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Regression analysis: likelihood, error and entropy

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Abstract

In a regression with independent and identically distributed normal residuals, the log-likelihood function yields an empirical form of the \(\mathcal{L}^2\)-norm, whereas the normal distribution can be obtained as a solution of differential entropy maximization subject to a constraint on the \(\mathcal{L}^2\)-norm of a random variable. The \(\mathcal{L}^1\)-norm and the double exponential (Laplace) distribution are related in a similar way. These are examples of an “inter-regenerative” relationship. In fact, \(\mathcal{L}^2\)-norm and \(\mathcal{L}^1\)-norm are just particular cases of general error measures introduced by Rockafellar et al. (Finance Stoch 10(1):51–74, 2006) on a space of random variables. General error measures are not necessarily symmetric with respect to ups and downs of a random variable, which is a desired property in finance applications where gains and losses should be treated differently. This work identifies a set of all error measures, denoted by \(\mathscr {E}\), and a set of all probability density functions (PDFs) that form “inter-regenerative” relationships (through log-likelihood and entropy maximization). It also shows that M-estimators, which arise in robust regression but, in general, are not error measures, form “inter-regenerative” relationships with all PDFs. In fact, the set of M-estimators, which are error measures, coincides with \(\mathscr {E}\). On the other hand, M-estimators are a particular case of L-estimators that also arise in robust regression. A set of L-estimators which are error measures is identified—it contains \(\mathscr {E}\) and the so-called trimmed \(\mathcal{L}^p\)-norms.

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Notes

  1. The least squares method was used, although without proof, by Legendre in 1805 [28], see [17].

  2. The idea to minimize the sum of the absolute deviations of error residuals was first proposed by Boscovich in 1757 [4], see [17].

  3. Rockafellar et al. [38, 39] proposed a unifying axiomatic framework for general measures of error, deviation and risk—all of them are positively homogenous convex functionals defined on a space of r.v.’s, see also [34, 37], whereas recently, Grechuk and Zabarankin [15] analyzed sensitivity of optimal values of positively homogenous convex functionals in various optimization problems, including linear regression, to noise in the data.

  4. We assume that 0 ln 0 = 0.

  5. A deviation measure is a functional \(\mathcal{D}:\mathcal{L}^r(\Theta )\rightarrow [0,\infty ]\) satisfying axioms E2–E4 and such that \(\mathcal{D}(Z) = 0\) for constant Z, and \(\mathcal{D}(Z) > 0\) otherwise [38]. A deviation measure is called law-invariant if \(\mathcal{D}(X) = \mathcal{D}(Y)\) whenever r.v.’s X and Y have the same distribution [12].

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Acknowledgements

We are grateful to the referees for the comments and suggestions, which helped to improve the quality of the paper. The first author thanks the University of Leicester for granting him the academic study leave to do this research.

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Correspondence to Michael Zabarankin.

Appendix A: Proofs of Propositions 1–6

Appendix A: Proofs of Propositions 16

1.1 Appendix A.1: Proof of Proposition 1

Since \(\mathcal{E}(Z)\) assumes all values in \([0,+\infty )\), the range of h is \([0,+\infty )\), hence it is continuous and \(h(0)=0\). This implies that h has a strictly increasing continuous inverse function \(h^{-1}:\mathbb {R}^+\rightarrow \mathbb {R}^+\), and

$$\begin{aligned} h^{-1}(\mathcal{E}(Z))=h^{-1}[h(\mathbb {E}[\rho (Z)])]=\mathbb {E}[\rho (Z)]. \end{aligned}$$

For constant \(Z=t\geqslant 0\),

$$\begin{aligned} \rho (t)=\mathbb {E}[\rho (t)]=h^{-1}(\mathcal{E}(t))=h^{-1}(|t|\mathcal{E}(1)). \end{aligned}$$

Similarly, \(\rho (t)=h^{-1}(|t|\mathcal{E}(-1))\) for \(t\leqslant 0\). Consequently, in general,

$$\begin{aligned} \rho (t)=h^{-1}\left( a\,[t]_+ +b\,[t]_-\right) , \end{aligned}$$

where \(a=\mathcal{E}(1)>0\) and \(b=\mathcal{E}(-1)>0\). Thus,

$$\begin{aligned} \mathcal{E}(Z)=\varphi ^{-1}\left( \mathbb {E}\left[ \varphi \left( \,a\,[Z]_++b\,[Z]_-\,\right) \right] \right) , \end{aligned}$$
(28)

where \(\varphi =h^{-1}\).

