JP3406675B2 - Color matching method of paint - Google Patents
Color matching method of paintInfo
- Publication number
- JP3406675B2 JP3406675B2 JP05234694A JP5234694A JP3406675B2 JP 3406675 B2 JP3406675 B2 JP 3406675B2 JP 05234694 A JP05234694 A JP 05234694A JP 5234694 A JP5234694 A JP 5234694A JP 3406675 B2 JP3406675 B2 JP 3406675B2
- Authority
- JP
- Japan
- Prior art keywords
- paint
- sample
- color
- mixed
- raw material
- Prior art date
- Legal status (The legal status is an assumption and is not a legal conclusion. Google has not performed a legal analysis and makes no representation as to the accuracy of the status listed.)
- Expired - Fee Related
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- Spectrometry And Color Measurement (AREA)
Description
【0001】[0001]
【産業上の利用分野】この発明は、塗料の色合わせ方
法、すなわち、複数の原料塗料を混合して作成する混合
塗料で得られる塗膜の色が色見本の色と良く合う原料塗
料の配合を求める方法に関する。BACKGROUND OF THE INVENTION 1. Field of the Invention The present invention relates to a method for color matching paints, that is, blending raw material paints in which the color of a coating film obtained by a mixed paint prepared by mixing a plurality of raw material paints matches well with the color of a color sample. Regarding how to ask.
【0002】[0002]
【従来の技術】塗料の場合、普通、ユーザーが希望する
色(色見本の色)に丁度合う塗膜色の出せる塗料が在庫
されているわけではなく、普通、適当な複数の原料塗料
を見本の色に合う塗膜色となる配合で混合した混合塗料
を作成して出荷するようにしている。2. Description of the Related Art In the case of paints, there is usually no stock of paints that can produce a coating color that exactly matches the color desired by the user (color of a color sample). The mixed paint is mixed and mixed in such a way that the paint film color matches the color of the product and shipped.
【0003】この時、見本の色に合わせるために混合す
る原料塗料の適切な配合を予め求める(色を合わせる)
わけであるが、近年、コンピュータを利用した色合わせ
(コンピュータ・カラーマッチング)により原料塗料の
適切な配合を予め求める作業の合理化を図っている。従
来のコンピュータを利用した色合わせ方法の場合、複数
の原料塗料を混合して得られる混合塗料の塗膜の色を各
原料塗料ごとの基礎データに基づき算出した予測結果
と、平行して得る色見本の測色結果とを比較し、両結果
の差が所定範囲内に納まれば、この時の原料塗料の配合
が求める適切な配合であるとする。At this time, an appropriate composition of the raw material paint to be mixed to match the color of the sample is obtained in advance (color matching).
However, in recent years, efforts have been made to rationalize the work of previously obtaining an appropriate mixture of raw material paints by color matching using a computer (computer color matching). In the case of the conventional color matching method using a computer, the color of the paint film of the mixed paint obtained by mixing multiple raw material paints is obtained in parallel with the prediction result calculated based on the basic data for each raw material paint. If the difference between the results is within a predetermined range, it is determined that the raw material coating composition at this time is an appropriate composition required.
【0004】この場合、基礎データを得るために所定の
試料を作る。各原料塗料のみの塗膜を基材表面に形成し
た単独塗料試料と各原料塗料に白色塗料をそれぞれ混合
した各混合塗料の塗膜を基材表面に形成した混合塗料試
料(白混合塗料試料)をそれぞれ作成し、これら単独塗
料試料と白混合塗料試料とに基づき基礎データを得るよ
うにするのである。In this case, a predetermined sample is prepared to obtain basic data. A sample of a single paint in which a coating film of each raw material paint was formed on the surface of the base material, and a sample of mixed coating material in which the coating film of each mixed paint in which each raw material paint was mixed with each other was formed on the surface of the base material (white mixed paint sample) To obtain basic data on the basis of these individual paint samples and white mixed paint samples.
【0005】これらの塗料試料より得る基礎データは、
基材(通常は白色紙)込みの散乱係数と吸収係数とをそ
れぞれ得て、着色要因としての試料の散乱係数と吸収係
数とをそれぞれ独立した形で着色状態を求める演算(例
えばダンカンの式による演算)の中に取り入れるいわゆ
る2定数法を用いて混合塗料の塗膜の色の予測結果をコ
ンピュータ処理により得る。この予測結果と色見本の測
色結果との差が所定範囲内でない場合、原料塗料の配合
を変更し再び予測結果を得て比較する処理を繰り返し行
う。通常、処理を繰り返してゆくに従い両結果の差が縮
まり収束していく。また、ひとつの原料塗料の組み合わ
せに対する適切な配合が求まれば、塗料の組み合わせを
変え、同様にして、異なる原料塗料の組み合わせに対す
る適当な配合を求めることもよく行われている。The basic data obtained from these paint samples are:
A calculation that obtains the scattering coefficient and the absorption coefficient including the base material (usually white paper) and obtains the coloring state in an independent form for the scattering coefficient and the absorption coefficient of the sample as the coloring factors (for example, according to Duncan's formula) The prediction result of the color of the coating film of the mixed paint is obtained by computer processing by using the so-called two-constant method which is incorporated into the calculation. If the difference between this prediction result and the colorimetric measurement result of the color sample is not within the predetermined range, the process of changing the composition of the raw material coating material and obtaining the prediction result again and comparing them is repeated. Normally, as the process is repeated, the difference between the two results becomes smaller and converges. In addition, once an appropriate formulation for one combination of raw material paints is obtained, the combination of coating materials is changed, and similarly, an appropriate formulation for a combination of different raw material paints is often obtained.
【0006】しかしながら、従来、色見本の色によって
は計算を繰り返しても両結果の差が小さくならずに所定
範囲内に入らない場合がある。この場合、所定範囲に近
い予測結果のうちで適当そうな結果を選択し(必要に応
じては熟練者の勘で適当に調整を加えた上)、選択した
結果についての原料塗料の配合で混合して混合塗料を作
成することになるが、その混合塗料で塗膜を形成し、人
間の目や測色機器で色見本の色との比較をしてみると、
色の差が許容範囲を越えていることがしばしばあり、再
び熟練者の経験に頼って修正を行ったりするが、非常に
手間であるため、改善が望まれていた。However, conventionally, depending on the color of the color sample, even if the calculation is repeated, the difference between the two results may not be small and may not fall within the predetermined range. In this case, select a suitable result from the prediction results close to the predetermined range (if necessary, make appropriate adjustments with the intuition of a skilled person), and mix with the raw material paint for the selected result. Then, you will create a mixed paint, but when you form a coating film with the mixed paint and compare it with the color of the color sample with human eyes or colorimetric equipment,
The color difference often exceeds the permissible range, and correction is performed again depending on the experience of a skilled person, but it is very troublesome, and improvement has been desired.
【0007】[0007]
【発明が解決しようとする課題】この発明は、上記の事
情に鑑みて、原料塗料の的確な配合を迅速に得ることの
出来る塗料の色合わせ方法を提供することを課題とす
る。SUMMARY OF THE INVENTION In view of the above circumstances, it is an object of the present invention to provide a paint color matching method capable of quickly obtaining an accurate blending of raw material paints.
【0008】[0008]
【課題を解決するための手段】前記課題を解決するた
め、この発明の塗料の色合わせ方法は、複数の原料塗料
を混合して得られる混合塗料の塗膜の色を各原料塗料ご
との基礎データに基づき算出した予測結果と、色見本の
測色結果とを比較し、両結果の差が所定範囲内となる原
料塗料の配合を求めるにあたり、前記予測結果の算出
を、2定数法により行うとともに、前記測色結果と予測
結果との差が所定範囲内に入らない時には、1定数法に
変更して行うようにするか、あるいは、彩度が所定の範
囲にある色見本に対する色合わせでは、前記予測結果の
算出を1定数法により行うようにしている。In order to solve the above-mentioned problems, the paint color matching method of the present invention is based on the color of the coating film of a mixed paint obtained by mixing a plurality of raw paints as a basis for each raw paint. The prediction result calculated based on the data is compared with the colorimetric measurement result of the color sample, and the calculation of the prediction result is performed by the two-constant method in order to obtain the mixture of the raw material paints in which the difference between the results is within the predetermined range. At the same time, when the difference between the color measurement result and the prediction result does not fall within the predetermined range, the method is changed to the one-constant method, or the color matching is performed on the color sample whose saturation is within the predetermined range. The calculation of the prediction result is performed by the one-constant method.
