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CN101741448A - Information transmission method based on minimum mean square error beamforming in bidirectional channel - Google Patents

Information transmission method based on minimum mean square error beamforming in bidirectional channel Download PDF

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CN101741448A
CN101741448A CN200910219342A CN200910219342A CN101741448A CN 101741448 A CN101741448 A CN 101741448A CN 200910219342 A CN200910219342 A CN 200910219342A CN 200910219342 A CN200910219342 A CN 200910219342A CN 101741448 A CN101741448 A CN 101741448A
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李颖
李海强
孙岳
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Xidian University
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Xidian University
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Abstract

The invention discloses a minimum mean square error beam forming-based information transmission method in a two-way channel, belongs to the technical field of wireless communication, and mainly solves the problem of high technical complexity of the prior art. Particularly, the invention provides the information transmission method capable of improving channel capacity and error ratio performance, and reducing complexity at the same time by aiming at a wireless communication network of two source nodes and a relay node. The method comprises the following steps that: the two source nodes simultaneously send encoding information to the relay node; the relay node builds a beam forming matrix according to a minimum mean square error rule; the relay node carries out beam forming processing on the received source node mixed information, and then broadcasts the source node mixed information after the beam forming processing to the source nodes; and the source nodes are decoded to acquire information of other parts. The method reduces the complexity and ensures the correctness of transmission without great influence on system performance, and can be used for reliable information transmission in a two-way relay system.

Description

双向信道中基于最小均方误差波束成型的信息传输方法 Information transmission method based on minimum mean square error beamforming in bidirectional channel

技术领域technical field

本发明属于无线通信技术领域,涉及网络编码和波束成型,具体地说是针对两个源节点和一个中继节点的无线通信网络,可用于改善信道容量和误比特率性能。The invention belongs to the technical field of wireless communication, and relates to network coding and beam forming, in particular to a wireless communication network of two source nodes and a relay node, which can be used to improve channel capacity and bit error rate performance.

背景技术Background technique

利用中继帮助移动用户转发数据,可获得额外的分集增益,改善接收端的误比特BER性能,是提高移动用户在小区边缘通话质量的有效手段之一。针对图1所示的无线双向中继信道,两个源节点通过一个中继节点交换信息时,通常需要四个时隙,即两个源节点分别占用一个时隙与中继节点进行通信,中继节点占用两个时隙,分别为两个源节点转发数据。Using relays to help mobile users forward data can obtain additional diversity gain and improve the bit error BER performance of the receiving end. It is one of the effective means to improve the call quality of mobile users at the edge of the cell. For the wireless two-way relay channel shown in Figure 1, when two source nodes exchange information through a relay node, four time slots are usually required, that is, two source nodes respectively occupy one time slot to communicate with the relay node. The relay node occupies two time slots and forwards data for the two source nodes respectively.

网络编码作为现代通信网络中的一种设计方案允许网络节点把多条链路接收到的信号进行一定的线性或非线性编码后转发,减少了数据包的传输次数,提高了网络吞吐量,增强网络的容错性和鲁棒性,为提高双向中继信道的传输效率提供了一个有效的方法。特别是在无线网络中,由于其在无线传输中的广播特性使其能更好的利用网络编码,更有效的解决了无线网络中的干扰问题。As a design scheme in modern communication networks, network coding allows network nodes to perform certain linear or non-linear coding on signals received by multiple links before forwarding, reducing the number of data packet transmissions, improving network throughput, and enhancing The fault tolerance and robustness of the network provide an effective method for improving the transmission efficiency of the two-way relay channel. Especially in wireless networks, due to its broadcast characteristics in wireless transmission, it can make better use of network coding, and more effectively solve the interference problem in wireless networks.

通常交换一次信息需要四个时隙,在中继节点通过利用网络编码我们可以在三个时隙内完成一次交换,其基本原理是将两个源节点分别占用一个时隙与中继节点进行通信,然后由中继节点将译码得到两个源节点的数据信息进行模2运算后重新编码转发,需要三个时隙就可以交换一个数据包,利用基于模拟网络编码ANC的TWRC可以在两个时隙内完成这一过程,源节点同时向中继发送信息,然后在中继进行放大转发操作,从而实现了两个源节点之间信息的交换。Usually, four time slots are required to exchange information. By using network coding at the relay node, we can complete an exchange within three time slots. The basic principle is that two source nodes occupy one time slot respectively to communicate with the relay node. , and then the relay node will decode and obtain the data information of the two source nodes, perform modulo 2 operation, and then re-encode and forward. It takes three time slots to exchange a data packet. Using TWRC based on analog network coding ANC can be used in two This process is completed within the time slot, the source node sends information to the relay at the same time, and then the relay performs amplification and forwarding operations, thus realizing the exchange of information between the two source nodes.

