₁= -√ (R₁ ²-X₁ ²) Is unsuitable) ... (8) '
The relationship of the coordinates of the axis of the lower drive roller 6b is
(Y₁+ Y_S)²= R₁ ²-(X₁+ X_S)²... (9)
It is.
[0036]
Here, both the expressions (8) and (9) are satisfied (X₁, Y₁) Is the relative position of the axis of the drive roller 6b of the lower step 2 with respect to the axis of the drive roller 6a of the upper step 2 (X)._S, Y_S), The coordinates of the axis of the upper drive roller 6a are expressed as follows.₁Ask for.
[0037]
First, formula (9) is developed.
Y₁ ²+ 2Y_S・ Y₁+ Y_S ²= R₁ ²-X₁ ²-2X_S・ X₁-X_S ²... (9) '
Next, the expression (8) 'is substituted into the expression (9)'.
Y₁ ²+ 2Y_S√ (R₁ ²-X₁ ²) + Y_S ²= Y₁ ²-2X_S・ X₁-X_S ²
2Y_S√ (R₁ ²-X₁ ²) =-2X_S・ X₁-(X_S ²+ Y_S)
√ (R₁ ²-X₁ ²) =-(X_S/ Y_S) X₁-(X_S ²+ Y_S ²) / 2Y_S
[0038]
Where p₁= -X_S/ Y_S, Q₁=-(X_S ²+ Y_S ²) / 2Y_SAfter all,
√ (R₁ ²-X₁ ²) = P₁X₁+ Q₁
It becomes. If you deform by squaring both sides,
(P₁ ²+1) X₁ ²+ 2p₁q₁・ X₁+ (Q₁ ²-R₁ ²) = 0 ... (10)
[0039]
Equation (10) is expressed as a quadratic equation solution formula X₁Solving for
X₁= [-P₁q₁+ √ {(p₁q₁)²− (P₁ ²+1) (q₁ ²-R₁ ²)}] / (P₁ ²+1) ... (11)
(X₁= [-P₁q₁−√ {(p₁q₁)²− (P₁ ²+1) (q₁ ²-R₁ ²)}] / (P₁ ²+1) is inappropriate)
It becomes. However, p₁= X_S/ Y_S, Q₁= (X_S ²+ Y_S ²) / 2Y_S(Signs can be omitted)
[0040]
The Y coordinate is given by equation (3)
Y₁= √ (R₁ ²-X₁ ²)
The coordinate of the axis of the driving roller 6b of the lower step is (X₁+ X_S, Y₁+ Y_S).
[0041]
However, this relationship is such that the axis of the upper drive roller 6a is located at the boundary point 29 and the axis of the lower drive roller 6b is at the boundary point 30 between the upper curved portion B and the intermediate inclined portion C. This is applied in the region between the positions of the positions (the state where both the axis of the upper drive roller shaft 5 and the axis of the lower drive roller shaft 5 are located in the upper curved portion B). The state where the axis of the upper drive roller 6a is located at the boundary point 29 is a limit point on the upper entrance / exit part A side of the upper curved part B to which the equation (8) can be applied. The state where the axis of the lower drive roller 6b is located at the boundary point 30 is a limit point on the intermediate inclined portion C side of the upper curved portion B to which the equation (9) can be applied.
[0042]
The coordinates of the boundary point 30 between the upper curved portion B and the intermediate inclined portion C are (R₁sinα_m, R₁cosα_mTherefore, when the axis of the lower drive roller 6b is positioned on the boundary point 30, the following equation is established.
X₁= R₁sinα_m-X_S(12)
Y₁= R₁cosα_m-Y_S... (13)
[0043]
Substituting Equations (12) and (13) into Equation (8) for transformation.
(R₁cosα_m-Y_S)²= R₁ ²-(R₁sinα_m-X_S)²
R₁ ²cos²α_m-2R₁cosα_m・ Y_S+ Y_S ²
= R₁ ²-R₁ ²sin²α_m+ 2R₁sinα_m・ X_S-X_S ²
Y_S ²-2R₁cosα_m・ Y_S-(2R₁sinα_m・ X_S-X_S ²) = 0 ... (14)
[0044]
Equation (14) can be expressed as Y_SY when the axis of the lower drive roller 6b is located at the boundary point 30_SAsk for.
Y_S= R₁cosα_m−√ {(R₁cosα_m)²+ (2R₁sinα_m・ X_S-X_S ²)} ... (15)
(Y_S= R₁cosα_m+ √ {(R₁cosα_m)²+ (2R₁sinα_m・ X_S-X_S ²)} Is not suitable)
[0045]
Y when the axis of the upper drive roller 6a is located at the boundary point 29 between the upper entrance / exit part A and the upper curved part B_SIs already obtained from the equation (7), and if this equation is adopted, the equation (11) is obtained by converting the axis of the drive roller 6b of the lower step to the axis of the drive roller 6a of the upper step. Relative position Y_SBut
R₁cosα_m−√ {(R₁cosα_m)²+ (2R₁sinα_m・ X_S-X_S ²)} ≦ Y_S<-R₁+ √ (R₁ ²-X_S ²)
Applies when the range is
[0046]
FIG. 5 is an explanatory view showing the movement locus of the axis of the drive roller shaft 5 in the section on the intermediate inclined portion C side from FIG. Here, the axis of the driving roller 6a of the upper step 2 is located at the upper curved portion B, and its coordinates are (X₁, X₂), The axis of the driving roller 6b of the lower step 2 is located at the intermediate inclined portion C, and its coordinates are (X₂, X₂), The relative position of the axis of the drive roller 6b of the lower step 2 with respect to the axis of the drive roller 6a of the upper step 2 is (X_S, Y_S).
[0047]
At this time, the movement locus of the axis of the drive roller 6a in the upper entrance / exit part A is:
y²= R₁ ²-X²
Therefore, the relationship of the coordinate of the axis of the upper drive roller shaft is
Y₁ ²= R₁ ²-X₁ ²... (16)
It is. The straight line of the movement locus of the axis of the drive roller shaft in the intermediate inclined portion B is
y = p₂x + q2
Because it is expressed,
(Y₁+ Y_S) = P₂(X₁+ X_S) + Q₂... (17)
Y₁= P₂(X₁+ X_S) + (Q₂-Y_S) ... (17) '
It becomes.
[0048]
This straight line is the coordinates of the boundary point 30 between the upper curved portion B and the intermediate inclined portion C (Rsin α_m, Rcosα_m) Through a straight line with a slope p, where
p₂= -Tan α_m, Q₂= R₁(Cosα_m+ Sin α_m・ Tanα_m)
It is.
[0049]
Here, both (16) and (17) are satisfied (X₁, Y₁) Is the relative position of the axis of the drive roller 6b of the lower step 2 with respect to the axis of the drive roller 6a of the upper step 2 (X)._S, Y_S) Is the coordinate of the axis of the upper drive roller 6a, so that the equations (16) and (17)₁Ask for.
[0050]
First, square both sides of the equation (17) 'to obtain the equation (18).