【0009】以下、この発明の塗料の色合わせ方法を具
体的に説明する。この発明における塗料は、通常の膜形
成材に着色剤(顔料や染料など)を分散したものであ
り、インクのような基材の着色だけでなく、十分な厚み
(通常、10μm程度以上)の塗膜が形成できて、基材
の着色と同時に十分な保護が行えるものであり、具体的
には以下のようなものが例示される。アクリルラッカ
ー、硝化綿ラッカーエナメル、フェノール系樹脂ワニ
ス、フタル酸系樹脂ワニス、マレイン酸樹脂ワニス、尿
素系樹脂ワニス、ビニル系樹脂ワニス、エポキシ系樹脂
ワニス、ポリエステル系樹脂ワニス、フラン系樹脂ワニ
ス等のうちから選んだ膜成形材と、酸化チタン、カーボ
ンブラック、黄鉛などの無機顔料やフタロシアニン系顔
料、キナクリドン系顔料、アンスラキノン系顔料などの
有機顔料のうちから選んだ着色剤を主材料として、溶剤
や希釈剤などの副材料が必要に応じて添加混合されたも
のである。The color matching method of the paint of the present invention will be specifically described below. The coating material according to the present invention is a film-forming material in which a colorant (a pigment, a dye, etc.) is dispersed, and not only for coloring a base material such as ink, but also for a sufficient thickness (usually about 10 μm or more). A coating film can be formed, and the substrate can be colored and, at the same time, sufficient protection can be achieved. Specific examples include the following. Acrylic lacquer, nitrified cotton lacquer enamel, phenolic resin varnish, phthalic acid resin varnish, maleic acid resin varnish, urea resin varnish, vinyl resin varnish, epoxy resin varnish, polyester resin varnish, furan resin varnish, etc. With a film forming material selected from among them, titanium oxide, carbon black, inorganic pigments such as yellow lead and phthalocyanine pigments, quinacridone pigments, colorants selected from organic pigments such as anthraquinone pigments as the main material, Sub-materials such as a solvent and a diluent are added and mixed as needed.
【0010】先ず、試料の散乱と吸収とをそれぞれ独立
した形(ふたつのパラメータ)で着色状態を求める演算
の中に取り入れる2定数法用の基礎データや、試料の散
乱係数と吸収係数とを両者の比という形(ひとつのパラ
メータ)で着色状態を求める演算の中に取り入れる1定
数法用の基礎データは、各原料塗料について予め得てお
く必要がある。First, the basic data for the two-constant method, which incorporates the scattering and absorption of the sample into the calculation for obtaining the colored state in independent forms (two parameters), and the scattering coefficient and the absorption coefficient of the sample are both described. It is necessary to obtain in advance the basic data for the 1-constant method, which is incorporated in the calculation for obtaining the coloring state in the form of the ratio (one parameter), for each raw material paint.
【0011】前者の2定数法を適用する場合の基礎デー
タは、各原料塗料のみの塗膜を基材表面に形成した単独
塗料試料と各原料塗料に白色塗料をそれぞれ混合した各
混合塗料の塗膜を基材表面に形成した混合塗料試料(白
混合塗料試料)とに基づき得る。後者の1定数法を適用
する場合の基礎データは、各原料塗料のみの塗膜を基材
表面に形成した単独塗料試料と各原料塗料に無色透明塗
料をそれぞれ混合した各混合塗料の塗膜を基材表面に形
成した混合塗料試料(透明混合塗料試料)とに基づき得
る。The basic data in the case of applying the former two-constant method is as follows: a single paint sample in which a coating film of each raw material paint alone is formed on the surface of the base material and a mixed coating material in which each raw material paint is mixed with a white coating material. And a mixed paint sample (white mixed paint sample) with a film formed on the substrate surface. The basic data when applying the latter one-constant method are the single paint sample in which the coating film of each raw material paint is formed on the surface of the base material and the coating film of each mixed coating material in which each raw material paint is mixed with colorless transparent coating material. Based on the mixed paint sample (clear mixed paint sample) formed on the substrate surface.
【0012】これらの原料塗料の基礎データを得るため
には試料を先ず準備することになる。2定数法用の試料
としては、上記の単独塗料試料と白混合塗料試料をそれ
ぞれ揃える。この場合の白色塗料としては、酸化チタン
が普通使われる。基材は白色基材、例えば、紙が適当で
ある。より具体的には以下の通りのものを準備する。In order to obtain the basic data of these raw material coating materials, a sample is first prepared. As the samples for the 2-constant method, the above-mentioned single paint sample and the white mixed paint sample are prepared. Titanium oxide is usually used as the white paint in this case. Suitable substrates are white substrates such as paper. More specifically, the following items are prepared.
【0013】−2定数法用の試料例−
単独塗料試料:混合用の原料塗料単独で白色基材に厚み
10μmの塗膜形成した試料を各原料塗料毎に作成す
る。
白混合塗料試料A:重量比で原料塗料0.7と白色塗料
0.3を混合した白混合塗料で白色基材に例えば厚み1
0μmの塗膜形成した試料を各原料塗料毎に作成する。-Sample Example for Constant Method-Individual Paint Sample: A sample in which a raw material paint for mixing is used to form a coating film having a thickness of 10 μm on a white base material is prepared for each raw material paint. White mixed paint sample A: white mixed paint in which the raw material paint 0.7 and the white paint 0.3 are mixed in a weight ratio.
A sample having a film thickness of 0 μm is prepared for each raw material paint.
【0014】白混合塗料試料B:重量比で原料塗料0.
3と白色塗料0.7を混合した白混合塗料で白色基材に
例えば厚み10μmの塗膜形成した試料を各原料塗料毎
に作成する。
白混合塗料試料C:重量比で原料塗料0.1と白色塗料
0.9を混合した白混合塗料で白色基材に例えば厚み1
0μmの塗膜形成した試料を各原料塗料毎に作成する。White mixed paint sample B: Raw material paint in a weight ratio of 0.
A sample in which a coating film having a thickness of, for example, 10 μm is formed on a white base material with a white mixed paint obtained by mixing 3 and white paint 0.7 is prepared for each raw material paint. White mixed paint Sample C: White mixed paint in which the raw material paint 0.1 and the white paint 0.9 are mixed in a weight ratio.
A sample having a film thickness of 0 μm is prepared for each raw material paint.
【0015】白混合塗料試料D:重量比で原料塗料0.
05と白色塗料0.95を混合した白混合塗料で白色基
材に例えば厚み10μmの塗膜形成した試料を各原料塗
料毎に作成する。
白色塗料試料:白色塗料単独で白色基材に厚み10μm
の塗膜形成した試料を作成する。White mixed paint sample D: Raw material paint by weight ratio
A sample in which a coating film having a thickness of, for example, 10 μm is formed on a white base material with a white mixed paint in which 05 and white paint 0.95 are mixed is prepared for each raw material paint. White paint sample: White paint alone has a thickness of 10 μm on a white substrate.
A sample with a coating film formed is prepared.
【0016】1定数法用の塗料試料としては、各原料塗
料のみの塗膜を基材表面に形成した単独塗料試料と各原
料塗料に無色透明塗料(クリヤ塗料)をそれぞれ混合し
た各混合塗料の塗膜を基材表面に形成した混合塗料試料
(透明混合塗料試料)をそれぞれ揃える。なお、単独塗
料試料は2定数法用と1定数法用で同じ一つのものを共
通に使うことも出来る。無色透明塗料としては、ラッカ
ーエナメルが普通使われる。基材は白色基材、例えば、
紙が適当である。より具体的には以下の通りのものを準
備する。基礎データ測定用の塗料試料の場合、基材は白
色であることが望ましい理由は、白色でないと下地であ
る基材自体の色の影響を受けるからである。The paint samples for the 1 constant method include a single paint sample in which a coating film of only each raw material paint is formed on the surface of a base material, and a mixed paint composition in which a colorless transparent paint (clear paint) is mixed with each raw material paint. Align the mixed paint samples (transparent mixed paint samples) with the coating film formed on the substrate surface. The same single paint sample can be used for the two-constant method and the one-constant method. Lacquer enamel is commonly used as a colorless transparent paint. The substrate is a white substrate, for example,
Paper is suitable. More specifically, the following items are prepared. The reason why the base material is preferably white in the case of the paint sample for measuring the basic data is that if the base material is not white, the color is influenced by the color of the base material itself.
【0017】−1定数法用の試料例−
単独塗料試料:混合用の原料塗料(無色透明塗料は除
く)単独で白色基材に厚み10μmの塗膜形成した試料
を各原料塗料毎に作成する(上の2定数法用の単独塗料
試料を利用してもよい)。
透明混合塗料試料a:重量比で原料塗料0.5と無色透
明塗料0.5を混合した透明混合塗料で白色基材に例え
ば厚み10μmの塗膜形成した試料を各原料塗料毎に作
成する。-1 Sample Example for Constant Method-Single Paint Sample: Raw Material Paint for Mixing (Excluding Colorless Transparent Paint) A sample having a film thickness of 10 μm formed on a white base material is prepared for each raw material paint. (A single paint sample for the above two-constant method may also be used). Transparent mixed paint sample a: A sample in which a coating film having a thickness of, for example, 10 μm is formed on a white base material with a transparent mixed paint obtained by mixing the raw material paint 0.5 and the colorless transparent paint 0.5 in a weight ratio is prepared for each raw material paint.
