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a(n) = floor(1/{(n^4+2*n)^(1/4)}), where {}=fractional part.
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<a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a> , signature (3, -3, 1).
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Join[{3}, LinearRecurrence[{3, -3, 1}, {8, 18, 32}, 69]] (* Ray Chandler, Aug 02 2015 *)
<a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a> signature (3, -3, 1).
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_Clark Kimberling (ck6(AT)evansville.edu), _, Jan 18 2011
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Is a(n) = A001105(n) for n>=2 ?
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