无线通信网络中的波束成型方法根据衰落信道状态设计波束成型矩阵,利用波束成型矩阵对发送信号进行预处理消除信道间干扰,提高多径衰落信道中的传输性能,双向中继信道的容量最优波束成型方法不同于传统网络中的设计,均是基于系统的容量限问题设计出波束成型矩阵,现有的最优波束成型方法虽然可以在满足系统容量的同时消除干扰,但却存在复杂度较高的问题,而次优波束成型方法虽然降低了复杂度但是误码率性能较差,给传输过程中带来较多的错误比特,影响传输的正确性。The beamforming method in the wireless communication network designs the beamforming matrix according to the state of the fading channel, and uses the beamforming matrix to preprocess the transmitted signal to eliminate inter-channel interference, improve the transmission performance in the multipath fading channel, and the capacity of the two-way relay channel is optimal The beamforming method is different from the design in the traditional network. The beamforming matrix is designed based on the capacity limit of the system. Although the existing optimal beamforming method can meet the system capacity and eliminate the interference at the same time, it is more complicated. However, although the sub-optimal beamforming method reduces the complexity, the bit error rate performance is poor, which brings more error bits to the transmission process and affects the correctness of the transmission.

发明内容Contents of the invention

本发明的目的在于克服上述已有技术的缺点,提出了一种双向信道中基于最小均方误差波束成型的信息传输方法,以在中继功率受限条件下,降低波束成型矩阵的复杂度,提高系统误码率性能,避免传输过程中的错误比特,保证了传输的正确性。The purpose of the present invention is to overcome the shortcomings of the above-mentioned prior art, and proposes an information transmission method based on minimum mean square error beamforming in a two-way channel, so as to reduce the complexity of the beamforming matrix under the condition of limited relay power, Improve the bit error rate performance of the system, avoid erroneous bits during transmission, and ensure the correctness of transmission.

本发明是这样实现的:The present invention is achieved like this:

(1)采用Turbo码对两个源节点的数据信息d1,d2分别进行编码,得到编码序列x1,x2,对该编码序列进行调制,并将调制后的信号s1(n)和s2(n)以功率p1和p2同时发送至中继节点;(1) Use Turbo code to encode the data information d 1 and d 2 of the two source nodes respectively to obtain the coded sequence x 1 , x 2 , modulate the coded sequence, and convert the modulated signal s 1 (n) and s 2 (n) are simultaneously sent to the relay node with power p 1 and p 2 ;

(2)中继节点基于最小均方误差准则构建波束成型矩阵:(2) The relay node constructs the beamforming matrix based on the minimum mean square error criterion:

(2a)令HUL=[h1,h2],HDL=[h2,h1]T,h1和h2分别为源节点到中继节点的信道,对HUL进行奇异值分解HUL=U∑VH,U∈CM×2,将中继最小均方误差波束成型矩阵表示为A=U*BUH,B∈C2×2(2a) Let H UL = [h 1 , h 2 ], H DL = [h 2 , h 1 ] T , h 1 and h 2 are the channels from the source node to the relay node respectively, and perform singular value decomposition on H UL H UL =U∑V H , U∈C M×2 , express the relay minimum mean square error beamforming matrix as A=U * BU H , B∈C 2×2 ;

(2b)采用最小均方误差准则构建中继波束成型矩阵:(2b) Construct the relay beamforming matrix using the minimum mean square error criterion:

根据最小均方误差准则的接收机和发射机表达式构建中继最小均方误差波束成型矩阵:The relay minimum mean square error beamforming matrix is constructed according to the receiver and transmitter expressions of the minimum mean square error criterion:

AA MMSEMMSE == Hh DLDL Hh (( Hh DLDL Hh DLDL Hh ++ σσ nno 22 σσ aa 22 II )) ++ aa MMSEMMSE 00 00 bb MMSEMMSE (( Hh ULUL Hh Hh ULUL ++ σσ nno 22 σσ aa 22 II )) ++ Hh ULUL Hh

其中σn 2和σa 2分别为噪声功率和信号功率,aMMSE和bMMSE是构建波束成型矩阵需要求解的两个复变量,I是复单位矩阵,

Figure G2009102193421D0000022
是最小均方误差接收机表达式,
Figure G2009102193421D0000023
是最小均方误差发射机表达式;where σ n 2 and σ a 2 are noise power and signal power respectively, a MMSE and b MMSE are two complex variables that need to be solved to construct the beamforming matrix, I is the complex identity matrix,
Figure G2009102193421D0000022
is the minimum mean square error receiver expression,
Figure G2009102193421D0000023
is the minimum mean square error transmitter expression;

