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O.g.f. column k: 1/( (1 - x)*(1 - 5*x)*...*(1 - (4*k + 1)*x ) ). (End)
1;
1,1;
1,6,1;
1,31,15,1;
1,156,166,28,1;
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(Python)
def A096038(n, m):
if n < 1 or m < 1 or m > n:
return 0
elif n <=2:
return 1
else:
(Python) def A096038(n, m): ...if n < 1 or m < 1 or m > n: ......return 0 ...elif n <=2: ......return 1 ...else: ...... return A096038(n-1, m-1)+(4*m-3)*A096038(n-1, m)
print( [A096038(n, m) for n in range(20) for m in range(1, n+1)] ) # _R. J. Mathar_, Oct 11 2009
# R. J. Mathar, Oct 11 2009
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T[n_, k_] := 1/(4^(k-1)*(k-1)!) * Sum[ (-1)^(k-j-1) * (4*j+1)^(n-1) * Binomial[k-1, j], {j, 0, k-1}]; Table[T[n, k], {n, 1, 10}, {k, 1, n}] // Flatten (* Jean-François Alcover, Jan 28 2015, after Peter Bala *)
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