Y₁ ²= {P₂(X₁+ X_S)}²+ 2p₂(X₁+ X_S) (Q₂-Y_S) + (Q₂-Y_S)²... (18)
Next, the equation (16) is substituted into the equation (18) for transformation.
R₁ ²-X₁ ²= {P₂(X₁+ X_S)}²+ 2p₂(X₁+ X_S) (Q₂-Y_S) + (Q₂-Y_S)²
(P₂ ²+1) X₁ ²+ 2p₂sX₁+ (S²-R₁ ²)} = 0 (19)
However, s = p₂X_S+ Q₂-Y_S
[0051]
Equation (19) is converted to X using the quadratic equation formula₁I will solve it.
X₁= [-P₂s-√ {(p₂s)²− (P₆ ²+1) (s²-R₁ ²)}] / (P₂ ²+1) (20)
(X₁= [-P₂s + √ {(p₂s)²− (P₆ ²+1) (s²-R₁ ²)}] / (P₂ ²+1) is inappropriate)
However, p₂= -Tan α_m, Q₂= R₁(Cosα_m+ Sin α_m・ Tanα_m), S = p₂X_S+ Q₂-Y_S
It is.
[0052]
The Y coordinate is given by equation (16):
Y₁= √ (R₁ ²-X₁ ²)
(Y₁= -√ (R₁ ²-X₁ ²) Is unsuitable)
It is. The coordinate of the axis of the driving roller 6b of the lower step 2 is (X₁+ X_S, Y₁+ Y_S).
[0053]
However, this relationship is such that when the axis of the lower drive roller 6b is located at the boundary point 30 between the upper curved portion B and the intermediate inclined portion C, the axis of the upper drive roller 6a is the upper bent portion B. And an intermediate slope portion C when located at the boundary point 30 (the axis of the upper drive roller shaft 5 is at the upper curved portion B, and the shaft center of the lower drive roller shaft 5 is at the intermediate slope. Applied to the part C). The state where the axis of the lower drive roller 6b is located at the boundary point 30 is the limit point on the intermediate inclined portion C side of the upper curved portion where the axis of the lower drive roller 6b can apply the equation (16). . The state where the axis of the upper drive roller 6a is located at the boundary point 30 is a limit point on the upper curved portion B side of the intermediate inclined portion C to which the equation (17) can be applied.
[0054]
The coordinates of the boundary point 30 between the upper curved portion B and the intermediate inclined portion C are (R₁sinα_m, R₁cosα_mTherefore, when the axis of the upper drive roller 6a is positioned on the boundary point 30, the following equation holds.
X₁= R₁sinα_m(21)
Y₁= R₁cosα_m(22)
The expressions (21) and (22) are substituted into the expression (17).
(R₁cosα_m+ Y_S) = P₂(R₁sinα_m+ X_S) + Q₂
p₂= -Tan α_m, Q₂= R₁(Cosα_m+ Sin α_m・ Tanα_m)
So
(R₁cosα_m+ Y_S) =
-Tan α_m(R₁sinα_m+ X_S) + R₁(Cosα_m+ Sin α_m・ Tanα_m)
Y_S= -X_S. tanα_m
[0055]
Y when the axis of the lower drive roller 6b is located at the boundary point 30 between the upper curved portion B and the intermediate inclined portion C_SIs already obtained from the equation (15), and if this equation is adopted, the equation (20) is obtained by using the axis of the driving roller 6b of the lower step 2 with respect to the axis of the driving roller 6a of the upper step 2. Relative position Y in the y direction_SBut,
-X_S. tanα_m≦ Y_S
<R₁cosα_m−√ {(R₁cosα_m)²+ (2R₁sinα_m・ X_S-X_S ²)}
Applies when the range is
[0056]
FIG. 6 is an explanatory view showing the movement locus of the axis of the drive roller shaft 5 in the vicinity of the lower entrance / exit part E and the lower curved part D of FIG. In the figure, the radius of curvature of the movement locus 5a of the axis of the drive roller shaft 5 at the lower curved portion D is R₂It is. The origin of the coordinates is R in the vertical direction (y direction) from the boundary point 31 between the lower entrance / exit portion E and the lower curved portion D of the movement locus 5a of the axis of the drive roller shaft 5.₂I'm just at a point away.
[0057]
Here, the axis of the driving roller 6a of the upper step 2 is located at the lower curved portion D, and its coordinates are (X₁, X₂). The axis of the driving roller 6b of the lower step 2 is located at the lower entrance / exit E, and its coordinates are (X₂, X₂). Further, the relative position of the axis of the drive roller 6b of the lower step 2 with respect to the axis of the drive roller 6a of the upper step 2 is (X_S, Y_S).
[0058]
At this time, the movement locus of the axis of the driving roller 6a in the lower curved portion D is as follows:
y²= R₂ ²-X²
It is expressed. For this reason, the relationship of the coordinates of the axis of the upper drive roller shaft 5 is
Y₁ ²= R₂ ²-X₁ ²(23)
It is. Moreover, in the lower entrance / exit part E,
y = -R₂
Thus, the coordinate of the axis of the drive roller 6b of the lower step 2 is
(Y₁+ Y_S) =-R₂... (24)
Y₁= -R₂-Y_S... (24) '
It is.
[0059]
Here, both the expressions (23) and (24) are satisfied (X₁, Y₁) Is the relative position of the axis of the drive roller 6b of the lower step 2 with respect to the axis of the drive roller 6a of the upper step 2 (X)._S, Y_S), The coordinates of the axis of the upper drive roller 6a are expressed as follows.₁Ask for.
[0060]
When the equation (24) ′ is substituted into the equation (23) and transformed, the following equation (25) is obtained.
X₁ ²= 2R₂Y_S-Y_S ²... (25)
Therefore,
X₁= -√ (2R₂・ Y_S-Y_S ²) ... (26)
(X₁= + √ (2R₂・ Y_S-Y_S ²) Is unsuitable)
The Y coordinate is
Y₁= -√ (R₂ ²-X₁ ²)
(Y₁= √ (R₂ ²-X₁ ²) Is unsuitable)
It is. Accordingly, the coordinate of the axis of the driving roller 6b of the lower step 2 is (X₁+ X_S, Y₁+ Y_S).
[0061]
However, this relationship is such that the axis of the upper drive roller 6a is positioned at the boundary point 31 between the lower entrance / exit E and the lower curved portion D, and the axis of the lower drive roller 6b is the boundary point. 31 (when the upper drive roller shaft 5 is located at the lower bent portion D, and the lower drive roller shaft 5 is located at the lower entrance E. Applied). The state where the axis of the upper drive roller 6a is located at the boundary point 31 is a limit point on the lower entrance / exit part E side of the lower curved part D to which the equation (23) can be applied. The state where the axis of the lower drive roller 6b is located at the boundary point 31 is a limit point on the lower curved portion D side of the lower entrance / exit portion E to which the equation (24) can be applied.
