(MAGMAMagma) [Floor(Fibonacci(n+2)/3-3*n/8-1/6): n in [0..40]]; // Vincenzo Librandi, Apr 28 2011
(MAGMAMagma) [Floor(Fibonacci(n+2)/3-3*n/8-1/6): n in [0..40]]; // Vincenzo Librandi, Apr 28 2011
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Accumulate[Floor[Fibonacci[Range[0, 40]]/3]] (* Harvey P. Dale, Jun 13 2022 *)
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a(n) = round(Fibonacci(n+2)/3 - 3*n/8 - 11/24).
a(n) = round(Fibonacci(n+2)/3 - 3*n/8 - 1/3).
a(n) = floor(Fibonacci(n+2)/3 - 3*n/8 - 1/6).
a(n) =ceil ceiling(Fibonacci(n+2)/3 - 3*n/8 - 3/4).
a(n) = a(n-8) + Fibonacci(n-1) + Fibonacci(n-3) - 3, n > 8.
a(n) = 2*a(n-1) - a(n-3) + a(n-8) - 2*a(n-9) + a(n-11), n > 10.
G.f.: -x^4*(1 + x^4 + x^3) / ( (1+x)*(x^2+1)*(x^2+x-1)*(x^4+1)*(x-1)^2 ).
a(9) = 0 + 0 + 0 + 0 + 1 + 1 + 2 + 4 + 7 + 11 = 26.
(MAGMA) [Floor(Fibonacci(n+2)/3-3*n/8-1/6): n in [0..40]]; // _Vincenzo Librandi, _, Apr 28 2011
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_Mircea Merca (mircea.merca(AT)profinfo.edu.ro), _, Jan 03 2011
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