Since \(\Theta =(\Omega , \mathcal{M}, \mathbb {P})\) is non-trivial, there exists an event \(A\in \mathcal{M}\) such that \(p=\mathbb {P}[A]\in (0,1)\). For any non-negative constants c and d, let Z be an r.v. assuming values \(Z(\omega )=c/a\geqslant 0\) and \(Z(\omega )=d/a\geqslant 0\) for \(\omega \in A\) and \(\omega \not \in A\), respectively. Then

$$\begin{aligned} \begin{aligned} \varphi ^{-1}\left[ p \varphi (\lambda c) + (1-p)\varphi (\lambda d)\right]&= \mathcal{E}(\lambda \,Z) = \lambda \,\mathcal{E}(Z) \\&= \lambda \varphi ^{-1}\left[ p \varphi (c) + (1-p)\varphi (d)\right] \end{aligned} \end{aligned}$$
(29)

for any \(\lambda \geqslant 0\). Replacing c and d by \(\varphi ^{-1}(c)\) and \(\varphi ^{-1}(d)\), respectively, and applying \(\varphi (\cdot )\) to the left-hand and right-hand parts of (29), we obtain

$$\begin{aligned} p \varphi (\lambda \varphi ^{-1}(c)) + (1-p)\varphi (\lambda \varphi ^{-1}(d)) = \varphi (\lambda \varphi ^{-1}(pc + (1-p)d). \end{aligned}$$

Consequently, the function \(g(x)=\varphi (\lambda \varphi ^{-1}(x))\) satisfies

$$\begin{aligned} pg(c)+(1-p)g(d)=g(pc + (1-p)d) \quad \forall c,d\geqslant 0. \end{aligned}$$
(30)

Let

$$\begin{aligned} \mathcal{A}=\{a\in [0,1] \, : \, a g(c) + (1-a) g(d) = g(a c + (1-a)d) \,\, \forall c,d\geqslant 0 \}. \end{aligned}$$

By definition, \(0\in \mathcal{A}\) and \(1\in \mathcal{A}\). Also, (30) implies that \(p a + (1-p)b \in \mathcal{A}\) whenever \(a,b\in \mathcal{A}\), hence \(\mathcal{A}\) is a dense subset of [0, 1]. Finally, \(\mathcal{A}\) is closed due to continuity of g, so that \(\mathcal{A}=[0,1]\), and g is a linear function. Since \(g(0)=\varphi (\lambda \varphi ^{-1}(0))=0\), there exists a constant \(C(\lambda )\) such that

$$\begin{aligned} \varphi (\lambda \varphi ^{-1}(x))=g(x)=C(\lambda )x \quad \forall x, \lambda \geqslant 0. \end{aligned}$$
(31)

Setting \(x=\varphi (y)\) in (31), we obtain

$$\begin{aligned} \varphi (\lambda y)=C(\lambda )\varphi (y) \quad \forall y, \lambda \geqslant 0. \end{aligned}$$
(32)

Then setting \(y=1\) in (32), we obtain \(\varphi (\lambda )=C(\lambda )\varphi (1)\). Consequently, \(C(\lambda )=\varphi (\lambda )/\varphi (1)\), and (32) takes the form \(\varphi (\lambda y)=\varphi (\lambda )\varphi (y)/\varphi (1)\quad \forall y, \lambda \geqslant 0\). For the function

$$\begin{aligned} g(x)=\log \frac{\varphi (e^x)}{\varphi (1)}, \end{aligned}$$

this implies that

$$\begin{aligned} g(x+y)= \log \frac{\varphi (e^{x+y})}{\varphi (1)} = \log \frac{\varphi (e^{x})\varphi (e^{y})}{\varphi (1)^2}=g(x)+g(y). \end{aligned}$$

Since g is additive, continuous, and \(g(0)=0\), it is linear, i.e., \(g(x)=px\) for some constant p. Consequently, \(e^{px}=e^{g(x)}=\varphi (e^x)/\varphi (1)\). Finally, with \(e^x=y\), we obtain \(\varphi (y)=\varphi (1)y^p\), and (28) simplifies to

$$\begin{aligned} \mathcal{E}(Z)=\left( \mathbb {E}\left[ \,a\,[Z]_+ +b\,[Z]_-\,\right] ^p\right) ^{1/p}. \end{aligned}$$

The condition \(p\geqslant 1\) follows from sub-additivity of \(\mathcal{E}\).