利用奇异值分解公式

Figure G2009102193421D0000024
Figure G2009102193421D0000025
分别对HDL H和HUL H进行分解,得到中继波束成型矩阵为:Using the singular value decomposition formula
Figure G2009102193421D0000024
and
Figure G2009102193421D0000025
The H DL H and H UL H are decomposed separately, and the relay beamforming matrix is obtained as:

AA MMSEMMSE == Hh ** ΣVΣV TT (( Hh DLDL Hh DLDL Hh ++ σσ nno 22 σσ aa 22 II )) ++ 00 aa MMSEMMSE bb MMSEMMSE 00 (( Hh ULUL Hh Hh ULUL ++ σσ nno 22 σσ aa 22 II )) ++ VΣUVΣU Hh

B MMSE = ΣV T ( H DL H DL H + σ n 2 σ a 2 I ) + 0 a MMSE b MMSE 0 ( H UL H H UL + σ n 2 σ a 2 I ) + VΣ , make B MMSE = ΣV T ( h DL h DL h + σ no 2 σ a 2 I ) + 0 a MMSE b MMSE 0 ( h UL h h UL + σ no 2 σ a 2 I ) + VΣ ,

使AMMSE=U*BMMSEUHLet A MMSE = U * B MMSE U H ;

式中BMMSE矩阵通过对源节点S1和S2的可达速率求解得到,U*为U的共轭矩阵,UH为U的共轭转置矩阵;In the formula, the B MMSE matrix is obtained by solving the reachable rate of the source nodes S 1 and S 2 , U * is the conjugate matrix of U, and U H is the conjugate transpose matrix of U;

(3)利用得到的最小均方误差波束成型矩阵,对中继节点接收到的混合信号进行最小均方误差波束成型,表示为xR(n)=AMMSEyR(n),n=1,...,N,其中yR(n)为中继节点接收到的两个源节点的混合信息;(3) Use the obtained minimum mean square error beamforming matrix to perform minimum mean square error beamforming on the mixed signal received by the relay node, expressed as x R (n) = A MMSE y R (n), n = 1 ,..., N, where y R (n) is the mixed information of the two source nodes received by the relay node;

(4)中继节点在第二个时隙将波束成型信息xR(n)广播给两个源节点,这两个源节点分别从各自接收到的信息中减去自相干扰后,通过解调得到对方源节点的信息,以在两个时隙内实现源节点之间信息的交换。(4) The relay node broadcasts the beamforming information x R (n) to two source nodes in the second time slot, and the two source nodes subtract the self-interference from the received information respectively, and then solve the Call to obtain the information of the other source node, so as to realize the exchange of information between the source nodes within two time slots.

本发明与现有技术相比,具有如下优点:Compared with the prior art, the present invention has the following advantages:

1.本发明由于在中继节点采用可达速率优化构建最小均方误差波束成型矩阵,在不对系统性能造成较大影响下,相比于最优波束成型方法极大的降低了复杂度,同时保证了传输的正确性。1. Since the present invention uses reachable rate optimization to construct the minimum mean square error beamforming matrix at the relay node, it greatly reduces the complexity compared with the optimal beamforming method without causing a great impact on system performance, and at the same time The correctness of transmission is guaranteed.

2.本发明由于在中继节点上采用了最小均方误差波束成型,使中继节点不需要译出两个源节点的发送信息而直接放大转发,可以在两个时隙完成两个源节点的信息交互,使吞吐量达到1/2符号/用户/符号周期,提高了系统吞吐量;2. Since the present invention adopts the minimum mean square error beamforming on the relay node, the relay node does not need to decode the transmission information of the two source nodes and directly amplifies and forwards, and can complete the two source nodes in two time slots The information interaction makes the throughput reach 1/2 symbol/user/symbol period, which improves the system throughput;

附图说明Description of drawings

图1是现有的无线双向中继通信网络模型示意图;Fig. 1 is the schematic diagram of existing wireless two-way relay communication network model;

图2是本发明的信息传输流程图;Fig. 2 is the flow chart of information transmission of the present invention;

图3是本发明的可达速率优化求解矩阵BMMSE的流程图;Fig. 3 is the flow chart of attainable rate optimization solution matrix B MMSE of the present invention;

图4是本发明容量域性能比较图;FIG. 4 is a comparison diagram of capacity domain performance in the present invention;

图5是本发明误码率性能比较图。Fig. 5 is a comparison chart of bit error rate performance of the present invention.

具体实施方式Detailed ways

参照图2,双向信道中基于最小均方误差波束成型的信息传输方法,包括如下步骤:Referring to Figure 2, the information transmission method based on minimum mean square error beamforming in a two-way channel includes the following steps:

步骤1,两个源节点同时发送信息Step 1, two source nodes send information at the same time

参照图1,采用Turbo码对两个源节点的数据信息d1,d2分别进行编码,得到编码序列x1,x2,对该编码序列进行调制,并将调制后的信号s1(n)和s2(n)以功率p1和p2同时发送至中继节点。Referring to Fig. 1, the data information d 1 and d 2 of the two source nodes are respectively coded by using Turbo codes to obtain coded sequences x 1 , x 2 , and the coded sequences are modulated, and the modulated signal s 1 (n ) and s 2 (n) are simultaneously sent to the relay node with power p 1 and p 2 .