【0018】透明混合塗料試料b:重量比で原料塗料
0.25と無色透明塗料0.75を混合した透明混合塗
料で白色基材に例えば厚み10μmの塗膜形成した試料
を各原料塗料毎に作成する。
透明混合塗料試料c:重量比で原料塗料0.1と無色透
明塗料0.9を混合した透明混合塗料で白色基材に例え
ば厚み10μmの塗膜形成した試料を各原料塗料毎に作
成する。Transparent mixed paint sample b: A sample prepared by coating a raw material paint 0.25 and a colorless transparent paint 0.75 in a weight ratio on a white base material to form a coating film having a thickness of 10 μm. create. Transparent mixed paint sample c: A sample having a film thickness of, for example, 10 μm formed on a white base material with a transparent mixed paint obtained by mixing the raw material paint 0.1 and the colorless transparent paint 0.9 in a weight ratio is prepared for each raw material paint.
【0019】透明混合塗料試料d:重量比で原料塗料
0.05と無色透明塗料0.95を混合した透明混合塗
料で白色基材に例えば厚み10μmの塗膜形成した試料
を各原料塗料毎に作成する。
次に、これらの基礎データ測定用の試料から基礎データ
を求める。基礎データを求めるには、先ず各試料の分光
反射率をそれぞれ測定する。この分光反射率の測定にあ
たっては、可視波長範囲(400〜700nm)におい
て離散的に16点、あるいは、32点の反射率を分光光
度計などで測定する。そして、分光光度計により得た分
光反射率にサンダーソン変換を施した分光反射率Rを用
い、下記の式(1)〜(3)に従って、2定数法用の試
料からは各波長点毎の試料の吸収係数および散乱係数を
求め、1定数法用の試料からは試料の吸収係数と散乱係
数の比を求め基礎データとするのである。吸収係数と散
乱係数の比は(1)式だけで求まる。得られた基礎デー
タは、コンピュータ用メモリに記憶させておく。Transparent mixed paint sample d: A sample in which a coating having a thickness of, for example, 10 μm was formed on a white base material with a transparent mixed paint prepared by mixing the raw material paint 0.05 and the colorless transparent paint 0.95 in a weight ratio for each raw material paint. create. Next, basic data is obtained from these samples for measuring basic data. To obtain the basic data, first, the spectral reflectance of each sample is measured. In measuring the spectral reflectance, the reflectance at 16 points or 32 points in the visible wavelength range (400 to 700 nm) is discretely measured with a spectrophotometer or the like. Then, using the spectral reflectance R obtained by subjecting the spectral reflectance obtained by the spectrophotometer to the Sanderson conversion, according to the following equations (1) to (3), from the sample for the two-constant method, The absorption coefficient and the scattering coefficient of the sample are calculated, and the ratio of the absorption coefficient and the scattering coefficient of the sample is calculated from the sample for the 1-constant method to be used as basic data. The ratio between the absorption coefficient and the scattering coefficient can be obtained only by the equation (1). The obtained basic data is stored in the computer memory.
【0020】[0020]
【数1】 [Equation 1]
【0021】R :サンダーソン変換の後の分光反射率
Kp :単独塗料試料の吸収係数
SP :単独塗料試料の散乱係数
(K/S) p:単独塗料試料のK/S値
(K/S) w+p:塗料試料A〜DそれぞれのK/S値
Cw :白色塗料の配合量
CP :混合用塗料の配合量
Cw +Cp =1(一定)とする
Kw :白色塗料試料の(K/S)w=Kw /Sw でSw =
1とした時の値
−予測結果の算出−
このようにして、基礎データを準備しておいて、つぎ
に、実際にコンピュータ処理により、混合塗料の塗膜の
色(塗膜色)の予測結果の算出を行う。R: Spectral reflectance after Sanderson conversion Kp: Absorption coefficient of single paint sample SP: Scattering coefficient of single paint sample (K / S) p: K / S value of single paint sample (K / S) w + p: K / S value of each of the paint samples A to D Cw: White paint blending amount CP: Mixing paint blending amount Cw + Cp = 1 (constant) Kw: White paint sample (K / S) w = Kw / Sw and Sw =
Value when 1 is set-Calculation of prediction result-In this way, the basic data is prepared, and then the result of prediction of the color of the coating film of the mixed paint (coating color) is actually performed by computer processing. Is calculated.
【0022】この発明では、2定数法と1定数法の二つ
の方法のいずれでも算出が行えるのであるが、着色要因
としての試料の散乱と吸収とをそれぞれ独立した形で着
色状態を求める演算の中に取り入れる2定数法による予
測結果の算出の方を先に説明する。混合に使う原料塗料
の組み合わせを決定する。混合は、通常、4種(塗料
1,塗料2,塗料3,塗料4)の原料塗料を使って行
う。In the present invention, the calculation can be performed by either of the two-constant method and the one-constant method. However, the calculation of the coloring state can be performed independently of the scattering and absorption of the sample as the coloring factors. The calculation of the prediction result by the two-constant method incorporated in the method will be described first. Determine the combination of raw material paints used for mixing. Mixing is usually performed using four types of raw material paints (paint 1, paint 2, paint 3, paint 4).
【0023】組み合わせる各塗料の基礎データである散
乱係数S1 〜S4 および吸収係数K 1 〜K4 と下記式
(4)とを用いて演算することにより混合塗料による塗
膜の着色状態(K/S)を求める。式(4)はダンカン
(Duncan)の式と呼ばれており、散乱係数と吸収係数とが
それぞれ独立した形で演算の中に取り込まれることが分
かる。勿論、着色状態(K/S)は、散乱係数データと
吸収係数データの取り込み波長点毎に求めるのであるか
ら、いわば分光着色状態を求めることになる。なお、C
1 〜C4 は各原料塗料の配合割合であり、C1 +C2 +
C3 +C4 =1という設定である。The basic data of each paint to be combined
Dispersion coefficient S1~ SFourAnd absorption coefficient K 1~ KFourAnd the following formula
(4) is calculated by using
The coloring state (K / S) of the film is determined. Formula (4) is Duncan
This is called the (Duncan) equation, and the scattering coefficient and absorption coefficient are
It is understood that each is incorporated in the calculation in an independent form.
Light Of course, the coloring state (K / S) is
Is absorption coefficient data acquired for each wavelength point?
In other words, the so-called spectral coloring state will be obtained. Note that C
1~ CFourIs the blending ratio of each raw material paint, and C1+ C2+
C3+ CFourThe setting is = 1.
【0024】[0024]
【数2】 [Equation 2]
【0025】求めた着色状態 (K/S)と分光反射率R
の間には下記の式(5),(6)の関係があり、この関
係を利用することにより、混合塗料の塗膜の分光反射率
Raを算出する。Obtained coloring state (K / S) and spectral reflectance R
There is a relationship expressed by the following equations (5) and (6), and the spectral reflectance Ra of the coating film of the mixed paint is calculated by using this relationship.
【0026】[0026]
【数3】 [Equation 3]
【0027】算出した分光反射率Rに対しサンダーソン
(Saunderson)の式による変換を行って(分光光度計から
得られた状態に相当する)分光反射率Raにしてから、
下記の式(7)〜(9)を用いて三刺激値(Xa,Y
a,Za)を算出することで混色後の塗膜色の予測結果
が得られる。For the calculated spectral reflectance R, Sanderson
(Saunderson) conversion is performed (corresponding to the state obtained from the spectrophotometer) to obtain the spectral reflectance Ra,
Using the following equations (7) to (9), the tristimulus values (Xa, Y
By calculating a, Za), the prediction result of the coating film color after color mixing can be obtained.
【0028】[0028]
【数4】 [Equation 4]
【0029】ここに、x(λ)ρ(λ),y(λ)ρ
(λ),z(λ)ρ(λ)は、CIEで定められている
数値である。
−色見本の測色結果の算出−
一方、色見本の分光反射率(サンダーソン変換をしない
状態)を分光光度計等の測色機器を用いて別途測定す
る。色見本の分光反射率は、可視波長範囲(400〜7
00nm)において基礎データの測定波長位置と同じ波
長位置で離散的に16点、あるいは、32点で得たもの
である。このようにして得た分光反射率を使って、上記
の式(7)〜(9)で三刺激値(Xs,Ys,Zs)を
算出することで測色結果を得る。Where x (λ) ρ (λ) and y (λ) ρ
(Λ) and z (λ) ρ (λ) are numerical values defined by CIE. -Calculation of Colorimetric Result of Color Swatch-On the other hand, the spectral reflectance of the color sample (in a state where Sanderson conversion is not performed) is separately measured using a colorimetric device such as a spectrophotometer. The spectral reflectance of the color sample is in the visible wavelength range (400 to 7
(00 nm) is obtained discretely at 16 points or 32 points at the same wavelength position as the measurement wavelength position of the basic data. By using the spectral reflectances thus obtained, the tristimulus values (Xs, Ys, Zs) are calculated by the above equations (7) to (9) to obtain a colorimetric result.