1.2 Appendix A.2: Proof of Proposition 2

Proposition 4.7 (b) in [11] implies that if \(Z^*\in \mathcal{C}^1(\Theta )\) has a log-concave PDF, then it is a solution to

$$\begin{aligned} \max _{Z\in \mathcal{C}^1(\Theta )} S(Z)\quad \text {subject to}\quad \mathbb {E}[Z]=\mu , \quad \mathcal{D}(Z)\leqslant 1, \end{aligned}$$
(33)

for \(\mu =\mathbb {E}[Z^{*}]\) and some law-invariant the deviation measureFootnote 5\(\mathcal{D}\). Hence \(Z^*\) is a solution to with \(\mathcal{X}=\{Z\in \mathcal{C}^1(\Theta )\,|\,\mathbb {E}[Z]=\mu ,\,\mathcal{D}(Z)\leqslant 1\}\).

Conversely, let \(Z^*\in \mathcal{C}^1(\Theta )\) be a solution to (13) for some convex closed law-invariant set \(\mathcal{X}\). Then it is a solution to (33) for the deviation measure

$$\begin{aligned} \mathcal{D}(Z)=\sup \limits _{\alpha \in [0,1]}\frac{\mathrm{CVaR}_\alpha ^\Delta (Z)}{\mathrm{CVaR}_\alpha ^\Delta (Z^*)} \quad \hbox { for all}\ Z\in \mathcal{L}^1(\Theta ), \end{aligned}$$
(34)

where

$$\begin{aligned} \mathrm{CVaR}_\alpha ^\Delta (Z)\equiv \mathbb {E}[Z]-\frac{1}{\alpha }\int \nolimits _{0}^{\alpha }q_Z(s)\,ds, \quad \alpha \in (0,1), \end{aligned}$$

\(\mathrm{CVaR}_{0}^\Delta (Z)=\mathbb {E}[Z]-\inf Z\) and \(\mathrm{CVaR}_{1}^\Delta (Z)=\sup Z - \mathbb {E}[Z]\), see [14]. Indeed, if an r.v. Z satisfies the constraints in (33) with \(\mathcal{D}\) given by (34), then \( \mathbb {E}[Z]=\mu =\mathbb {E}[Z^*]\), and \(\mathrm{CVaR}_\alpha ^\Delta (Z)\leqslant \mathrm{CVaR}_\alpha ^\Delta (Z^*)\) for all \(\alpha \in [0,1]\), so that Z dominates \(Z^*\) with respect to concave ordering, see Proposition 1 in [14]. Since \(Z^*\) has a PDF, the underlying probability space \(\Theta \) is, by definition, atomless, and part “(a) to (d)” of Corollary 2.61 in [9] along with Lemma 4.2 in [22] implies that \(Z \in \mathcal{X}\). Since \(Z^*\in \mathcal{C}^1(\Theta )\) is a solution to (13), this yields \(S(Z^*)\geqslant S(Z)\), and consequently, \(Z^*\) is a solution to (33). Thus, \(Z^*\) has a log-concave PDF by Proposition 4.11 in [11].

1.3 Appendix A.3: Proof of Proposition 3

If \(Z^*\in \mathcal{C}^1(\Theta )\) has a log-concave PDF, then it is a solution to (33) for some law-invariant deviation measure \(\mathcal{D}\). On the other hand, Proposition 5.1 in [45] shows that problem (33) is equivalent to (14) with an error measure \(\mathcal{E}\) such that \(\mathcal{D}(Z)=\inf _{C\in \mathbb {R}} \mathcal{E}(Z-C)\), i.e., \(\mathcal{D}\) is the deviation measure projected from \(\mathcal{E}\). In general, for a given deviation measure \(\mathcal{D}\), such an error measure is non-unique and can be determined by

$$\begin{aligned} \mathcal{E}(Z)=\frac{1}{1+\mu }\left( \mathcal{D}(Z)+|\mathbb {E}[Z]|\right) , \end{aligned}$$
(35)

which is called inverse projection of \(\mathcal{D}\), see [39]. Thus, \(Z^*\) is a solution to (14) with (35).