[0062]
When the axis of the upper drive roller 6a is located at the boundary point 31 between the lower entrance / exit part E and the lower curved part D, Y₁= −R, so this is substituted into the equation (24) and Y_SAsk for
Y_S= 0 (27)
It becomes. When the axis of the lower drive roller 6b is located at the boundary point 31 between the lower entrance / exit part E and the lower curved part D,
X₁+ X_S= 0 and X₁= -X_S... (28)
Y₁+ Y_S= -R₂, Y₁=-(R₂+ Y_S) ... (29)
Furthermore, substituting Equation (28) and Equation (29) into Equation (23)
(R₂+ Y_S)²= R₂ ²-X_S ²
Y_S ²+ 2R₂・ Y_S-X_S ²= 0 (30)
[0063]
Using equation (30) to solve the quadratic equation, Y_SWhen you solve about
Y_S= -R₂+ √ (R₂ ²-X_S ²(31)
(Y_S= R₂-√ (R₂ ²-X_S ²) Is unsuitable)
It becomes. Therefore, the equation (26) is expressed by the relative position Y in the y direction of the axis of the drive roller 6b of the lower step 2 with respect to the axis of the drive roller 6a of the upper step 2._SBetween (27) and (31)
-R₂+ √ (R₂ ²-X_S ²) ≦ Y_S<0
It is applied in the range.
[0064]
FIG. 7 is an explanatory diagram showing the movement locus of the axis of the drive roller shaft 5 in the section closer to the intermediate inclined portion C than FIG. In the figure, the axis of the driving roller 6a of the upper stage 2 and the axis of the driving roller 6b of the lower stage 2 are both located in the lower curved portion D, and their coordinates are (X₁, X₂), (X₂, X₂). The relative position of the axis of the drive roller 6b of the lower step 2 with respect to the axis of the drive roller 6a of the upper step 2 is (X_S, Y_S).
[0065]
At this time, the movement trajectory of the axis of the driving rollers 6a and 6b in the lower curved portion D is
y²= R₂ ²-X²
It is expressed. Therefore, the relationship of the coordinates of the axis of the upper drive roller 6a is:
Y₁ ²= R₂ ²-X₁ ²... (32)
Y₁= -√ (R₂ ²-X₁ ²)
(Y₁= √ (R₂ ²-X₁ ²) Is unsuitable) ... (32) '
The relationship of the coordinates of the axis of the lower drive roller 6b is
(Y₁+ Y_S)²= R₂ ²-(X₁+ X_S)²... (33)
It is.
[0066]
Here, both (32) and (33) are satisfied (X₁, Y₁) Is the relative position of the axis of the drive roller 6b of the lower step with respect to the axis of the drive roller 6a of the upper step (X_S, Y_S), The coordinates of the axis of the upper drive roller 6a at the time of₁Ask for.
[0067]
First, formula (33) is developed.
Y₁ ²+ 2Y_S・ Y₁+ Y_S ²= R₂ ²-X₁ ²-2X_S・ X₁-X_S ²... (33) '
Next, the expression (32) 'is substituted into the expression (33)'.
Y₁ ²-2Y_S√ (R₂ ²-X₁ ²) + Y_S ²= Y₁ ²-2X_S・ X₁-X_S ²
-2Y_S√ (R₂ ²-X₁ ²) =-2X_S・ X₁-(X_S ²+ Y_S)
√ (R₂ ²-X₁ ²) = (X_S/ Y_S) X₁+ (X_S ²+ Y_S ²) / 2Y_S
[0068]
Where p₃= X_S/ Y_S, Q₁= (X_S ²+ Y_S ²) / 2Y_SAfter all,
√ (R₂ ²-X₁ ²) = P₁X₁+ Q₁
It becomes. If you deform by squaring both sides,
(P₁ ²+1) X₁ ²+ 2p₁q₁. X₁+ (Q₁ ²-R₂ ²) = 0 ... (34)
It becomes. Equation (10) is expressed as a quadratic equation solution formula X₁Solve about.
X₁= [-P₃q₃−√ {(p₃q₃)²− (P₃ ²+1) (q₃ ²-R₂ ²)}] / (P₃ ²+1) ... (35)
(X₁= [-P₃q₃+ √ {(p₃q₃)²− (P₃ ²+1) (q₃ ²-R₂ ²)}] / (P₃ ²+1) is inappropriate)
Where p₃= X_S/ Y_S, Q₃= (X_S ²+ Y_S ²) / 2Y_S
The Y coordinate is from equation (32) '
Y₁= -√ (R₂ ²-X₁ ²)
(Y₁= √ (R₂ ²-X₁ ²) Is unsuitable)
The coordinate of the axis of the driving roller 6b of the lower step is (X₁+ X_S, Y₁+ Y_S).
[0069]
However, this relationship is such that when the axis of the lower drive roller 6b is positioned at the boundary point 31 between the lower entrance / exit part E and the lower bent part D, the axis of the upper drive roller 6a is bent downward. The region between the portion D and the intermediate inclined portion C when located at the boundary point 32 (the shaft center of the upper drive roller shaft 5 and the shaft center of the lower drive roller shaft 5 are both located in the lower curved portion D. Applied). The state where the axis of the lower drive roller 6b is located at the boundary point 31 is a limit point on the lower entrance / exit part E of the lower curved part D to which the equation (32) can be applied. The state where the axis of the upper drive roller 6a is positioned at the boundary point 32 is a limit point on the intermediate inclined portion C side of the lower curved portion D to which the equation (33) can be applied.
[0070]
The coordinates of the boundary point 32 between the lower curved portion D and the intermediate inclined portion C are (−R₂sinα_m, -R₂cosα_mTherefore, when the axis of the upper drive roller 6a is positioned on the boundary point 32, the following equation holds.
X₁= -R₂sinα_m... (36)
Y₁= -R₂cosα_m... (37)
Substituting Equations (36) and (37) into Equation (32) for transformation.
(-R₂cosα_m+ Y_S)²= R₂ ²-(-R₂sinα_m+ X_S)²
R₂ ²cos²α_m-2R₂cosα_m. Y_S+ Y_S ²= R₂ ²-R₂ ²sin²α_m+ 2R₂sinα_m. X_S-X_S ²
Y_S ²-2R₂cosα_m. Y_S-(2R₂sinα_m. X_S-X_S ²) = 0 ... (38)
[0071]
Equation (38) can be expressed as Y_SY when the axis of the upper drive roller 6a is located at the boundary point 32 between the lower curved portion D and the intermediate inclined portion C._SAsk for.
Y_S= R₂cosα_m−√ {(R₂cosα_m)²+ (2R₂sinα_m・ X_S-X_S ²)} ... (39)
(Y_S= R₂cosα_m+ √ {(R₂cosα_m)²+ (2R₂sinα_m・ X_S-X_S ²)} Is not suitable)
[0072]
Y when the axis of the lower drive roller 6b is located at the boundary 31 between the lower entrance / exit part E and the lower curved part D_SIs already obtained from the equation (31), and if this equation is adopted, the equation (35) is the y direction of the axis of the drive roller 6b of the lower step with respect to the axis of the drive roller 6a of the upper step. Relative position Y_SBut
R₂cosα_m−√ {(R₂cosα_m)²+ (2R₂sinα_m・ X_S-X_S ²)} ≦ Y_S<-R₂+ √ (R₂ ²-X_S ²)
It is applied in the range.