步骤2,中继节点构建波束成型矩阵Step 2, the relay node constructs the beamforming matrix

中继节点根据最小均方误差准则构造波束成型矩阵:The relay node constructs the beamforming matrix according to the minimum mean square error criterion:

(2.1)令上行链路信道HUL=[h1,h2],下行链路信道HDL=[h2,h1]T,h1和h2分别为源节点到中继节点的信道,对上行链路信道HUL进行奇异值分解HUL=U∑VH,U∈CM×2,将中继最小均方误差波束成型矩阵表示为AMMSE=U*BMMSEUH,BMMSE∈C2×2(2.1) Let the uplink channel H UL = [h 1 , h 2 ], the downlink channel H DL = [h 2 , h 1 ] T , h 1 and h 2 are the channels from the source node to the relay node respectively , perform singular value decomposition on the uplink channel H UL H UL = U∑V H , U∈C M×2 , express the relay minimum mean square error beamforming matrix as A MMSE = U * B MMSE U H , B MMSEC 2×2 ;

(2.2)根据最小均方误差准则的接收机和发射机表达式构建中继最小均方误差波束成型矩阵:(2.2) Construct the relay minimum mean square error beamforming matrix according to the receiver and transmitter expressions of the minimum mean square error criterion:

AA MMSEMMSE == Hh DLDL Hh (( Hh DLDL Hh DLDL Hh ++ σσ nno 22 σσ aa 22 II )) ++ aa MMSEMMSE 00 00 bb MMSEMMSE (( Hh ULUL Hh Hh ULUL ++ σσ nno 22 σσ aa 22 II )) ++ Hh ULUL Hh

其中σn 2和σa 2分别为噪声功率和信号功率,aMMSE和bMMSE是构建波束成型矩阵需要求解的两个复变量,I是复单位矩阵,where σ n 2 and σ a 2 are noise power and signal power respectively, a MMSE and b MMSE are two complex variables that need to be solved to construct the beamforming matrix, I is the complex identity matrix,

Figure G2009102193421D0000042
为已知基于最小均方误差的接收机表达式为,
Figure G2009102193421D0000042
It is known that the receiver expression based on the minimum mean square error is,

Figure G2009102193421D0000043
为已知基于最小均方误差的发射机表达式为,
Figure G2009102193421D0000043
The expression for the known transmitter based on the minimum mean square error is,

(2.3)利用奇异值分解公式

Figure G2009102193421D0000044
对HDL H和HUL H分别进行分解,代入上述最小均方误差波束成型矩阵,将其转化为:(2.3) Using the singular value decomposition formula
Figure G2009102193421D0000044
and Decompose H DL H and H UL H respectively, substitute into the above minimum mean square error beamforming matrix, and transform it into:

AA MMSEMMSE == Hh ** ΣVΣV TT (( Hh DLDL Hh DLDL Hh ++ σσ nno 22 σσ aa 22 II )) ++ 00 aa MMSEMMSE bb MMSEMMSE 00 (( Hh ULUL Hh Hh ULUL ++ σσ nno 22 σσ aa 22 II )) ++ VΣUVΣU Hh

B MMSE = ΣV T ( H DL H DL H + σ n 2 σ a 2 I ) + 0 a MMSE b MMSE 0 ( H UL H H UL + σ n 2 σ a 2 I ) + VΣ , make B MMSE = ΣV T ( h DL h DL h + σ no 2 σ a 2 I ) + 0 a MMSE b MMSE 0 ( h UL h h UL + σ no 2 σ a 2 I ) + VΣ ,

使AMMSE=U*BMMSEUHLet A MMSE = U * B MMSE U H ;

式中U*为U的共轭矩阵,UH为U的共轭转置矩阵,BMMSE矩阵通过对源节点S1和S2的可达速率求解得到;In the formula, U * is the conjugate matrix of U, U H is the conjugate transpose matrix of U, and the B MMSE matrix is obtained by solving the attainable rates of source nodes S 1 and S 2 ;

(2.4)参照图3,利用源节点可达速率优化求解BMMSE矩阵:(2.4) With reference to Fig. 3, optimize the B MMSE matrix by using the reachable rate of the source node:

