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A255418
Row 8 of Ludic array A255127.
4
23, 145, 271, 403, 523, 655, 781, 911, 1037, 1157, 1289, 1417, 1543, 1673, 1801, 1927, 2057, 2183, 2305, 2437, 2563, 2693, 2819, 2951, 3071, 3197, 3331, 3457, 3587, 3713, 3841, 3967, 4093, 4223, 4349, 4477, 4603, 4735, 4855, 4987, 5113, 5237, 5369, 5489, 5621, 5747, 5875, 6001
OFFSET
1,1
LINKS
FORMULA
a(n) = a(n-P) + S = a((n-1)%P + 1) + S*floor((n-1)/P) with period P = 92160 = A377469(8) and shift S = 11741730 = A376237(9). - M. F. Hasler, Nov 17 2024
PROG
(Scheme) (define (A255418 n) (A255127bi 8 n)) ;; Code for A255127bi given in A255127.
(PARI) my(L=vector(3913910, x, 3*x+1+x%2), m(n, k)=2^(n\/k*k)\(2^k-1)); for(i=3, 7, L=vecextract(L, 2^#L-m(#L, L[1])-1)); L255418=vecextract(L, m(#L, L[1]));
A255418(n, P=92160)=n--\P*11741730 + L255418[n%P+1] \\ M. F. Hasler, Nov 17 2024
(Python) # S can be decreased if only terms up to a smaller limit are needed.
def A255418(n, S=11741730, P=92160):
try: n-=1; return A255418.L[n]
except IndexError: return A255418.L[n%P] + n//P*S
except AttributeError: L = [x+5-x%2 for x in range(0, S, 3)]
while (k:=L[0]) < 23: L = [x for i, x in enumerate(L) if i%k]
A255418.L = L[::k]; return A255418(n+1) # M. F. Hasler, Nov 17 2024
CROSSREFS
Row 8 of A255127. See A255417 for row 7 and A255419 for row 9.
Sequence in context: A376891 A139175 A055827 * A268778 A231207 A142902
KEYWORD
nonn
AUTHOR
Antti Karttunen, Feb 22 2015
STATUS
approved