[0073]
FIG. 8 is an explanatory view showing the movement locus of the axis of the drive roller shaft 5 in the section on the intermediate inclined portion C side from FIG. In the figure, the axis of the driving roller 6a of the upper step 2 is located at the intermediate inclined portion C, and its coordinates are (X₁, X₂). The axis of the driving roller 6b of the lower step 2 is located at the lower curved portion D, and its coordinates are (X₂, X₂). Furthermore, the relative position of the shaft center of the drive roller 6b of the lower step 2 with respect to the shaft center of the drive roller 6a of the upper step 2 is (X_S, Y_S).
[0074]
The straight line of the movement locus of the axis of the drive roller shaft in the intermediate inclined portion C is
y = p₄x + q₄
It is represented by Therefore, the coordinates of the axis of the upper drive roller 6a located at the intermediate inclined portion C are:
Y₁= P₄X₁+ Q₄... (40)
This straight line is the coordinate (−R of the boundary point 32 between the lower curved portion D and the intermediate inclined portion C₂sinα_m, -R₂cosα_m) P₄Here is a straight line of
p₄= -Tan α_m, Q₂= -R₂(Cosα_m-Sin α_m・ Tanα_m)
It is.
[0075]
Furthermore, the movement locus of the axis of the lower drive roller 6b in the lower curved portion D is:
y²= R₂ ²-X²
It is expressed. Therefore, the relationship of the coordinates of the axis of the lower drive roller 6b is:
(Y₁+ Y_S)²= R₂ ²-(X₁+ X_S)²... (41)
It is. When expanding (41) and substituting (40) for transformation,
(P₄ ²+1) X₁ ²+2 (p₄q₄+ P₄Y_S+ X_S) X₁+ {(Q₄+ Y_S)²-R₂ ²+ X_S ²} = 0 (42)
[0076]
(42) is converted to X using the quadratic equation solution formula.₁Solve about.
X₁= {-(P₄q₄+ P₄Y_S+ X_s) + √A₁} / (P₄ ²+1)
A₁= (P₄q₄+ P₄Y_S+ X_S)²− (P₄ ²+1) {(q₄+ Y_s)²-R₂ ²+ X_S ²} ... (43)
(X₁= {-(P₄q₄+ P₄Y_S+ X_s) -√A₁} / (P₄ ²+1) is inappropriate)
However, p₄= -Tan α_m, Q₂= -R₂(Cosα_m+ Sin α_m・ Tanα_m).
The Y coordinate at that time is given by equation (40).
Y₁= P₄X₁+ Q₄
The coordinate of the axis of the driving roller 6b of the lower step is (X₁+ X_S, Y₁+ Y_S).
[0077]
However, this relationship is such that the axis of the upper drive roller 6a is positioned at the boundary point 32 between the lower curved portion D and the intermediate inclined portion C, and the axis of the lower drive roller 6b is at the boundary point 32. Applicable in the region between the positions (the state where the axis of the upper drive roller shaft 5 is positioned at the intermediate inclined portion C and the shaft center of the lower drive roller shaft 5 is positioned at the lower bent portion D) Is done. The state where the axis of the upper drive roller 6a is located at the boundary point 32 is a limit point on the lower curved portion D side of the intermediate inclined portion C to which the equation (40) can be applied. The state where the axis of the lower drive roller 6b is located at the boundary point 32 is a limit point on the intermediate inclined portion C side of the lower curved portion D to which the equation (41) can be applied.
[0078]
The coordinates of the boundary point 32 between the lower curved portion D and the intermediate inclined portion C are (−R₂sinα_m, -R₂cosα_mTherefore, when the axis of the lower drive roller 6a is positioned on the boundary point 32, the following equation is established.
X₁+ X_S= -R₂sinα_mX₁= -R₂sinα_m-X_S... (44)
Y₁+ Y_S= -R₂cosα_mY₁= -R₂cosα_m-Y_S... (45)
Substituting equations (44) and (45) into equation (40)
-R₂cosα_m-Y_S= P₄(-R₂sinα_m-X_S) + Q₄... (46)
[0079]
Where p₄= -Tan α_m, Q₂= -R₂(Cosα_m+ Sin α_m・ Tanα_m)
-R₂cosα_m-Y_S= R₂sinα_m. tanα_m+ X_Stanα_m-R₂cosα_m-R₂sinα_m・ Tanα_m
Y_S= -X_Stanα_m
It becomes.
[0080]
Y when the axis of the lower drive roller 6b is located at the boundary point 32 between the lower curved portion D and the intermediate inclined portion C_SIs already obtained from the equation (39), and if this equation is adopted, the equation (43) is obtained by calculating the axis of the drive roller 6b of the lower step 2 with respect to the axis of the drive roller 6a of the upper step 2. R relative position Y_SBut,
-X_Stanα_m≦ Y_S<R₂cosα_m−√ {(R₂cosα_m)²+ (2R₂sinα_m・ X_S-X_S ²)}
It is applied in the range.
[0081]
By the above method, in the upper curved portion B and the lower curved portion D where the level difference of the step 2 changes, the axial center coordinates of the upper drive roller 6a and the lower step are determined from the relative coordinates of the axis of the adjacent drive roller shaft 5. The axial center coordinate of the driving roller 6b on the side can be obtained.
[0082]
Next, FIG. 9 is an explanatory view showing the relationship between the position of the axis of the drive roller shaft, the position of the link connection point, and the position of the axis of the auxiliary roller in the inclined portion high-speed escalator of FIG. Here, a procedure for obtaining the position of the link connection point M (shaft 28) from the positions of the shaft centers G and F of the adjacent drive roller shafts 5 obtained by the above procedure will be described.
[0083]
The coordinates of the axis G of the upper drive roller shaft 5 (drive roller 6a) are expressed as (X_G, Y_G) And the coordinates of the axis F of the lower drive roller shaft 5 (drive roller 6b) (X_F, Y_F), The distance W between the axes is
W = √ {(X_G-X_F)²+ (Y_G-Y_F)²}
It is. The angle β between the line FG connecting the two axes and the horizontal line is
β = tan^―1{(Y_F-Y_G) / (X_F-X_G)}
It is.
[0084]
Here, the distance of the line segment GM from the axis G of the upper drive roller shaft 5 to the link connection point M is expressed as L₁The length of the line segment FM from the axis F of the lower drive roller shaft 5 to the link connection point M is L₂Then, the angle γ between the line segment GF and the line segment GM is
γ = cos^―1{(L₁ ²-L₂ ²+ W²) / 2L₁W} ... The second cosine theorem
It is. Since the angle of the line segment FM with respect to the horizontal line is β−γ, the coordinates (X_M, Y_M)
X_M= X_F+ L₁cos {β-γ}
Y_M= Y_F+ L₁sin {β-γ}
The relationship between the relative position of the shaft center of the drive roller shaft 5 and the position of the link connection point can be obtained.