【0030】−予測結果と測色結果の比較演算−
上記で得た三刺激値(Xa,Ya,Za)と三刺激値
(Xs,Ys,Zs)の差(ΔX,ΔY,ΔZ)を出
し、さらに、これから下記の式(10) で示される色差を
求め、色差が所定値以下であれば、その時の原料塗料の
配合が求める結果である。色差が所定値以下でなけれ
ば、C1 〜C4 を変えて再び計算を繰り返す。比較結果
を左右する色差の所定値は、色や使用塗料によって多少
は異なるのであるが、普通、色差が0.1程度である。-Comparison operation of prediction result and colorimetric result-The difference (ΔX, ΔY, ΔZ) between the tristimulus values (Xa, Ya, Za) and the tristimulus values (Xs, Ys, Zs) obtained above is calculated. Further, from this, the color difference represented by the following formula (10) is obtained, and if the color difference is less than or equal to a predetermined value, the result is that the blending of the raw material coating material at that time is obtained. If the color difference is not less than the predetermined value, C 1 to C 4 are changed and the calculation is repeated again. Although the predetermined value of the color difference that influences the comparison result is slightly different depending on the color and the paint used, the color difference is usually about 0.1.
【0031】[0031]
【数5】 [Equation 5]
【0032】原料塗料の1つの組み合わせに対する処理
が終われば、原料塗料の組み合わせを変えて、同様の算
出処理を繰り返す。適当な原料塗料の配合は1つだけで
なく複数ある場合が普通である。最終的には最も適当と
判断される特定の1個の配合で原料塗料を混合して出荷
することになる。なお、三刺激値を求める際の分光反射
率は、いずれも、分光光度計から得たままのサンダーソ
ン変換をしない状態のものを用いたが、両者共にサンダ
ーソン変換をした状態のものを用いて三刺激値を求める
ようにしてもよい。When the processing for one combination of the raw material coating materials is completed, the combination of the raw material coating materials is changed and the same calculation processing is repeated. It is common that there is more than one suitable raw material coating formulation. Ultimately, the raw material paints will be mixed and shipped in one specific formulation that is judged to be the most appropriate. As for the spectral reflectance when obtaining the tristimulus values, the ones that were not subjected to the Sanderson conversion as they were obtained from the spectrophotometer were used, but both are the ones that are subjected to the Sanderson conversion. Alternatively, the tristimulus value may be obtained.
【0033】続いて、着色要因としての試料の散乱係数
と吸収係数とを両者の比という形で着色状態を求める演
算の中に取り入れる1定数法による予測結果の算出を説
明する。混合に使う塗料の組み合わせを決定する。1定
数法では、3種(塗料1,塗料2,塗料3)の原料塗料
と無色透明塗料(塗料4)を使って混合するのが普通で
ある。Next, the calculation of the prediction result by the one-constant method in which the scattering coefficient and the absorption coefficient of the sample as the coloring factor are incorporated in the calculation for obtaining the coloring state in the form of the ratio of the two will be described. Determine the combination of paints used for mixing. In the one-constant method, it is common to mix three kinds of raw material paints (paint 1, paint 2, paint 3) and colorless transparent paint (paint 4).
【0034】まず、混合する塗料の組み合わせを決め、
組み合わせる各塗料の基礎データ(散乱係数と吸収係数
の比(K1 /S1 )〜(K4 /S4 )と下記式(11)
を用いて演算することにより混合塗料による塗膜の着色
状態(K/S)を求める。式(11)はダンカン(Dunca
n)の式の変形式であり、この式(11)は、散乱係数が
下地の基材の散乱が優勢となり、各下地の基材は同じな
のでS1 〜S4 は、S 1 =S2 =S3 =S4 =SC とな
るからである。勿論、着色状態(K/S)は、基礎デー
タの取り込み波長点毎に求める。なお、塗料4は吸収が
殆どないので無視できるため、実際は、(K4 /S4 )
=(K4 /Sc )=0で不要となる。First, the combination of paints to be mixed is decided,
Basic data of each paint to be combined (scattering coefficient and absorption coefficient
Ratio of (K1/ S1) ~ (KFour/ SFour) And the following formula (11)
Coloring of coating film with mixed paint by calculating using
Determine the state (K / S). Equation (11) is Duncan
n) is a modification of the equation, and the equation (11) has a scattering coefficient
The scattering of the base material becomes dominant, and the base material of each base is the same.
So S1~ SFourIs S 1= S2= S3= SFour= SCTona
This is because that. Of course, the coloring status (K / S) is
Data is obtained for each wavelength point. The paint 4 is not absorbed
Since it is almost nonexistent, it can be ignored, so (KFour/ SFour)
= (KFour/ Sc) = 0, it becomes unnecessary.
【0035】[0035]
【数6】 [Equation 6]
【0036】求めた着色状態 (K/S)と分光反射率R
の間には上記の式(5),(6)の関係があり、この関
係を利用することにより、混合塗料の塗膜の分光反射率
Rbを算出する。以下、予測結果や測色結果の比較演算
などは上記の2定数法の場合と同じであるため、説明を
省略する。以上のように、この発明では、2定数法と1
定数法の二つの方法のいずれでも算出が行えるのである
が、普通、2定数法で先に算出を行い、予測結果と測色
結果の差が所定値以内に入ってこない(合わない)場
合、1定数法に変更して予測結果を算出する。Obtained coloring state (K / S) and spectral reflectance R
There is a relation of the above equations (5) and (6), and by utilizing this relation, the spectral reflectance Rb of the coating film of the mixed paint is calculated. Hereinafter, the comparison operation of the prediction result and the colorimetric result is the same as in the case of the above-mentioned two-constant method, and therefore the description is omitted. As described above, in the present invention, the 2-constant method and the 1
Although it is possible to calculate by either of the two methods of the constant method, normally, when the calculation is performed by the two-constant method first and the difference between the prediction result and the colorimetric result does not fall within the predetermined value (does not match), The prediction result is calculated by changing to the one-constant method.
【0037】しかし、色見本の色を観察して、彩度が明
らかに高い場合などは、直接、1定数法で算出を行って
もよい。この場合も、予測結果と測色結果が合わなけれ
ば、2定数法へ変更して予測結果を算出するようにして
もよい。1定数法と2定数法の間の切替えは人間が行っ
てもよいし、自動的に切り変わるようであってもよい。However, when the color of the color sample is observed and the saturation is obviously high, the calculation may be performed directly by the one-constant method. Also in this case, if the prediction result and the colorimetric result do not match, the two-constant method may be changed to calculate the prediction result. Switching between the one-constant method and the two-constant method may be performed by a human or may be automatically switched.
【0038】2定数法と1定数法の切り替えは、通常、
色差が5以下(ΔE≦5)にならない場合〔好ましくは
色差が3以下(ΔE≦3)にならない場合〕を、目安と
する。Switching between the two-constant method and the one-constant method is usually performed by
The case where the color difference does not become 5 or less (ΔE ≦ 5) [preferably the color difference does not become 3 or less (ΔE ≦ 3)] is used as a guide.
【0039】[0039]
【作用】この発明の場合、2定数法で適切な混合塗料の
塗膜色の予測結果が得られない場合や、色見本の色の観
察により1定数法に対する適性の高い場合は、1定数法
で的確な配合を迅速に得ることが出来る。その詳しい理
由は、以下の通りである。In the case of the present invention, the 1-constant method is used when the result of predicting the coating film color of an appropriate mixed paint cannot be obtained by the 2-constant method or when the suitability for the 1-constant method is high by observing the color of a color sample. Therefore, an accurate blend can be quickly obtained. The detailed reason is as follows.
【0040】従来の塗料の色合わせ方法で用いていた2
定数法では、塗料を混合する場合に隠蔽性をもたせるべ
く白色塗料を混合塗料の一つとすることが多いため、基
礎データを得る塗料試料を白色塗料を混合して形成し的
確な色合わせが出来るように配慮しているが、発明者ら
の検討の結果、ある場合には、この配慮が逆に作用して
いることもあることが分かったのである。つまり、色見
本が彩度が高く鮮明な色の場合には白色塗料を混合した
白濁塗膜を形成した試料から得た基礎データでは白濁が
災いして的確な色合わせが出来なかったのである。さら
に言うならば鮮明な色の場合と考慮する必要のない白色
塗料の添加による吸収に起因して狂った配合しか得られ
なかったのである。2 used in the conventional paint color matching method
In the constant method, white paint is often used as one of the mixed paints in order to have concealing properties when mixing paints, so basic paints that obtain basic data can be formed by mixing white paints for accurate color matching. However, as a result of the study by the inventors, in some cases, it was found that this consideration may have an opposite effect. In other words, when the color sample had a high saturation and a clear color, the basic data obtained from the sample in which the white turbid coating film was mixed with the white paint did not allow accurate color matching due to the cloudiness. Furthermore, it was only possible to obtain a wrong formulation due to absorption by the addition of the white paint, which does not need to be considered as the case of a vivid color.
