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Revision History for A324426 (Bold, blue-underlined text is an addition; faded, red-underlined text is a deletion.)

Showing entries 1-10 | older changes
a(n) = Product_{i=1..n, j=1..n} (i^3 + j^3).
(history; published version)
#28 by Vaclav Kotesovec at Fri Dec 08 04:51:15 EST 2023
STATUS

editing

approved

#27 by Vaclav Kotesovec at Fri Dec 08 04:51:08 EST 2023
STATUS

approved

editing

#26 by Vaclav Kotesovec at Sat Dec 02 03:49:20 EST 2023
STATUS

editing

approved

#25 by Vaclav Kotesovec at Sat Dec 02 03:49:11 EST 2023
FORMULA

For n>0, a(n)/a(n-1) = A272246(n)^2 / (2*n^9). - Vaclav Kotesovec, Dec 02 2023

CROSSREFS

Cf. A272246.

STATUS

approved

editing

#24 by Alois P. Heinz at Sun Nov 26 15:50:55 EST 2023
STATUS

reviewed

approved

#23 by Hugo Pfoertner at Sun Nov 26 15:28:25 EST 2023
STATUS

proposed

reviewed

#22 by Chai Wah Wu at Sun Nov 26 15:11:11 EST 2023
STATUS

editing

proposed

#21 by Chai Wah Wu at Sun Nov 26 15:11:09 EST 2023
PROG

(Python)

from math import prod, factorial

def A324426(n): return prod(i**3+j**3 for i in range(1, n) for j in range(i+1, n+1))**2*factorial(n)**3<<n # Chai Wah Wu, Nov 26 2023

STATUS

approved

editing

#20 by Vaclav Kotesovec at Wed Nov 22 09:36:53 EST 2023
STATUS

editing

approved

#19 by Vaclav Kotesovec at Wed Nov 22 09:36:38 EST 2023
FORMULA

a(n) = A079478(n) * A367543(n). - Vaclav Kotesovec, Nov 22 2023

STATUS

approved

editing