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Revision History for A370753 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
Antidiagonal products of A319840.
(history; published version)
#69 by N. J. A. Sloane at Sat Jun 22 22:39:09 EDT 2024
STATUS

proposed

approved

#68 by Stefano Spezia at Sat Jun 22 08:32:53 EDT 2024
STATUS

editing

proposed

#67 by Stefano Spezia at Sat Jun 22 08:26:58 EDT 2024
COMMENTS

a(n) is a sixth power iff n = 0, 1, or is of the form (6*m - 10)^3 with m > 1. (End);

the only seventh powers in the sequence are 1 and a(128) = 77458109039896212820250015287665035595218944^7. (End)

#66 by Stefano Spezia at Sat Jun 22 08:21:38 EDT 2024
COMMENTS

the only fifth powers in the sequence are 1 and a(32) = 227200942336^5. (End);

a(n) is a sixth power iff n = 0, 1, or is of the form (6*m - 10)^3 with m > 1. (End)

#65 by Stefano Spezia at Sat Jun 22 08:14:55 EDT 2024
COMMENTS

It appears that: (Start)

It appears that a(n) is a cube iff n = 0, 1, or is of the form (3*m - 4)^3 with m > 1. Cf. (A016791.);

It appears that the only fourth powers in the sequence are 1 and a(9) = 21743271936 = 384^4.;

the only fifth powers in the sequence are 1 and a(32) = 227200942336^5. (End)

#64 by Stefano Spezia at Sat Jun 22 08:09:10 EDT 2024
COMMENTS

It appears that the only fourth powers in the sequence are 0, 1, and 21743271936 = 384^4.

#63 by Stefano Spezia at Sat Jun 22 08:08:43 EDT 2024
COMMENTS

It appears that the only fourth powers in the sequence are 0, 1, and 21743271936 = 384^4.

#62 by Stefano Spezia at Sat Jun 22 07:50:09 EDT 2024
COMMENTS

It appears that a(n) is a cube iff n = 0, 1, or is of the form (3*m - 4)^3 with m > 1. Cf. A016791.

#61 by Stefano Spezia at Sat Jun 22 07:34:16 EDT 2024
COMMENTS

a(n) is a square iff n = 1 or congruent to {1, 3, 4} mod 5. Cf. A047206.

#60 by Stefano Spezia at Sat Jun 22 07:11:17 EDT 2024
COMMENTS

a(n) has trailing zeros iff n is congruent to 0 or 1 mod 5. Cf. A008851.

CROSSREFS