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Expansion in any base b >= 3 of 1/((b-1)*(b^2-b+1) ) = 1/(b^3-2b^2+2b-1). E.g., 1/14 in base 3, 1/39 in base 4, 1/84 in base 5, etc. - Franklin T. Adams-Watters, Nov 07 2006
approved
editing
editing
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a(n) = (1/30)*{7*(n mod 6)+7*[(n+1) mod 6]+2*[(n+2) mod 6]-3*[(n+3) mod 6]-3*[(n+4) mod 6]+2*[(n+5) mod 6]}, with n>=0. - Paolo P. Lava, Jan 31 2008
approved
editing
reviewed
approved
proposed
reviewed
editing
proposed