【0041】そこで、発明者らは、基礎データを得る場
合に白色塗料でなく無色透明塗料を混合し白濁のない塗
料試料を形成し、鮮明な色に適合する基礎データを得て
用いることを思いつき試みたところ、白濁塗膜を用いる
2定数法では的確な結果が得られない鮮明色に対して直
ちに的確な色合わせが実現したのである。つまり、基礎
データを得る試料から必要のない白色塗料を除くことで
誤差を解消することができたのである。Therefore, when obtaining the basic data, the inventors have come up with the idea of mixing a colorless and transparent paint instead of a white paint to form a paint sample without white turbidity, obtaining basic data suitable for a clear color, and using it. As a result of trial, an accurate color matching was immediately realized for a vivid color that could not be obtained by the two-constant method using a cloudy coating film. In other words, the error could be eliminated by removing the unnecessary white paint from the sample for which the basic data was obtained.
【0042】そして、このような無色透明塗料(透明ラ
ッカー)を混合し白濁のないものでは、散乱の影響が基
材の散乱となり散乱係数を一定とみなすことが出来る。
つまり、前記の(4)式において、基材の散乱が優勢と
なり、各基材は同じなのでS 1 〜S4 は、S1 =S2 =
S3 =S4 =SC とすることが出来、この結果、上記
(4)式が下記(12)式からさらに(13)式とな
る。Then, such a colorless transparent paint (transparent paint)
If there is no cloudiness, the effect of scattering is
It becomes the scattering of the material and the scattering coefficient can be regarded as constant.
That is, in the equation (4), the scattering of the base material is dominant.
Since each base material is the same, S 1~ SFourIs S1= S2=
S3= SFour= SCAnd as a result of this, above
From equation (12) below, equation (4) is further transformed into equation (13).
It
【0043】[0043]
【数7】 [Equation 7]
【0044】ここで、C1 +C2 +C3 +C4 =1とい
う設定であるから、結果的に(11)式となることは直
ちに分かるであろう。すなわち、着色要因としての試料
の散乱係数と吸収係数とを両者の比というひとつのパラ
メータの形で着色状態を求める演算の中に取り入れてい
る1定数法の演算式となるのである。この結果、散乱係
数と吸収係数を独立して扱う必要もないから演算は比較
的簡単に行える。基礎データを得るのも、白濁のない透
明混合塗料試料を作成することになるが、白色塗料の代
わりに無色透明塗料を使うだけのことであり難しいこと
はない上、散乱係数と吸収係数の比を求めるだけだから
基礎データ自体を求めることが簡単であるため、追加負
荷は軽くてすむ。Here, since the setting is C 1 + C 2 + C 3 + C 4 = 1, it will be immediately apparent that the result is the equation (11). That is, it is an arithmetic expression of the one-constant method that is incorporated in the calculation for obtaining the coloring state in the form of one parameter of the ratio of the scattering coefficient and the absorption coefficient of the sample as the coloring factor. As a result, it is not necessary to handle the scattering coefficient and the absorption coefficient independently, so the calculation can be performed relatively easily. Obtaining the basic data also means preparing a transparent mixed paint sample without white turbidity, but it is not difficult because it uses only colorless transparent paint instead of white paint, and the ratio of scattering coefficient to absorption coefficient Since it is easy to obtain the basic data itself because it is simply required, the additional load is light.
【0045】[0045]
【実施例】続いて、この発明の実施例について説明す
る。この発明は下記の実施例に限らない。
−実施例1−
実施例1の場合、色見本の色はグリーン(DICカラー
ガイド番号DIC133)である。EXAMPLES Next, examples of the present invention will be described. This invention is not limited to the following embodiments. -Example 1-In the case of Example 1, the color of the color sample is green (DIC color guide number DIC133).
【0046】−2定数法用の塗料試料−
混合する原料塗料(以下に使用する塗料はすべて関西ペ
イント株式会社製である。)の組み合わせは下記のとお
りである。
塗料1・・・酸化チタン系アクリル塗料(白色塗料:オ
ートホワイト)
塗料2・・・シアニングリーン系アクリル塗料(緑色塗
料:ファーストグリーン)
塗料3・・・シアニンブルー系アクリル塗料(青色塗
料:ファーストブルー)
塗料4・・・黄鉛系アクリル塗料(黄色塗料:ライトイ
エロー)
単独塗料試料は塗料2〜4を各々、厚み10μmで白色
紙の塗膜形成した試料である。-2. Paint Sample for Constant Method-The combination of raw material paints to be mixed (all paints used below are manufactured by Kansai Paint Co., Ltd.) are as follows. Paint 1 ... Titanium oxide acrylic paint (white paint: Auto White) Paint 2 ... Cyanine green acrylic paint (Green paint: Fast Green) Paint 3 ... Cyanine blue acrylic paint (Blue paint: Fast Blue) ) Paint 4 ... Yellow lead-based acrylic paint (yellow paint: light yellow) The single paint samples are paints 2 to 4 each having a thickness of 10 μm and a white paper film formed thereon.
【0047】白混合塗料試料Aは塗料1〜4各々につ
き、重量比で原料塗料0.7と白色塗料0.3を混合し
た白混合塗料を白色紙に厚み10μmで塗膜形成した試
料である。白混合塗料試料Bは塗料1〜4各々につき、
重量比で原料塗料0.3と白色塗料0.7を混合した白
混合塗料を白色紙に厚み10μmで塗膜形成した試料で
ある。The white mixed paint sample A is a sample in which a white mixed paint in which the raw material paint 0.7 and the white paint 0.3 are mixed in a weight ratio for each of the paints 1 to 4 is applied to a white paper to form a film having a thickness of 10 μm. . White mixed paint sample B is for each of paints 1 to 4,
This is a sample in which a white mixed paint in which the raw material paint 0.3 and the white paint 0.7 are mixed in a weight ratio is formed on a white paper to have a thickness of 10 μm.
【0048】白混合塗料試料Cは塗料1〜4各々につ
き、重量比で原料塗料0.1と白色塗料0.9を混合し
た白混合塗料を白色紙に厚み10μmで塗膜形成した試
料である。白混合塗料試料Dは塗料1〜3各々につき、
重量比で原料塗料0.05と白色塗料0.95を混合し
た白混合塗料を白色紙に厚み10μmで塗膜形成した試
料である。The white mixed paint sample C is a sample in which a white mixed paint in which the raw material paint 0.1 and the white paint 0.9 are mixed in a weight ratio for each of the paints 1 to 4 is coated on white paper to a thickness of 10 μm. . White mixed paint sample D is for each of paints 1 to 3,
This is a sample in which a white mixed paint obtained by mixing the raw material paint 0.05 and the white paint 0.95 in a weight ratio was formed into a coating film on a white paper with a thickness of 10 μm.
【0049】白塗料試料は塗料1を白色紙に厚み10μ
mで塗膜形成した試料である。
−1定数法用の塗料試料−
混合する原料塗料の組み合わせは下記のとおりである。
塗料1・・・酸化チタン系アクリル塗料(白色塗料:オ
ートホワイト)
塗料2・・・シアニングリーン系アクリル塗料(緑色塗
料:ファーストグリーン)
塗料3・・・シアニンブルー系アクリル塗料(青色塗
料:ファーストブルー)
塗料4・・・アクリルラッカー(無色透明)
単独塗料試料は上の2定数法用の単独塗料試料を流用す
る。As a white paint sample, paint 1 was applied to white paper with a thickness of 10 μm.
It is a sample for which a coating film was formed by m. -1 Paint sample for the constant method-The combinations of raw material paints to be mixed are as follows. Paint 1 ... Titanium oxide acrylic paint (white paint: Auto White) Paint 2 ... Cyanine green acrylic paint (Green paint: Fast Green) Paint 3 ... Cyanine blue acrylic paint (Blue paint: Fast Blue) ) Paint 4 ... Acrylic lacquer (colorless and transparent) As the single paint sample, the single paint sample for the two constant method above is used.
【0050】透明混合塗料試料aは塗料1〜3各々につ
き、重量比で原料塗料0.5と無色透明塗料0.5を混
合した透明混合塗料を白色紙に厚み10μmで塗膜形成
した試料である。透明混合塗料試料bは塗料1〜3各々
につき、重量比で原料塗料0.25と無色透明塗料0.
75を混合した透明混合塗料を白色紙に厚み10μmで
塗膜形成した試料である。The transparent mixed paint sample a is a sample in which a transparent mixed paint in which the raw material paint 0.5 and the colorless transparent paint 0.5 are mixed in a weight ratio for each of paints 1 to 3 is formed on a white paper with a thickness of 10 μm. is there. The transparent mixed paint sample b is a raw material paint 0.25 and a colorless transparent paint 0.
It is a sample in which a transparent mixed paint containing 75 is coated on a white paper to form a film having a thickness of 10 μm.
【0051】透明混合塗料試料cは塗料1〜3各々につ
き、重量比で原料塗料0.1と無色透明塗料0.9を混
合した透明混合塗料を白色紙に厚み10μmで塗膜形成
した試料である。透明混合塗料試料dは塗料1〜3各々
につき、重量比で原料塗料0.05と無色透明塗料0.