首先,引进向量α=[α21,α12]T

Figure G2009102193421D0000048
Figure G2009102193421D0000049
Rsnm=r21+r12,r12为源节点S1通过中继节点向源节点S2传输的可达速率,r21为源节点S2通过中继节点向源节点S1传输的可达速率,对于确定的向量α,源节点可达速率优化表达式为:First, introduce the vector α=[α 21 , α 12 ] T ,
Figure G2009102193421D0000048
Figure G2009102193421D0000049
R snm =r 21 +r 12 , r 12 is the achievable transmission rate from source node S 1 to source node S 2 via relay node, and r 21 is the achievable transmission rate from source node S 2 to source node S 1 via relay node reachable rate, for a certain vector α, the optimal expression of source node reachable rate is:

MaximizeMaximize RR sumsum ,, BB RR sumsum

Subject toSubject to 11 22 loglog 22 (( 11 ++ || gg 11 TT BB MMSEMMSE gg 22 || 22 pp 22 || || BB MMSEMMSE Hh gg 11 ** || || 22 ++ 11 )) ≥&Greater Equal; αα 21twenty one RR sumsum

11 22 loglog 22 (( 11 ++ || gg 22 TT BB MMSEMMSE gg 11 || 22 pp 11 || || BB MMSEMMSE Hh gg 22 ** || || 22 ++ 11 )) ≥&Greater Equal; αα 1212 RR sumsum ,,

|| || BB MMSEMMSE gg 11 || || 22 pp 11 ++ || || BB MMSEMMSE gg 22 || || 22 pp 22 ++ trtr (( BB MMSEMMSE BB MMSEMMSE Hh )) ≤≤ PP RR

其中g1=UHh1和g2=UHh2分别为两个源节点到中继节点的等价信道,Rsum为源节点可达速率;Where g 1 =U H h 1 and g 2 =U H h 2 are the equivalent channels from the two source nodes to the relay node respectively, and R sum is the reachable rate of the source node;

其次,将上述可达速率优化转化为中继发射功率优化求解的表达式为:Secondly, the expression for transforming the above achievable rate optimization into relay transmit power optimization solution is:

MinimizeMinimize BB pp RR == || || BB MMSEMMSE gg 11 || || 22 pp 11 ++ || || BB MMSEMMSE gg 22 || || 22 pp 22 ++ trtr (( BB MMSEMMSE BB MMSEMMSE Hh ))

subject tosubject to 11 22 loglog 22 (( 11 ++ || gg 11 TT BB MMSEMMSE gg 22 || 22 pp 22 || || BB MMSEMMSE Hh gg 11 ** || || 22 ++ 11 )) ≥&Greater Equal; αα 21twenty one rr ,,

11 22 loglog 22 (( 11 ++ || gg 22 TT BB MMSEMMSE gg 11 || 22 pp 11 || || BB MMSEMMSE Hh gg 22 ** || || 22 ++ 11 )) ≥&Greater Equal; αα 1212 rr

其中r为求解过程中的一个常量;Where r is a constant in the solution process;

最后,对上述中继发射功率优化表达式进行求解,步骤如下:Finally, to solve the above relay transmission power optimization expression, the steps are as follows:

(a)设定向量α、源节点速率和的上限

Figure G2009102193421D0000058
及中继发射功率上限PR均为已知,令
Figure G2009102193421D0000059
rmin=0,
Figure G2009102193421D00000510
(a) Set the upper limit of vector α, source node speed and
Figure G2009102193421D0000058
and relay transmission power upper limit P R are known, so that
Figure G2009102193421D0000059
rmin = 0,
Figure G2009102193421D00000510

(b)根据设定的参数求解中继发射功率优化表达式,得到最优解pR *以及此时的矩阵BMMSE,如果

Figure G2009102193421D00000511
令rmin=r,否则令rmax=r;(b) Solve the relay transmission power optimization expression according to the set parameters, and obtain the optimal solution p R * and the matrix B MMSE at this time, if
Figure G2009102193421D00000511
Let r min = r, otherwise let r max = r;

(c)令δr为给定的一个常数,若rmax-rmin≥δr,利用

Figure G2009102193421D00000512
更新r的值后,返回步骤(b)执行循环,继续求解中继发射功率优化表达式,直到rmax-rmin≤δr,循环结束,最终得到矩阵BMMSE。(c) Let δ r be a given constant, if r max -r min ≥ δ r , use
Figure G2009102193421D00000512
After updating the value of r, return to step (b) to execute the loop, and continue to solve the relay transmission power optimization expression until r max -r min ≤δ r , the loop ends, and the matrix B MMSE is finally obtained.