Conversely, let \(Z^*\in \mathcal{C}^1(\Theta )\) be a solution to (14) for some law-invariant error measure \(\mathcal{E}\). Then positive homogeneity of \(\mathcal{E}\) and relation \(S(kZ)=S(Z)+\ln k,k>0\), imply that \(Z^*\) is also a solution to

$$\begin{aligned} \max _{Z\in \mathcal{L}^r(\Theta )} S(Z)\quad \text {subject to}\quad \mathcal{E}(Z)\leqslant 1. \end{aligned}$$

Since \(\{Z\,|\, \mathcal{E}(Z)\leqslant 1\}\) is a convex closed law-invariant set, \(Z^*\) has a log-concave PDF by Proposition 2.

1.4 Appendix A.4: Proof of Proposition 4

If \(\mathcal{E}\) and f satisfy the conditions of Proposition 4, then \(\mathcal{E}\) and \(\rho (t) = -\log (f(t))\) satisfy the conditions of Proposition 1. Consequently, \(\rho \) has the form in (12), which implies that \(f(t)=e^{-\rho (t)}\) has the form of (2b).

1.5 Appendix A.5: Proof of Proposition 5

Since h is strictly increasing, problem (8) with \(\mathcal{E}^*\) is equivalent to minimizing \(\mathbb {E}[\rho ^*(Z)]\) or to maximizing \(\mathbb {E}[\ln (f^*(Z))]\). For an r.v. Z such that \(\mathbb {P}[Z=z_i]=1/n,i=1,\dots ,n\), it reduces to (6).

With \(c=h\left( - \int _{-\infty }^\infty f^*(t)\ln f^*(t)\,dt\right) \), the constraint \(\mathcal{E}^*(Z)= c\) in (19) simplifies to

$$\begin{aligned} \int _{-\infty }^\infty f(t)\ln f^*(t)\,dt = \int _{-\infty }^\infty f^*(t)\ln f^*(t)\,dt, \end{aligned}$$

which holds for \(f=f^*\) and for any \(f \ne f^*\) implies that

$$\begin{aligned} -\int _{-\infty }^\infty f(t)\ln f(t)\,dt\leqslant & {} -\int _{-\infty }^\infty f(t)\ln f^*(t)\,dt \\= & {} -\int _{-\infty }^\infty f^*(t)\ln f^*(t)\,dt, \end{aligned}$$

where the first inequality follows from the non-negativity of relative entropy (Kullback-Leibler divergence between f and \(f^*\)), defined as \(D_{KL}(f||f^*)=\int _{-\infty }^\infty f(t)\ln \frac{f(t)}{f^*(t)}\,dt \geqslant 0\), see [25].

1.6 Appendix A.6: Proof of Proposition 6

We first prove the “if” part in (a) and (b). If \(\mathcal{E}\) is a particular case of (2a), it is an error measure that can be represented in the form of (11), which is (21) with M being a Lebesgue measure on (0, 1), and the “if” part in (a) follows. If \(\mathcal{E}\) is a particular case of (25), then it can be represented in the form of (23) with \(M(c,d)=\int _c^d w(\alpha ) \, d\alpha , \, 0\leqslant c<d\leqslant 1,\rho (t)=t_{a,b}^p\), and \(h(x)=x^{1/p}\). For \(Z\ne 0,q_{Z_{a,b}}^p(\alpha )\) is a non-negative non-decreasing function with \(\int _0^1 q_{Z_{a,b}}^p(\alpha ) \,d\alpha > 0\), so that \(L=\lim \limits _{\alpha \rightarrow 1} q_{Z_{a,b}}^p(\alpha ) > 0\), and we claim that

$$\begin{aligned} I=\int _0^1 w(\alpha )\,q_{Z_{a,b}}^p(\alpha )\,d\alpha > 0. \end{aligned}$$
(36)