[0085]
Also, the coordinates (X_M, Y_M) Is successively calculated along the movement locus of the relative coordinates of the axis of the drive roller shaft 5, the movement locus of the link connection point M can be obtained. Further, the movement locus of the axis N of the auxiliary roller 27 can be obtained from the movement locus of the link connection point M. The shape obtained by offsetting the obtained movement locus of the axis N of the auxiliary roller 27 by the radius of the auxiliary roller 27 can be used as the shape of the auxiliary rail 23.
[0086]
Further, if the shape of the riser 4 is substantially matched to the movement locus of the axis of the adjacent drive roller shaft 5, the step plate 3 is attached to the riser 4 of the adjacent step 2 in the process of changing the step of the adjacent step 2. It is possible to prevent interference and a gap between the riser 4 and the tread 3. That is, although it is possible to set the trajectory of the drive roller shaft 5 and the trajectory of the link connection point separately, in that case, interference or a gap occurs. On the other hand, the occurrence of interference and gaps can be prevented by providing the above relationship between the trajectory of the drive roller shaft 5 and the trajectory of the link connection point.
[0087]
Next, a method for setting the position of the axis of the auxiliary roller 27 will be described. In FIG. 9, the coordinate of the axis N of the auxiliary roller 27 is represented by (X_N, Y_N). In addition, the length of the line segment MN from the axis N to the link connection point M is set to L₃And Furthermore, line segment MN and length L₁The angle formed by the line segment GM is θ. At this time, the length V of the line segment GN connecting the coordinate of the axis G of the upper drive roller shaft 5 and the axis N of the auxiliary roller 27 is:
V₂ ²= L₁ ²+ L₃ ²-2L₁L₃cosθ ・・・ The second cosine theorem
From
V = √ (L₁ ²+ L₃ ²-2L₁L₃cos θ)
It becomes. Θ is
V / sin θ = L₃/ Sinδ ・・・ Sine theorem
From
δ = sin^―1(L₃sin θ / V)
It becomes.
[0088]
Here, the angle of the line segment GN with respect to the horizontal line is β−γ−δ. Therefore, the coordinate of the axis N of the auxiliary roller 27 is
X_N= X₁+ Vcos {β-γ-δ}
Y_N= Y₁+ L₁sin {β-γ-δ}
Can be obtained as
[0089]
Such coordinates of the axis N (X_N, Y_N) Is sequentially calculated along the movement locus of the relative coordinates of the axis of the drive roller shaft 5, the movement locus of the axis N of the auxiliary roller 27 can be obtained. Then, the shape of the auxiliary rail 23 can be obtained by offsetting the movement locus of the axis of the auxiliary roller 27 by the radius of the drive roller 27.
[0090]
Embodiment 2. FIG.
In the first embodiment, the link mechanism 24 having the first and second links 25 and 26 is used. However, for example, a link mechanism 41 constituting a pantograph type quadruple link mechanism as shown in FIG. 10 is used. Also good. In FIG. 10, the link mechanism 41 has first to fifth links 42 to 46.
[0091]
One end of the first link 42 is rotatably connected to the drive roller shaft 5. The other end portion of the first link 42 is rotatably connected to an intermediate portion of the third link 44 via a shaft 47. One end of the second link 43 is rotatably connected to the drive roller shaft 5 of the adjacent step 2. The other end of the second link 43 is rotatably connected to an intermediate portion of the third link 44 via a shaft 47.
[0092]
One end portion of the fourth link 45 is rotatably connected to the intermediate portion of the first link 42. One end portion of the fifth link 46 is rotatably connected to an intermediate portion of the second link 43. The other ends of the fourth and fifth links 45 and 46 are connected to one end of the third link 44 via a sliding shaft 48.
[0093]
A guide groove 44 a that guides the sliding of the sliding shaft 48 in the longitudinal direction of the third link 44 is provided at one end of the third link 44. A rotatable auxiliary roller 27 is provided at the other end of the third link 44.
[0094]
Even when such a link mechanism 42 is used, the link connection point (shaft 47) is determined from the relative positions of the shaft center of the upper drive roller 6a and the shaft center of the lower drive roller 6b, as in the first embodiment. And the movement trajectory of the link connection point can be obtained. Further, the movement locus of the axis of the auxiliary roller 27 can also be obtained from the movement locus of the link connection point. Further, if the shape of the riser 4 is made to substantially coincide with the movement locus of the axis of the adjacent drive roller shaft 5, the step board 3 is attached to the riser 4 of the adjacent step 2 in the process of changing the step of the adjacent step 2. It is possible to prevent interference and a gap between the riser 4 and the tread 3.
[0095]
In the first and second embodiments, the shape of the riser 4 is made to substantially coincide with the movement locus of the relative position of the axis of the adjacent drive roller shaft 5. However, after the shape of the riser 4 is first determined, The procedure may be such that the movement locus of the relative position of the axial center of the drive roller shaft 5 is determined so as to match it.
[0096]
【The invention's effect】
As described above, according to the inclined portion high-speed escalator of the present invention, the position of the link connection point can be obtained from the movement locus of the relative position of the adjacent drive roller axis, and the shape of the auxiliary roller rail can be set. If the riser shape is made to substantially match the movement locus of the relative position of the drive roller shaft center, the step plate will not interfere with the riser of an adjacent step or a gap will not be created between the riser and the step plate A high-speed escalator can be constructed.
[Brief description of the drawings]
FIG. 1 is a side view showing an inclined high-speed escalator according to Embodiment 1 of the present invention.
2 is an enlarged side view showing the vicinity of an upper inversion portion in FIG. 1. FIG.
3 is an explanatory diagram showing a movement locus of an axis of a drive roller shaft in the vicinity of an upper entrance / exit part and an upper curved part in FIG. 1;
4 is an explanatory diagram showing a movement locus of an axis of a drive roller shaft in a section closer to the intermediate inclined portion than FIG. 3;
FIG. 5 is an explanatory diagram showing a movement locus of an axis of a driving roller shaft in a section closer to the intermediate inclined portion than FIG.
6 is an explanatory diagram showing the movement locus of the axis of the drive roller shaft in the vicinity of the lower entrance / exit part and the lower curved part of FIG. 1;
7 is an explanatory diagram showing a movement locus of an axis of a driving roller shaft in a section closer to the intermediate inclined portion than FIG. 6;
FIG. 8 is an explanatory diagram showing a movement locus of an axis of a drive roller shaft in a section closer to the intermediate inclined portion than FIG.
FIG. 9 is an explanatory diagram showing the relationship between the position of the axis of the drive roller shaft, the position of the link connection point, and the position of the axis of the auxiliary roller in the inclined portion high-speed escalator of FIG. 1;
FIG. 10 is a side view showing an essential part of an inclined portion high-speed escalator according to Embodiment 2 of the present invention.
FIG. 11 is a side view showing a main part of an example of a conventional inclined portion high-speed escalator.
[Explanation of symbols]
1 main frame, 2 steps, 5 drive roller shaft, 6 drive roller, 21 drive rail, 23 auxiliary rail, 24 link mechanism, 25 first link, 26 second link, 27 auxiliary roller.