步骤3,中继节点波束成型Step 3, relay node beamforming

利用得到的最小均方误差波束成型矩阵,对中继节点接收到的混合信号进行最小均方误差波束成型,中继节点接收到的混合信号表示

Figure G2009102193421D0000061
zR(n)表示加性高斯白噪声,中继节点波束成型表示为xR(n)=AMMSEyR(n),n=1,...,N,其中AMMSE∈CM×M为中继节点最小均方误差波束成型矩阵。Using the obtained minimum mean square error beamforming matrix, the minimum mean square error beamforming is performed on the mixed signal received by the relay node, and the mixed signal received by the relay node represents
Figure G2009102193421D0000061
z R (n) represents additive white Gaussian noise, and relay node beamforming is expressed as x R (n) = A MMSE y R (n), n = 1,..., N, where A MMSEC M× M is the minimum mean square error beamforming matrix of the relay node.

步骤4,中继节点广播信息Step 4, the relay node broadcasts information

中继节点在第二个时隙将波束成型处理后的信息xR(n)广播给两个源节点,中继节点到源节点的信道分别为h1 T和h2 T,源节点S1和S2接收到的信号表示为:The relay node broadcasts the beamformed information x R (n) to two source nodes in the second time slot. The channels from the relay node to the source node are h 1 T and h 2 T respectively, and the source node S 1 and the signal received by S2 is expressed as:

ythe y 11 (( nno )) == hh 11 TT xx RR (( RR )) ++ zz 11 (( nno ))

== hh 11 TT AA MMSEMMSE hh 11 pp 11 sthe s 11 (( nno )) ++ hh 11 TT AA MMSEMMSE hh 22 pp 22 sthe s 22 (( nno )) ++ hh 11 TT AA MMSEMMSE zz RR ++ zz 11 (( nno )) ,,

ythe y 22 (( nno )) == hh 22 TT xx RR (( RR )) ++ zz 22 (( nno ))

== hh 22 TT AA MMSEMMSE hh 22 pp 22 sthe s 22 (( nno )) ++ hh 22 TT AA MMSEMMSE hh 11 pp 11 sthe s 11 (( nno )) ++ hh 22 TT AA MMSEMMSE zz RR (( nno )) ++ zz 22 (( nno )) ,,

其中z1(n)和z2(n)分别为中继节点到源节点S1和S2的加性高斯白噪声,源节点分别从各自接收到的信息中减去自相干扰

Figure G2009102193421D0000066
Figure G2009102193421D0000067
后,通过解调得到对方源节点的信息,从而在两个时隙内实现源节点之间信息的交换。where z 1 (n) and z 2 (n) are the additive white Gaussian noise from the relay node to the source nodes S 1 and S 2 respectively, and the source nodes subtract the self-phase interference from the received information respectively
Figure G2009102193421D0000066
and
Figure G2009102193421D0000067
Finally, the information of the other source node is obtained through demodulation, so as to realize the exchange of information between the source nodes in two time slots.

本发明的有益结果通过以下进一步仿真说明:The beneficial results of the present invention are illustrated by the following further simulations:

仿真中采用两个源节点一个中继节点的系统模型,源节点各配置一根天线,中继节点配置四根天线,源节点信息采用turbo编码以及BPSK调制进行处理,分别对系统的容量和误码率进行仿真。In the simulation, a system model of two source nodes and one relay node is used. Each source node is configured with one antenna, and the relay node is configured with four antennas. The source node information is processed by turbo coding and BPSK modulation. The system capacity and error code rate simulation.

图4给出了本发明与现有最优波束成型方法以及两种次优波束成型方法的容量性能比较,从图4可见,本发明在降低波束成型矩阵复杂度下不会对系统容量性能带来较大影响。Fig. 4 shows the capacity performance comparison between the present invention and the existing optimal beamforming method and two suboptimal beamforming methods. As can be seen from Fig. 4, the present invention will not affect the system capacity performance while reducing the complexity of the beamforming matrix to have a greater impact.

图5给出了本发明与现有最优波束成型方法以及两种次优波束成型方法的误码率性能比较,从图5可见,本发明较好的提高了系统误码率性能,减少了传输错误比特,保证了传输的正确性。Fig. 5 has provided the bit error rate performance comparison of the present invention and existing optimal beamforming method and two kinds of suboptimal beamforming methods, as can be seen from Fig. 5, the present invention has improved system bit error rate performance preferably, has reduced Transmission of error bits ensures the correctness of transmission.

Claims (2)