95を混合した透明混合塗料を白色紙に厚み10μmで
塗膜形成した試料である。The transparent mixed paint sample c is a sample in which a transparent mixed paint in which the raw material paint 0.1 and the colorless transparent paint 0.9 are mixed in a weight ratio for each of paints 1 to 3 is coated on white paper to a thickness of 10 μm. is there. For the transparent mixed paint sample d, the raw material paint 0.05 and the colorless transparent paint 0.
This is a sample in which a transparent mixed paint containing 95 is coated on a white paper to form a film having a thickness of 10 μm.
【0052】2定数法で得られた配合結果Aは下記の通
りである。
塗料1・・0.706,塗料2・・0.294,塗料3
・・0,塗料4・・0
色差・・8.6
1定数法で得られた配合結果Bは下記の通りである。
塗料1・・0.004,塗料2・・0.276,塗料3
・・0.024,塗料4・・0.696
色差・・・0.1以下
なお、色見本の色相角は178.27°,彩度は52.
93,明度70.91である。The compounding result A obtained by the two-constant method is as follows. Paint 1 ... 0.706, Paint 2 ... 0.294, Paint 3
..0, paint 4 ... 0 color difference ... 8.6 The compounding result B obtained by the 1 constant method is as follows. Paint 1 ... 0.004, Paint 2 ... 0.276, Paint 3
··································· but.
It has a brightness of 93 and a brightness of 70.91.
【0053】一方、配合結果Aによる塗膜の色相角は1
77.20°,彩度は45.46,明度65.34であ
る。色見本との色差は9.36である。また、配合結果
Bによる塗膜の色相角は178.44°,彩度は54.
4,明度65.34である。色見本との色差は2.37
である。配合結果Aによる塗膜色,配合結果Bによる塗
膜色と色見本の色の一致度を5人のパネラーによりテス
トした。On the other hand, the hue angle of the coating film according to the blending result A is 1
77.20 °, saturation is 45.46, and brightness is 65.34. The color difference from the color sample is 9.36. Further, according to the blending result B, the hue angle of the coating film is 178.44 ° and the saturation is 54.
4, the brightness is 65.34. Color difference from the color sample is 2.37
Is. The degree of coincidence between the coating color according to the blending result A and the coating color according to the blending result B and the color of the color sample was tested by five panelists.
【0054】−実施例2−
実施例2の場合、色見本の色はグリーン(DICカラー
ガイド番号DIC176)である。
−2定数法用の塗料試料−
混合する原料塗料の組み合わせは下記のとおりである。-Example 2- In the case of Example 2, the color of the color sample is green (DIC color guide number DIC176). -2. Paint sample for constant method-The combination of raw material paints to be mixed is as follows.
【0055】塗料1・・・酸化チタン系アクリル塗料
(白色塗料:オートホワイト)
塗料2・・・シアニングリーン系アクリル塗料(緑色塗
料:ファーストグリーン)
塗料3・・・シアニンブルー系アクリル塗料(青色塗
料:ファーストブルー)
塗料4・・・黄鉛系アクリル塗料(黄色塗料:ライトイ
エロー)
実施例1に準じて単独塗料試料、白混合塗料試料および
白塗料試料を準備した。Paint 1 ... Titanium oxide acrylic paint (white paint: auto white) Paint 2 ... Cyanine green acrylic paint (green paint: fast green) Paint 3 ... Cyanine blue acrylic paint (blue paint) : Fast blue) Paint 4 ... Yellow lead-based acrylic paint (yellow paint: light yellow) In accordance with Example 1, a single paint sample, a white mixed paint sample and a white paint sample were prepared.
【0056】−1定数法用の塗料試料−
混合する原料塗料の組み合わせは下記のとおりである。
塗料1・・・酸化チタン系アクリル塗料(白色塗料:オ
ートホワイト)
塗料2・・・シアニングリーン系アクリル塗料(緑色塗
料:ファーストグリーン)
塗料3・・・シアニンブルー系アクリル塗料(青色塗
料:ファーストブルー)
塗料4・・・アクリルラッカー(無色透明)
実施例1に準じて単独塗料試料、および、透明混合塗料
試料を準備した。-1 Paint Sample for Constant Method-The combination of raw material paints to be mixed is as follows. Paint 1 ... Titanium oxide acrylic paint (white paint: Auto White) Paint 2 ... Cyanine green acrylic paint (Green paint: Fast Green) Paint 3 ... Cyanine blue acrylic paint (Blue paint: Fast Blue) ) Paint 4 ... Acrylic lacquer (colorless and transparent) A single paint sample and a transparent mixed paint sample were prepared according to Example 1.
【0057】2定数法で得られた配合結果Aは下記の通
りである。
塗料1・・0.581,塗料2・・0.361,塗料3
・・0.057,塗料4・・0
色差・・・14.2
1定数法で得られた配合結果Bは下記の通りである。
塗料1・・0,塗料2・・0.08,塗料3・・0.0
26,塗料4・・0.894
色差・・・0.1以下
なお、色見本の色相角は184.95°,彩度は56.
84,明度63.20である。The compounding result A obtained by the two-constant method is as follows. Paint 1 ... 0.581, Paint 2 ... 0.361, Paint 3
··· 0.057, paint 4 ··· 0, color difference ・ ・ ・ 14.2 The compounding result B obtained by the 1 constant method is as follows. Paint 1 ... 0, Paint 2 ... 0.08, Paint 3 ... 0.0
26, paint 4 ... 0.894 color difference ... 0.1 or less The hue angle of the color sample is 184.95 ° and the saturation is 56.
84 and brightness 63.20.
【0058】一方、配合結果Aによる塗膜の色相角は1
83.41°,彩度は45.88,明度58.58であ
る。色見本との色差は11.97である。また、配合結
果Bによる塗膜の色相角は185.59°,彩度は5
5.0,明度62.43である。色見本との色差は1.
67である。配合結果Aによる塗膜色,配合結果Bによ
る塗膜色と色見本の色の一致度を5人のパネラーにより
テストした。On the other hand, the hue angle of the coating film according to the blending result A is 1
It has 83.41 °, a saturation of 45.88 and a lightness of 58.58. The color difference from the color sample is 11.97. Further, according to the blending result B, the hue angle of the coating film is 185.59 ° and the saturation is 5
The value is 5.0 and the brightness is 62.43. The color difference from the color sample is 1.
67. The degree of coincidence between the coating color according to the blending result A and the coating color according to the blending result B and the color of the color sample was tested by five panelists.
【0059】−実施例3−
実施例3の場合、色見本の色はブルー(DICカラーガ
イド番号DIC179)である。
−2定数法用の塗料試料−
混合する原料塗料の組み合わせは下記のとおりである。-Example 3- In the case of Example 3, the color of the color sample is blue (DIC color guide number DIC179). -2. Paint sample for constant method-The combination of raw material paints to be mixed is as follows.
【0060】塗料1・・・酸化チタン系アクリル塗料
(白色塗料:オートホワイト)
塗料2・・・シアニンブルー系アクリル塗料(青色塗
料:ファーストブルー)
塗料3・・・黄鉛系アクリル塗料(黄色塗料:ライトイ
エロー)
塗料4・・・シアニングリーン系アクリル塗料(緑色塗
料:ファーストグリーン)
実施例1に準じて単独塗料試料、白混合塗料試料および
白塗料試料を準備した。Paint 1 ... Titanium oxide acrylic paint (white paint: auto white) Paint 2 ... Cyanine blue acrylic paint (blue paint: fast blue) Paint 3 ... Yellow lead acrylic paint (yellow paint) : Light yellow) Paint 4 ... Cyanine green acrylic paint (green paint: fast green) In accordance with Example 1, a single paint sample, a white mixed paint sample and a white paint sample were prepared.
【0061】−1定数法用の塗料試料−
混合する原料塗料の組み合わせは下記のとおりである。
塗料1・・・シアニンブルー系アクリル塗料(青色塗
料:ファーストブルー)
塗料2・・・酸化チタン系アクリル塗料(白色塗料:オ
ートホワイト)
塗料3・・・黄鉛系アクリル塗料(黄色塗料:ライトイ
エロー)
塗料4・・・アクリルラッカー(無色透明)
実施例1に準じて単独塗料試料、および、透明混合塗料
試料を準備した。-1 Paint Sample for Constant Method-The combination of raw material paints to be mixed is as follows. Paint 1 ... Cyanine blue acrylic paint (blue paint: fast blue) Paint 2 ... Titanium oxide acrylic paint (white paint: auto white) Paint 3 ... Yellow lead acrylic paint (yellow paint: light yellow) ) Paint 4 ... Acrylic lacquer (colorless and transparent) A single paint sample and a transparent mixed paint sample were prepared according to Example 1.