Claims

Main frame,
Provided in the main frame, an upper entrance / exit portion, a lower entrance / exit portion, an intermediate inclined portion located between the upper entrance / exit portion and the lower entrance / exit portion, the upper entrance / exit portion, and the above A drive rail that forms a circulation path that includes an upper curved portion located between the intermediate inclined portion and a lower curved portion located between the lower entrance / exit portion and the intermediate inclined portion;
Each has a driving roller shaft and a driving roller that is rotatable about the driving roller shaft and that is guided by the driving rail and rolls, and is connected endlessly and circulated along the circulation path. Multiple steps,
A first link rotatably connected to the drive roller shaft; a second link rotatably connected to a link connection point of the first link and a drive roller shaft of an adjacent step; A plurality of link mechanisms that change the distance between the drive roller shafts by performing bending and stretching operations,
A rotatable auxiliary roller provided in each of the link mechanisms, and provided in the main frame, guiding the movement of the auxiliary rollers to cause the link mechanism to bend and extend, and to change the moving speed of the steps to the upper transmission unit. Auxiliary rails that change with the lower transmission
The shaft center of the adjacent drive roller shaft is in the upper transmission unit, and the horizontal and vertical relative coordinates of the shaft center of the drive roller shaft are (X _S , Y _S ), and the drive in the upper curved portion The radius of curvature of the movement locus of the axis of the roller shaft is R ₁ , and is separated by −R _{1 in the} vertical direction from the boundary point between the upper entrance / exit portion and the upper curve portion of the movement locus of the axis of the drive roller shaft. With the point as the origin of coordinates, the range of Y _S is −R ₁ + √ (R ₁ ² −X _S ² ) ≦ Y _S <0
When
The relative position of the adjacent drive roller in the upper transmission unit, the horizontal coordinate X _{1 of} the upper drive roller shaft axis, and the horizontal coordinate Y _{1 of the} upper drive roller shaft axis. The relationship between the horizontal coordinate X _{2 of} the axis of the lower drive roller shaft and the horizontal coordinate Y ₂ of the lower drive roller shaft is expressed by the equation X ₁ = −X _S + √ (−2R ₁ · Y _S −Y _S ² ),
Y ₁ = _R _1,
X ₂ = X ₁ + X _S and Y ₂ = Y ₁ + Y _S
Represented by
The position of the link connection point is expressed by the formula X _M = X ₁ + L ₁ cos {β-γ} and Y _M = Y ₁ + L ₁ sin {β-γ}.
(However,
β = tan ⁻¹ {(Y ₁ −Y ₂ ) / (X ₁ −X ₂ )},
γ = cos ⁻¹ {(L ₁ ² −L ₂ ² + W ² ) / 2L ₁ W},
W = √ {(X ₁ −X ₂ ) ² + (Y ₁ −Y ₂ ) ² },
X _M : horizontal coordinate of the link connecting point,
Y _M : vertical coordinate of the link connecting point,
L ₁ : length from the axis of the drive roller shaft on the upper stage side to the link connection point;
L ₂ : Length from the axis of the drive roller shaft on the lower stage side to the link connection point)
Inclined part high-speed escalator characterized by being set by.

Main frame,
Provided in the main frame, an upper entrance / exit portion, a lower entrance / exit portion, an intermediate inclined portion located between the upper entrance / exit portion and the lower entrance / exit portion, the upper entrance / exit portion, and the above A drive rail that forms a circulation path that includes an upper curved portion located between the intermediate inclined portion and a lower curved portion located between the lower entrance / exit portion and the intermediate inclined portion;
Each has a driving roller shaft and a driving roller that is rotatable about the driving roller shaft and that is guided by the driving rail and rolls, and is connected endlessly and circulated along the circulation path. Multiple steps,
A first link rotatably connected to the drive roller shaft; a second link rotatably connected to a link connection point of the first link and a drive roller shaft of an adjacent step; A plurality of link mechanisms that change the distance between the drive roller shafts by performing bending and stretching operations,
A rotatable auxiliary roller provided in each of the link mechanisms, and provided in the main frame, guiding the movement of the auxiliary rollers to cause the link mechanism to bend and extend, and to change the moving speed of the steps to the upper transmission unit. Auxiliary rails that change with the lower transmission
The shaft center of the adjacent drive roller shaft is in the upper transmission unit, and the horizontal and vertical relative coordinates of the shaft center of the drive roller shaft are (X _S , Y _S ), and the drive in the upper curved portion The radius of curvature of the movement locus of the axis of the roller shaft is R ₁ , the inclination of the intermediate inclined portion is α _m , and the boundary between the upper entrance / exit portion of the movement locus of the axis of the drive roller shaft and the upper curve portion The range of Y _S is R ₁ cos α _m −√ {(R ₁ cos α _m ) ² + (2R ₁ sin α _m · X _S −X _S ^{2, with the} point perpendicular to the point −R ₁ as the origin of coordinates. )} ≦ Y _S <−R ₁ + √ (R ₁ ² −X _S ² )
When
The relative position of the adjacent drive roller in the upper transmission unit, the horizontal coordinate X _{1 of} the upper drive roller shaft axis, and the horizontal coordinate Y _{1 of the} upper drive roller shaft axis. The relationship between the horizontal coordinate X _{2 of} the axis of the lower drive roller shaft and the horizontal coordinate Y ₂ of the lower drive roller shaft is expressed by the equation X ₁ = [− p ₁ q ₁ + √ {(p ₁ q ₁ ) ² − (p ₁ ² +1) (q ₁ ² −R ₁ ² )}] / (p ₁ ² +1),
Y ₁ = √ (R ₁ ² −X ₁ ² ),
X ₂ = X ₁ + X _S and Y ₂ = Y ₁ + Y _S
(However, p ₁ = X _S / Y _S , q ₁ = (X _S ² + Y _S ² ) / 2Y _S )
Represented by
The position of the link connection point is expressed by the formula X _M = X ₁ + L ₁ cos {β-γ}) and Y _M = Y ₁ + L ₁ sin {β-γ}.
(However,
β = tan ⁻¹ {(Y ₁ −Y ₂ ) / (X ₁ −X ₂ )},
γ = cos ⁻¹ {(L ₁ ² −L ₂ ² + W ² ) / 2L ₁ W},
W = √ {(X ₁ −X ₂ ) ² + (Y ₁ −Y ₂ ) ² },
X _M : horizontal coordinate of the link connecting point,
Y _M : vertical coordinate of the link connecting point,
L ₁ : length from the axis of the drive roller shaft on the upper stage side to the link connection point;
L ₂ : Length from the axis of the drive roller shaft on the lower stage side to the link connection point)
Inclined part high-speed escalator characterized by being set by.