1.一种双向信道中基于最小均方误差波束成型的信息传输方法,包括如下步骤:1. an information transmission method based on minimum mean square error beamforming in a two-way channel, comprising the steps: (1)采用Turbo码对两个源节点的数据信息d1,d2分别进行编码,得到编码序列x1,x2,对该编码序列进行调制,并将调制后的信号s1(n)和s2(n)以功率p1和p2同时发送至中继节点;(1) Use Turbo code to encode the data information d 1 and d 2 of the two source nodes respectively to obtain the coded sequence x 1 , x 2 , modulate the coded sequence, and convert the modulated signal s 1 (n) and s 2 (n) are simultaneously sent to the relay node with power p 1 and p 2 ; (2)中继节点基于最小均方误差准则构建波束成型矩阵:(2) The relay node constructs the beamforming matrix based on the minimum mean square error criterion: 2a)令HUL=[h1,h2],HDL=[h2,h1]T,h1和h2分别为源节点到中继节点的信道,对HUL进行奇异值分解HUL=U∑VH,U∈CM×2,将中继最小均方误差波束成型矩阵表示为AMMSE=U*BMMSEUH,BMMSE∈C2×22a) Let H UL =[h 1 , h 2 ], H DL =[h 2 , h 1 ]T, h 1 and h 2 are the channels from the source node to the relay node respectively, perform singular value decomposition on H UL UL =U∑V H , U∈C M×2 , express the relay minimum mean square error beamforming matrix as A MMSE =U * B MMSE U H , B MMSE ∈C 2×2 ; 2b)采用最小均方误差准则构建中继波束成型矩阵:2b) Construct the relay beamforming matrix using the minimum mean square error criterion: 根据最小均方误差准则的接收机和发射机表达式构建中继最小均方误差波束成型矩阵:The relay minimum mean square error beamforming matrix is constructed according to the receiver and transmitter expressions of the minimum mean square error criterion: AA MMSEMMSE == Hh DLDL Hh (( Hh DLDL Hh DLDL Hh ++ σσ nno 22 σσ aa 22 II )) ++ aa MMSEMMSE 00 00 bb MMSEMMSE (( Hh ULUL Hh Hh ULUL ++ σσ nno 22 σσ aa 22 II )) ++ Hh ULUL Hh 其中σn 2和σa 2分别为噪声功率和信号功率,aMMSE和bMMSE是构建波束成型矩阵需要求解的两个复变量,I是复单位矩阵,
Figure F2009102193421C0000012
是最小均方误差接收机表达式,是最小均方误差发射机表达式;
where σ n 2 and σ a 2 are noise power and signal power respectively, a MMSE and b MMSE are two complex variables that need to be solved to construct the beamforming matrix, I is the complex identity matrix,
Figure F2009102193421C0000012
is the minimum mean square error receiver expression, is the minimum mean square error transmitter expression;
利用奇异值分解公式
Figure F2009102193421C0000014
Figure F2009102193421C0000015
分别对HDL H和HUL H进行分解,得到中继波束成型矩阵为:
Using the singular value decomposition formula
Figure F2009102193421C0000014
and
Figure F2009102193421C0000015
The H DL H and H UL H are decomposed separately, and the relay beamforming matrix is obtained as:
AA MMSEMMSE == Uu ** ΣVΣV TT (( Hh DLDL Hh DLDL Hh ++ σσ nno 22 σσ aa 22 II )) ++ 00 aa MMSEMMSE bb MMSEMMSE 00 (( Hh ULUL Hh Hh ULUL ++ σσ nno 22 σσ aa 22 II )) ++ VΣUVΣU Hh B MMSE = ΣV T ( H DL H DL H + σ n 2 σ a 2 I ) + 0 a MMSE b MMSE 0 ( H UL H H UL + σ n 2 σ a 2 I ) + VΣ , make B MMSE = ΣV T ( h DL h DL h + σ no 2 σ a 2 I ) + 0 a MMSE b MMSE 0 ( h UL h h UL + σ no 2 σ a 2 I ) + VΣ , 使AMMSE=U*BMMSEUHLet A MMSE = U * B MMSE U H ; 式中BMMSE矩阵通过对源节点S1和S2的可达速率求解得到,U*为U的共轭矩阵,UH为U的共轭转置矩阵;In the formula, the B MMSE matrix is obtained by solving the reachable rate of the source nodes S 1 and S 2 , U * is the conjugate matrix of U, and U H is the conjugate transpose matrix of U; (3)利用得到的最小均方误差波束成型矩阵,对中继节点接收到的混合信号进行最小均方误差波束成型,表示为xR(n)=AMMSEyR(n),n=1,...,N,其中yR(n)为中继节点接收到的两个源节点的混合信息;(3) Use the obtained minimum mean square error beamforming matrix to perform minimum mean square error beamforming on the mixed signal received by the relay node, expressed as x R (n) = A MMSE y R (n), n = 1 ,..., N, where y R (n) is the mixed information of the two source nodes received by the relay node; (4)中继节点在第二个时隙将波束成型信息xR(n)广播给两个源节点,这两个源节点分别从各自接收到的信息中减去自相干扰后,通过解调得到对方源节点的信息,以在两个时隙内实现源节点之间信息的交换。(4) The relay node broadcasts the beamforming information x R (n) to two source nodes in the second time slot, and the two source nodes subtract the self-interference from the received information respectively, and then solve the Call to obtain the information of the other source node, so as to realize the exchange of information between the source nodes within two time slots.