【0062】2定数法で得られた配合結果Aは下記の通
りである。
塗料1・・0.646,塗料2・・0.295,塗料3
・・0.059,塗料4・・0
色差・・・16.6
1定数法で得られた配合結果Bは下記の通りである。
塗料1・・0.25,塗料2・・0,塗料3・・0,塗
料4・・0.75
色差・・・0.1以下
なお、色見本の色相角は229.11°,彩度は50.
41,明度60.75である。The compounding result A obtained by the two-constant method is as follows. Paint 1 ... 0.646, Paint 2 ... 0.295, Paint 3
..0.059, paint 4 ... 0 color difference ... 16.6 The compounding result B obtained by the 1 constant method is as follows. Paint 1 ... 0.25, Paint 2 ... 0, Paint 3 ... 0, Paint 4 ... 0.75 Color difference ... 0.1 or less The hue angle of the color sample is 229.11 °, saturation Is 50.
41 and a brightness of 60.75.
【0063】一方、配合結果Aによる塗膜の色相角は2
25.36°,彩度は35.93,明度49.55であ
る。色見本との色差は18.51である。また、配合結
果Bによる塗膜の色相角は232.86°,彩度は4
8.27,明度58.04である。色見本との色差は
4.73である。配合結果Aによる塗膜色,配合結果B
による塗膜色と色見本の色の一致度を5人のパネラーに
よりテストした。On the other hand, the hue angle of the coating film according to the blending result A is 2
25.36 °, saturation is 35.93, and brightness is 49.55. The color difference from the color sample is 18.51. Further, according to the blending result B, the hue angle of the coating film is 232.86 ° and the saturation is 4
The brightness is 8.27 and the brightness is 58.04. The color difference from the color sample is 4.73. Coating color according to blending result A, blending result B
The color matching of the paint film and the color of the color swatch according to the present invention was tested by five panelists.
【0064】−実施例4−
実施例4の場合、色見本の色はブルー(DICカラーガ
イド番号DIC649)である。
−2定数法用の塗料試料−
混合する原料塗料の組み合わせは下記のとおりである。-Example 4- In the case of Example 4, the color of the color sample is blue (DIC color guide number DIC649). -2. Paint sample for constant method-The combination of raw material paints to be mixed is as follows.
【0065】塗料1・・・酸化チタン系アクリル塗料
(白色塗料:オートホワイト)
塗料2・・・シアニングリーン系アクリル塗料(緑色塗
料:ファーストグリーン)
塗料3・・・シアニングリーン系アクリル塗料(緑色塗
料:ディープグリーン)
塗料4・・・黄鉛系アクリル塗料(黄色塗料:ライトイ
エロー)
実施例1に準じて単独塗料試料、白混合塗料試料および
白塗料試料を準備した。Paint 1 ... Titanium oxide acrylic paint (white paint: auto white) Paint 2 ... Cyanine green acrylic paint (green paint: fast green) Paint 3 ... Cyanine green acrylic paint (green paint) : Deep green) Paint 4 ... Yellow lead-based acrylic paint (yellow paint: light yellow) In accordance with Example 1, a single paint sample, a white mixed paint sample and a white paint sample were prepared.
【0066】−1定数法用の塗料試料−
混合する原料塗料の組み合わせは下記のとおりである。
塗料1・・・シアニングリーン系アクリル塗料(緑色塗
料:ファーストグリーン)
塗料2・・・シアニンブルー系アクリル塗料(青色塗
料:ファーストブルー)
塗料3・・・黄鉛系アクリル塗料(黄色塗料:ライトイ
エロー)
塗料4・・・アクリルラッカー(無色透明)
実施例1に準じて単独塗料試料、および、透明混合塗料
試料を準備した。-1 Paint Samples for Constant Method-The combinations of raw material paints to be mixed are as follows. Paint 1 ... Cyanine green acrylic paint (green paint: fast green) Paint 2 ... Cyanine blue acrylic paint (blue paint: fast blue) Paint 3 ... Yellow lead acrylic paint (yellow paint: light yellow) ) Paint 4 ... Acrylic lacquer (colorless and transparent) A single paint sample and a transparent mixed paint sample were prepared according to Example 1.
【0067】2定数法で得られた配合結果Aは下記の通
りである。
塗料1・・0.467,塗料2・・0.418,塗料3
・・0.115,塗料4・・0
色差・・・18.2
1定数法で得られた配合結果Bは下記の通りである。
塗料1・・0.208,塗料2・・0.008,塗料3
・・0.002,塗料4・・0.782
色差・・・0.1以下
なお、色見本の色相角は172.15°,彩度は65.
28,明度62.16である。The compounding result A obtained by the two-constant method is as follows. Paint 1 ... 0.467, Paint 2 ... 0.418, Paint 3
····························································. Paint 1 ... 0.208, Paint 2 ... 0.008, Paint 3
..0.002, paint 4..0.782 color difference ... 0.1 or less The hue angle of the color sample is 172.15 °, and the saturation is 65.
28 and a brightness of 62.16.
【0068】一方、配合結果Aによる塗膜の色相角は1
72.49°,彩度は48.18,明度56.48であ
る。色見本との色差は18.02である。また、配合結
果Bによる塗膜の色相角は173.96°,彩度は5
9.91,明度64.03である。色見本との色差は
6.02である。配合結果Aによる塗膜色,配合結果B
による塗膜色と色見本の色の一致度を5人のパネラーに
よりテストした。On the other hand, the hue angle of the coating film according to the blending result A is 1
72.49 °, saturation is 48.18, and lightness is 56.48. The color difference from the color sample is 18.02. Further, according to the blending result B, the hue angle of the coating film is 173.96 ° and the saturation is 5
It has a brightness of 9.91 and a brightness of 64.03. The color difference from the color sample is 6.02. Coating color according to blending result A, blending result B
The color matching of the paint film and the color of the color swatch according to the present invention was tested by five panelists.
【0069】−実施例5−
実施例5の場合、色見本の色はブルー(DICカラーガ
イド番号DIC135)である。
−2定数法用の塗料試料−
混合する原料塗料の組み合わせは下記のとおりである。Example 5 In the case of Example 5, the color of the color sample is blue (DIC color guide number DIC135). -2. Paint sample for constant method-The combination of raw material paints to be mixed is as follows.
【0070】塗料1・・・酸化チタン系アクリル塗料
(白色塗料:オートホワイト)
塗料2・・・シアニングリーン系アクリル塗料(緑色塗
料:ファーストグリーン)
塗料3・・・シアニンブルー系アクリル塗料(青色塗
料:ファーストブルー)
塗料4・・・黄鉛系アクリル塗料(黄色塗料:ライトイ
エロー)
実施例1に準じて単独塗料試料、白混合塗料試料および
白塗料試料を準備した。Paint 1 ... Titanium oxide acrylic paint (white paint: auto white) Paint 2 ... Cyanine green acrylic paint (green paint: first green) Paint 3 ... Cyanine blue acrylic paint (blue paint) : Fast blue) Paint 4 ... Yellow lead-based acrylic paint (yellow paint: light yellow) In accordance with Example 1, a single paint sample, a white mixed paint sample and a white paint sample were prepared.
【0071】−1定数法用の塗料試料−
混合する原料塗料の組み合わせは下記のとおりである。
塗料1・・・シアニングリーン系アクリル塗料(緑色塗
料:ファーストグリーン)
塗料2・・・シアニンブルー系アクリル塗料(青色塗
料:ファーストブルー)
塗料3・・・黄鉛系アクリル塗料(黄色塗料:ライトイ
エロー)
塗料4・・・アクリルラッカー(無色透明)
実施例1に準じて単独塗料試料、および、透明混合塗料
試料を準備した。-1 Paint Sample for Constant Method-The combination of raw material paints to be mixed is as follows. Paint 1 ... Cyanine green acrylic paint (green paint: fast green) Paint 2 ... Cyanine blue acrylic paint (blue paint: fast blue) Paint 3 ... Yellow lead acrylic paint (yellow paint: light yellow) ) Paint 4 ... Acrylic lacquer (colorless and transparent) A single paint sample and a transparent mixed paint sample were prepared according to Example 1.
【0072】2定数法で得られた配合結果Aは下記の通
りである。
塗料1・・0.723,塗料2・・0.194,塗料3
・・0.083,塗料4・・0
色差・・・12.6
1定数法で得られた配合結果Bは下記の通りである。
塗料1・・0.156,塗料2・・0.144,塗料3
・・0,塗料4・・0.700
色差・・・0.1以下
なお、色見本の色相角は196.18°,彩度は50.
09,明度66.05である。The compounding result A obtained by the two-constant method is as follows. Paint 1 ... 0.723, Paint 2 ... 0.194, Paint 3
···································· 4 0.4 color difference ... Paint 1 ... 0.156, Paint 2 ... 0.144, Paint 3
・ ・ 0 、 Paint 4 ・ ・ 0.700 Color difference ・ ・ ・ 0.1 or less In addition, the hue angle of the color sample is 196.18 ° and the saturation is 50.
09 and the brightness is 66.05.