Main frame,
Provided in the main frame, an upper entrance / exit portion, a lower entrance / exit portion, an intermediate inclined portion located between the upper entrance / exit portion and the lower entrance / exit portion, the upper entrance / exit portion, and the above A drive rail that forms a circulation path that includes an upper curved portion located between the intermediate inclined portion and a lower curved portion located between the lower entrance / exit portion and the intermediate inclined portion;
Each has a driving roller shaft and a driving roller that is rotatable about the driving roller shaft and that is guided by the driving rail and rolls, and is connected endlessly and circulated along the circulation path. Multiple steps,
A first link rotatably connected to the drive roller shaft; a second link rotatably connected to a link connection point of the first link and a drive roller shaft of an adjacent step; A plurality of link mechanisms that change the distance between the drive roller shafts by performing bending and stretching operations,
A rotatable auxiliary roller provided in each of the link mechanisms, and provided in the main frame, guiding the movement of the auxiliary rollers to cause the link mechanism to bend and extend, and to change the moving speed of the steps to the upper transmission unit. Auxiliary rails that change with the lower transmission
The shaft center of the adjacent drive roller shaft is in the upper transmission unit, and the horizontal and vertical relative coordinates of the shaft center of the drive roller shaft are (X _S , Y _S ), and the drive in the upper curved portion The radius of curvature of the movement locus of the axis of the roller shaft is R ₁ , the inclination of the intermediate inclined portion is α _m , and the boundary between the upper entrance / exit portion of the movement locus of the axis of the drive roller shaft and the upper curve portion The range of Y _S is −X _S tan α _m ≦ Y _S <R ₁ cos α _m −√ {(R ₁ cos α _m ) ² + (2R ₁ ), with a point perpendicular to the point by −R ₁ as the origin of coordinates. sin α _m · X _S −X _S ² )}
When
The relative position of the adjacent drive roller in the upper transmission unit, the horizontal coordinate X _{1 of} the upper drive roller shaft axis, and the horizontal coordinate Y _{1 of the} upper drive roller shaft axis. The relationship between the horizontal coordinate X _{2 of} the axis of the lower drive roller shaft and the horizontal coordinate Y ₂ of the lower drive roller shaft is expressed by the equation X ₁ = [− p _2. s−√ {(p ₂ s) ² − (p ₂ ² +1) (s ² −R ² )}] / (p ₂ ² +1),
Y ₁ = √ (R ₁ ² −X ₁ ² ),
X ₂ = X ₁ + X _S and Y ₂ = Y ₁ + Y _S
(However, p ₂ = −tan α _m , q ₂ = R ₁ (cos α _m + sin α _m · tan α _m ), s = p ₂ X _S + q ₂ −Y _S )
Represented by
The position of the link connection point is expressed by the formula X _M = X ₁ + L ₁ cos {β-γ}) and Y _M = Y ₁ + L ₁ sin {β-γ}.
(However,
β = tan ⁻¹ {(Y ₁ −Y ₂ ) / (X ₁ −X ₂ )},
γ = cos ⁻¹ {(L ₁ ² −L ₂ ² + W ² ) / 2L ₁ W},
W = √ {(X ₁ −X ₂ ) ² + (Y ₁ −Y ₂ ) ² },
X _M : horizontal coordinate of the link connecting point,
Y _M : vertical coordinate of the link connecting point,
L ₁ : length from the axis of the drive roller shaft on the upper stage side to the link connection point;
L ₂ : Length from the axis of the drive roller shaft on the lower stage side to the link connection point)
Inclined part high-speed escalator characterized by being set by.

Main frame,
Provided in the main frame, an upper entrance / exit portion, a lower entrance / exit portion, an intermediate inclined portion located between the upper entrance / exit portion and the lower entrance / exit portion, the upper entrance / exit portion, and the above A drive rail that forms a circulation path that includes an upper curved portion located between the intermediate inclined portion and a lower curved portion located between the lower entrance / exit portion and the intermediate inclined portion;
Each has a driving roller shaft and a driving roller that is rotatable about the driving roller shaft and that is guided by the driving rail and rolls, and is connected endlessly and circulated along the circulation path. Multiple steps,
A first link rotatably connected to the drive roller shaft; a second link rotatably connected to a link connection point of the first link and a drive roller shaft of an adjacent step; A plurality of link mechanisms that change the distance between the drive roller shafts by performing bending and stretching operations,
A rotatable auxiliary roller provided in each of the link mechanisms, and provided in the main frame, guiding the movement of the auxiliary rollers to cause the link mechanism to bend and extend, and to change the moving speed of the steps to the upper transmission unit. Auxiliary rails that change with the lower transmission
The shaft center of the adjacent drive roller shaft is in the lower transmission portion, and the horizontal and vertical relative coordinates of the shaft center of the drive roller shaft are expressed as (X _S , Y _S ), The radius of curvature of the movement locus of the shaft center of the drive roller shaft is R ₂ , and the distance from the boundary between the lower entrance / exit portion and the lower curve portion of the movement locus of the shaft center of the drive roller shaft is R _{2 in the} vertical direction The range of Y _S is −R ₂ + √ (R ₂ ² −X _S ² ) ≦ Y _S <0
When
The relative position of the adjacent drive roller in the lower transmission unit, the horizontal coordinate X _{1 of} the axis of the upper drive roller shaft, and the horizontal coordinate Y of the upper drive roller shaft center Y _1. The relationship between the horizontal coordinate X ₂ of the shaft axis of the lower drive roller shaft and the horizontal coordinate Y ₂ of the drive roller shaft axis of the lower step is expressed by the equation X ₁ = −√ ( 2R ₂ · Y _S −Y _S ² ),
Y ₁ = −√ (R ₂ ² −X ₁ ² ),
X ₂ = X ₁ + X _S and Y ₂ = Y ₁ + Y _S
Represented by
The position of the link connection point is expressed by the formula X _M = X ₁ + L ₁ cos {β-γ}) and Y _M = Y ₁ + L ₁ sin {β-γ}.
(However,
β = tan ⁻¹ {(Y ₁ −Y ₂ ) / (X ₁ −X ₂ )},
γ = cos ⁻¹ {(L ₁ ² −L ₂ ² + W ² ) / 2L ₁ W},
W = √ {(X ₁ −X ₂ ) ² + (Y ₁ −Y ₂ ) ² },
X _M : horizontal coordinate of the link connecting point,
Y _M : vertical coordinate of the link connecting point,
L ₁ : length from the axis of the drive roller shaft on the upper stage side to the link connection point;
L ₂ : Length from the axis of the drive roller shaft on the lower stage side to the link connection point)
Inclined part high-speed escalator characterized by being set by.