2.根据权利要求1所述的双向信道中基于最小均方误差波束成型的信息传输方法,其中步骤2b)所述的矩阵BMMSE通过源节点的可达速率求解,按照如下步骤进行:2. the information transmission method based on minimum mean square error beamforming in the two-way channel according to claim 1, wherein step 2b) described matrix B MMSE solves by the attainable rate of source node, carries out according to the following steps: 第一步,引进向量α=[α21,α12]T,其中
Figure F2009102193421C0000021
Rsum=r21+r12,r12为源节点S1通过中继节点向源节点S2传输的可达速率,r21为源节点S2通过中继节点向源节点S1传输的可达速率,
The first step is to introduce the vector α=[α 21 , α 12 ] T , where
Figure F2009102193421C0000021
R sum =r 21 +r 12 , r 12 is the achievable transmission rate from source node S 1 to source node S 2 through relay node, and r 21 is the achievable transmission rate from source node S 2 to source node S 1 through relay node reach rate,
对于确定的向量α,源节点可达速率优化表示为:For a certain vector α, the source node reachable rate optimization is expressed as: MaximizeMaximize RR sumsum ,, BB RR sumsum Subjectsubject toto 11 22 loglog 22 (( 11 ++ || gg 11 TT BB MMSEMMSE gg 22 || 22 pp 22 || || BB MMSEMMSE Hh gg 11 ** || || 22 ++ 11 )) ≥&Greater Equal; αα 21twenty one RR sumsum ,, 11 22 loglog 22 (( 11 ++ || gg 22 TT BB MMSEMMSE gg 11 || 22 pp 11 || || BB MMSEMMSE Hh gg 22 ** || || 22 ++ 11 )) ≥&Greater Equal; αα 1212 RR sumsum || || BB MMSEMMSE gg 11 || || 22 pp 11 ++ || || BB MMSEMMSE gg 22 || || 22 pp 22 ++ trtr (( BB MMSEMMSE BB MMSEMMSE Hh )) ≤≤ PP RR 其中g1=UHh1,g2=UHh2,Rsum为源节点可达速率;Where g 1 = U H h 1 , g 2 = U H h 2 , R sum is the reachable rate of the source node; 第二步,将上述可达速率优化转化为中继发射功率优化求解的表达式为:In the second step, the above achievable rate optimization is transformed into the expression of relay transmission power optimization solution: pR=||BMMSEg1||2p1+||BMMSEg2||2p2+tr(BMMSEBMMSE H) p R =||B MMSE g 1 || 2 p 1 +||B MMSE g 2 || 2 p 2 +tr(B MMSE B MMSE H ) subject to 1 2 log 2 ( 1 + | g 1 T B MMSE g 2 | 2 p 2 | | B MMSE H g 1 * | | 2 + 1 ) ≥ α 21 r , subject to 1 2 log 2 ( 1 + | g 1 T B MMSE g 2 | 2 p 2 | | B MMSE h g 1 * | | 2 + 1 ) &Greater Equal; α twenty one r ,            1 2 log 2 ( 1 + | g 2 T B MMSE g 1 | 2 p 1 | | B MMSE H g 2 * | | 2 + 1 ) ≥ α 12 r 1 2 log 2 ( 1 + | g 2 T B MMSE g 1 | 2 p 1 | | B MMSE h g 2 * | | 2 + 1 ) &Greater Equal; α 12 r r为求解过程中的一个常量:r is a constant during the solution process: 第三步,对第二步的中继发射功率优化求解表达式进行求解:The third step is to solve the relay transmission power optimization solution expression in the second step: (a)设定向量α、源节点速率和的上限
Figure F2009102193421C0000034
及中继发射功率上限PR均为已知,令rmin=0,
(a) Set the upper limit of vector α, source node speed and
Figure F2009102193421C0000034
and relay transmission power upper limit P R are known, so that rmin = 0,
(b)根据设定的参数求解中继发射功率优化表达式,得到最优解pR *以及此时的矩阵BMMSE,如果令rmin=r,否则令rmax=r;(b) Solve the relay transmission power optimization expression according to the set parameters, and obtain the optimal solution p R * and the matrix B MMSE at this time, if Let r min = r, otherwise let r max = r; (c)令δr为给定的一个常数,若rmax-rmin≥δr,利用
Figure F2009102193421C0000038
更新r的值后,返回步骤(b)执行循环,继续求解中继发射功率优化表达式,直到rmax-rmin≤δr,循环结束,最终得到矩阵BMMSE
(c) Let δ r be a given constant, if r max -r min ≥ δ r , use
Figure F2009102193421C0000038
After updating the value of r, return to step (b) to execute the loop, and continue to solve the relay transmission power optimization expression until r max -r min ≤δ r , the loop ends, and the matrix B MMSE is finally obtained.
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