【0073】一方、配合結果Aによる塗膜の色相角は1
94.92°,彩度は40.41,明度61.31であ
る。色見本との色差は10.82である。また、配合結
果Bによる塗膜の色相角は199.5°,彩度は46.
83,明度64.96である。色見本との色差は4.4
4である。なお、上記の各実施例で使用した塗料1〜4
は、いずれも関西ペイント社製である。On the other hand, the hue angle of the coating film according to the blending result A is 1
It is 94.92 °, the saturation is 40.41 and the lightness is 61.31. The color difference from the color sample is 10.82. Further, according to the blending result B, the hue angle of the coating film is 199.5 ° and the saturation is 46.
83 and brightness 64.96. The color difference from the color sample is 4.4
It is 4. The paints 1 to 4 used in each of the above examples
Are manufactured by Kansai Paint Co., Ltd.
【0074】実施例における配合結果Aによる塗膜色と
配合結果Bによる塗膜色それぞれと色見本の色の一致度
を5人のパネラーによりテストした。
パネラーA パネラーB パネラーC パネラーD パネラーE
実施例1配合A (×) (×) (×) (×) (×)
実施例1配合B (○) (○) (○) (○) (○)
実施例2配合A (×) (×) (×) (×) (×)
実施例2配合B (○) (○) (○) (○) (○)
実施例3配合A (×) (×) (×) (×) (×)
実施例3配合B (○) (○) (○) (○) (○)
実施例4配合A (×) (×) (×) (×) (×)
実施例4配合B (○) (○) (○) (○) (○)
実施例5配合A (×) (×) (×) (×) (×)
実施例5配合B (○) (○) (○) (○) (○)
上記のテスト結果にみるように、鮮明色では1定数法に
よる算出が効果的であることが分かる。The degree of coincidence between the coating color according to the blending result A and the coating color according to the blending result B in the examples and the color of the color sample was tested by five panelists. Panelist A Panelist B Paneler C Paneler D Paneler E Example 1 formulation A (x) (x) (x) (x) (x) Example 1 formulation B (○) (○) (○) (○) (○) Example 2 formulation A (x) (x) (x) (x) (x) Example 2 formulation B (O) (O) (O) (O) (O) Example 3 formulation A (X) (X) ) (X) (X) (X) Example 3 formulation B (O) (O) (O) (O) (O) Example 4 formulation A (X) (X) (X) (X) (X) Example 4 Formulation B (○) (○) (○) (○) (○) Example 5 Formulation A (x) (x) (x) (x) (x) Example 5 Formulation B (○) (○) ) (○) (○) (○) As can be seen from the above test results, it is found that the calculation by the 1-constant method is effective for vivid colors.
【0075】[0075]
【発明の効果】この発明によれば、2定数法で適切な混
合塗料の塗膜色の予測結果が得られない場合や、色見本
の色の観察により1定数法に対する適性のある場合は、
1定数法による適切な原料塗料の配合を求めることが出
来るため、色見本の色によく合う適切な原料塗料の配合
を迅速に得られるようになるため、この発明は、非常に
有用である。According to the present invention, when the two-constant method cannot obtain an appropriate prediction result of the coating color of the mixed paint or when the color of the color sample is suitable for the one-constant method,
The present invention is very useful because an appropriate raw material coating composition can be obtained by the 1-constant method, and an appropriate raw material coating composition that matches the color of the color sample can be quickly obtained.
フロントページの続き (56)参考文献 特開 平2−200862(JP,A) (58)調査した分野(Int.Cl.7,DB名) G01J 3/46 - 3/52 D06P 5/00 B44D 3/00 C09D 7/14 G06F 17/50 Continuation of front page (56) Reference JP-A-2-200862 (JP, A) (58) Fields investigated (Int.Cl. 7 , DB name) G01J 3/46-3/52 D06P 5/00 B44D 3 / 00 C09D 7/14 G06F 17/50
Claims (3)
料の塗膜の色を各原料塗料ごとの基礎データに基づき算
出した予測結果と、色見本の測色結果とを比較し、両結
果の差が所定範囲内となる原料塗料の配合を求める色合
わせ方法において、前記予測結果の算出を、2定数法に
より行うとともに、前記測色結果と予測結果との差が所
定範囲内に入らない時には、1定数法に変更して行う塗
料の色合わせ方法であって、 前記 2定数法を適用する場合の基礎データは、各原料塗
料のみの塗膜を基材表面に形成した単独塗料試料と各原
料塗料に白色塗料をそれぞれ混合した各混合塗料の塗膜
を基材表面に形成した混合塗料試料とに基づき得るよう
にし、1定数法を適用する場合の基礎データは、各原料
塗料のみの塗膜を基材表面に形成した単独塗料試料と各
原料塗料に無色透明塗料をそれぞれ混合した各混合塗料
の塗膜を基材表面に形成した混合塗料試料とに基づき得
るようにすることを特徴とする塗料の色合わせ方法。1. A mixed coating obtained by mixing a plurality of raw material coating materials.
The color of the paint film is calculated based on the basic data for each raw material paint.
Compare the predicted result and the color measurement result of the color sample,
Color to obtain a blend of raw material paint so that the difference in fruit is within the specified range
In the combination method, the calculation of the prediction result is performed by the two-constant method.
And the difference between the color measurement result and the prediction result.
If it does not fall within the fixed range, change to the 1 constant method
A charge of color matching method, the basic data in the case of applying the 2 constant method, white paint was mixed respectively singly paint sample and the raw materials coating the coating film of each raw material paint only was formed on the substrate surface The basic data when the 1 constant method is applied so that the coating film of each mixed paint is obtained based on the mixed paint sample formed on the surface of the base material is A color matching method for paints, characterized in that a paint sample and a paint film of each mixed paint obtained by mixing each of the raw material paints with a colorless transparent paint are obtained based on the mixed paint sample formed on the surface of the base material.
料の塗膜の色を各原料塗料ごとの基礎データに基づき算
出した予測結果と、色見本の測色結果とを比較し、両結
果の差が所定範囲内となる原料塗料の配合を求める色合
わせ方法において、彩度の高い色見本に対する色合わせ
方法では、前記予測結果の算出を、1定数法により行う
ことを特徴とする塗料の色合わせ方法。2. A prediction result of calculating the color of a coating film of a mixed paint obtained by mixing a plurality of raw material paints based on basic data for each raw material paint and a colorimetric measurement result of a color sample, and comparing both In a color matching method for obtaining a mixture of raw material paints in which a difference in results is within a predetermined range, in the color matching method for a color sample having high saturation, the prediction result is calculated by a one-constant method. Color matching method.
各原料塗料のみの塗膜を基材表面に形成した単独塗料試
料と各原料塗料に無色透明塗料をそれぞれ混合した各混
合塗料の塗膜を基材表面に形成した混合塗料試料とに基
づき得るようにする請求項2記載の塗料の色合わせ方
法。3. Basic data when applying the 1-constant method is
Based on a single paint sample in which a coating film of each raw material paint was formed on the surface of the base material and a mixed coating material sample in which the coating film of each mixed paint obtained by mixing each raw material paint with a colorless transparent coating material was formed on the base material surface The method of color matching paint according to claim 2 .
Priority Applications (1)
Application Number | Priority Date | Filing Date | Title |
---|---|---|---|
JP05234694A JP3406675B2 (en) | 1994-03-23 | 1994-03-23 | Color matching method of paint |
Applications Claiming Priority (1)
Application Number | Priority Date | Filing Date | Title |
---|---|---|---|
JP05234694A JP3406675B2 (en) | 1994-03-23 | 1994-03-23 | Color matching method of paint |
Publications (2)
Publication Number | Publication Date |
---|---|
JPH07260576A JPH07260576A (en) | 1995-10-13 |
JP3406675B2 true JP3406675B2 (en) | 2003-05-12 |
Family
ID=12912257
Family Applications (1)
Application Number | Title | Priority Date | Filing Date |
---|---|---|---|
JP05234694A Expired - Fee Related JP3406675B2 (en) | 1994-03-23 | 1994-03-23 | Color matching method of paint |
Country Status (1)
Country | Link |
---|---|
JP (1) | JP3406675B2 (en) |
Families Citing this family (3)
Publication number | Priority date | Publication date | Assignee | Title |
---|---|---|---|---|
JPH09229773A (en) * | 1996-02-22 | 1997-09-05 | Toto Ltd | Computerized color matching method |
JP5818471B2 (en) * | 2011-03-15 | 2015-11-18 | 関西ペイント株式会社 | Arithmetic system, arithmetic method, and arithmetic device |
JP7289398B1 (en) * | 2022-10-21 | 2023-06-09 | 大日精化工業株式会社 | Absorption-scattering ratio derivation device, method, program, recording medium |
-
1994
- 1994-03-23 JP JP05234694A patent/JP3406675B2/en not_active Expired - Fee Related
Also Published As
Publication number | Publication date |
---|---|
JPH07260576A (en) | 1995-10-13 |
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