Main frame,
Provided in the main frame, an upper entrance / exit portion, a lower entrance / exit portion, an intermediate inclined portion located between the upper entrance / exit portion and the lower entrance / exit portion, the upper entrance / exit portion, and the above A drive rail that forms a circulation path that includes an upper curved portion located between the intermediate inclined portion and a lower curved portion located between the lower entrance / exit portion and the intermediate inclined portion;
Each has a driving roller shaft and a driving roller that is rotatable about the driving roller shaft and that is guided by the driving rail and rolls, and is connected endlessly and circulated along the circulation path. Multiple steps,
A first link rotatably connected to the drive roller shaft; a second link rotatably connected to a link connection point of the first link and a drive roller shaft of an adjacent step; A plurality of link mechanisms that change the distance between the drive roller shafts by performing bending and stretching operations,
A rotatable auxiliary roller provided in each of the link mechanisms, and provided in the main frame, guiding the movement of the auxiliary rollers to cause the link mechanism to bend and extend, and to change the moving speed of the steps to the upper transmission unit. Auxiliary rails that change with the lower transmission
The shaft center of the adjacent drive roller shaft is in the lower transmission portion, and the horizontal and vertical relative coordinates of the shaft center of the drive roller shaft are (X _S , Y _S ), The radius of curvature of the movement locus of the axis of the drive roller shaft is R ₂ , the inclination of the intermediate inclined portion is α _m , the lower entrance / exit portion and the lower curve portion of the movement locus of the axis of the drive roller shaft as the origin of the coordinate point distant by _{R 2} in the vertical direction from the boundary point, the range of _{Y S} is _{_{_{R 2 cosα m -√ {(R}}} 2 cosα m) 2 + (2R 2 sinα m · X S -X S ² )} ≦ Y _S <−R ₂ + √ (R ₂ ² −X _S ² )
When
The relative position of the adjacent drive roller in the lower transmission unit, the horizontal coordinate X _{1 of} the axis of the upper drive roller shaft, and the horizontal coordinate Y of the upper drive roller shaft center Y _1. The relationship between the horizontal coordinate X ₂ of the shaft center of the lower drive roller shaft and the horizontal coordinate Y ₂ of the drive roller shaft shaft of the lower step is expressed by the equation X ₁ = [− p ₃ q ₃ −√ {(p ₃ q ₃ ) ² − (p ₃ ² +1) (q ₃ ² −R ₂ ² )}] / (p ₃ ² +1),
Y ₁ = −√ (R ₂ ² −X ₁ ² ),
X ₂ = X ₁ + X _S and Y ₂ = Y ₁ + Y _S
(However, p ₃ = X _S / Y _S , q ₃ = (X _S ² + Y _S ² ) / 2Y _S )
Represented by
The position of the link connection point is expressed by the formula X _M = X ₁ + L ₁ cos {β-γ}) and Y _M = Y ₁ + L ₁ sin {β-γ}.
(However,
β = tan ⁻¹ {(Y ₁ −Y ₂ ) / (X ₁ −X ₂ )},
γ = cos ⁻¹ {(L ₁ ² −L ₂ ² + W ² ) / 2L ₁ W},
W = √ {(X ₁ −X ₂ ) ² + (Y ₁ −Y ₂ ) ² },
X _M : horizontal coordinate of the link connecting point,
Y _M : vertical coordinate of the link connecting point,
L ₁ : length from the axis of the drive roller shaft on the upper stage side to the link connection point;
L ₂ : Length from the axis of the drive roller shaft on the lower stage side to the link connection point)
Inclined part high-speed escalator characterized by being set by.

Main frame,
Provided in the main frame, an upper entrance / exit portion, a lower entrance / exit portion, an intermediate inclined portion located between the upper entrance / exit portion and the lower entrance / exit portion, the upper entrance / exit portion, and the above A drive rail that forms a circulation path that includes an upper curved portion located between the intermediate inclined portion and a lower curved portion located between the lower entrance / exit portion and the intermediate inclined portion;
Each has a driving roller shaft and a driving roller that is rotatable about the driving roller shaft and that is guided by the driving rail and rolls, and is connected endlessly and circulated along the circulation path. Multiple steps,
A first link rotatably connected to the drive roller shaft; a second link rotatably connected to a link connection point of the first link and a drive roller shaft of an adjacent step; A plurality of link mechanisms that change the distance between the drive roller shafts by performing bending and stretching operations,
A rotatable auxiliary roller provided in each of the link mechanisms, and provided in the main frame, guiding the movement of the auxiliary rollers to cause the link mechanism to bend and extend, and to change the moving speed of the steps to the upper transmission unit. Auxiliary rails that change with the lower transmission
The shaft center of the adjacent drive roller shaft is in the lower transmission portion, and the horizontal and vertical relative coordinates of the shaft center of the drive roller shaft are (X _S , Y _S ), The radius of curvature of the movement locus of the shaft center of the drive roller shaft is R ₂ , the inclination of the intermediate inclined portion is α _m , the lower entrance / exit portion of the movement locus of the shaft center of the drive roller shaft, as the origin of the coordinate point distant by _{R 2} in the vertical direction from the boundary point, the range of _{Y S} is _{_{_{_{-X S tanα m ≦ Y S <}}}} R 2 cosα m -√ {(R 2 cosα m) 2 + (2R ₂ sin α _m · X _S −X _S ² )}
When
The relative position of the adjacent drive roller in the lower transmission unit, the horizontal coordinate X _{1 of} the upper drive roller shaft axis, and the horizontal coordinate Y of the upper drive roller shaft axis Y _1. The relationship between the horizontal coordinate X ₂ of the shaft center of the lower drive roller shaft and the horizontal coordinate Y ₂ of the drive roller shaft shaft of the lower step is expressed by the equation X ₁ = {− ( p ₄ q ₄ + p ₄ Y _S + X _s ) + √A ₁ } / (p ₄ ² +1),
A ₁ = (p ₄ q ₄ + p ₄ Y _S + X _S ) ² − (p ₄ ² +1) {(q ₄ + Y _s ) ² −R ₂ ² + X _S ² },
Y ₁ = p ₄ X ₁ + q ₄ ,
X ₂ = X ₁ + X _S and Y ₂ = Y ₁ + Y _S
(However, p ₄ = −tan α _m , q ₄ = −R ₂ (cos α _m + sin α _m · tan α _m ))
Represented by
The position of the link connection point is expressed by the formula X _M = X ₁ + L ₁ cos {β-γ}) and Y _M = Y ₁ + L ₁ sin {β-γ}.
(However,
β = tan ⁻¹ {(Y ₁ −Y ₂ ) / (X ₁ −X ₂ )},
γ = cos ⁻¹ {(L ₁ ² −L ₂ ² + W ² ) / 2L ₁ W},
W = √ {(X ₁ −X ₂ ) ² + (Y ₁ −Y ₂ ) ² },
X _M : horizontal coordinate of the link connecting point,
Y _M : vertical coordinate of the link connecting point,
L ₁ : length from the axis of the drive roller shaft on the upper stage side to the link connection point;
L ₂ : Length from the axis of the drive roller shaft on the lower stage side to the link connection point)
Inclined part high-speed escalator characterized by being set by.

A part of the first link has a bent shape. From the relative position of the adjacent drive roller, the position of the axis of the auxiliary roller is expressed by the formula X _N = X ₁ + V cos {β− γ-δ}, and Y _N = Y ₁ + Vsin {β-γ-δ}
(However,
V = √ (L ₁ ² + L ₃ ² −2L ₁ L ₃ cos θ),
δ = sin ⁻¹ (L ₃ sin θ / V),
X _N : horizontal coordinate of the axis of the auxiliary roller,
Y _N : vertical coordinate of the axis of the auxiliary roller,
L ₃ : length from the link connecting point to the axis of the auxiliary roller,
θ: set by the magnitude of the angle between the line connecting the axis of the drive roller shaft on the upper side and the link connecting point and the line connecting the axis of the auxiliary roller and the link connecting point) The inclined part high-speed escalator according to any one of claims 1 to 6, wherein the inclined part high-speed escalator is provided.