Indeed, if \(w(\alpha )\) is a delta function at 1, (36) reduces to \(I=L>0\). Otherwise \(\lim \limits _{\alpha \rightarrow 1} w(\alpha ) > 0\), hence \(w(\alpha ^*)>0\) and \(q_{Z_{a,b}}^p(\alpha ^*)>0\) for some \(\alpha ^*<1\), and \(I \geqslant \int _{\alpha ^*}^1 w(\alpha ^*)q_{Z_{a,b}}^p(\alpha ^*) = (1-\alpha ^*)w(\alpha ^*)q_{Z_{a,b}}^p(\alpha ^*) > 0\).

Inequality \(I>0\) implies that \(\mathcal{E}(Z)\) is well-defined and satisfies E1. Property E2 is obvious, whereas E4 is proved for \(w(\alpha )=1\) in [38, Proposition 6], and the general case holds by a similar argument. Next, we claim that

$$\begin{aligned} \mathcal{E}(X+Y) \leqslant \left( \int _0^1 w(\alpha )\,(q_{X_{a,b}}+q_{Y_{a,b}})^p(\alpha )\,d\alpha \right) ^{1/p} \leqslant \mathcal{E}(X) + \mathcal{E}(Y) \end{aligned}$$
(37)

holds for all \(X,Y \in \mathcal{L}^r(\Theta )\). Indeed, the second inequality in (37) is a triangle inequality for the \(\mathcal{L}^p[0,1]\)-norm, and the first one states that

$$\begin{aligned} \int _0^1 w(\alpha )\,f(\alpha )\,d\alpha \leqslant \int _0^1 w(\alpha )\,g(\alpha )\,d\alpha \end{aligned}$$
(38)

for \(f(\alpha )=q_{(X+Y)_{a,b}}^p(\alpha )\) and \(g(\alpha )=(q_{X_{a,b}}(\alpha )+q_{Y_{a,b}}(\alpha ))^p\).

If \(f, g \in \mathcal{L}^r[0,1]\) are such that (38) holds for any non-negative non-decreasing \(w\in \mathcal{L}^1[0,1]\), we write \(g \succcurlyeq f\). The relation \(\succcurlyeq \) is

  1. (i)

    associative;

  2. (ii)

    monotone, in sense that \(f_1(\alpha ) \geqslant f_2(\alpha )\)\(\forall \alpha \in [0,1]\) implies that \(f_1 \succcurlyeq f_2\);

  3. (iii)

    \(q_{X}(\alpha ) + q_{Y}(\alpha ) \succcurlyeq q_{X+Y}(\alpha )\) for any r.v.’s \(X,Y \in \mathcal{L}^r(\Theta )\) due to sub-additivity of functional \(\mathcal{F}(Z) = \int _0^1 w(\alpha ) \, q_Z(\alpha ) \, d\alpha \), see [13, Proposition 4.3];

  4. (iv)

    \(f_1 \succcurlyeq f_2\) is equivalent to \(\int _c^1 f_1(\alpha )\,d\alpha \geqslant \int _c^1 \,f_2(\alpha )\,d\alpha \) for all \(c\in (0,1)\), which, in turn, is equivalent to \(\int _0^1 u(f_1(\alpha ))\,d\alpha \geqslant \int _0^1 u(f_2(\alpha ))\,d\alpha \) for all convex increasing u, see [35, Theorem 8]; and

  5. (v)

    \(f_1 \succcurlyeq f_2\) implies that \(u(f_1) \succcurlyeq u(f_2)\) for any convex increasing function u, which follows from (iv) and the fact that superposition of two convex increasing functions is convex increasing.

Properties (i)–(iii) imply that

$$\begin{aligned} q_{X_{a,b}}+q_{Y_{a,b}} \succcurlyeq q_{X_{a,b}+Y_{a,b}} \succcurlyeq q_{(X+Y)_{a,b}}, \end{aligned}$$

and since the function \(\xi (z)=z^p\) is convex increasing for \(z\geqslant 0\), (38) follows from (v). This finishes the proof of “if” part in (b).

Now we prove the “only if” part. Let \(\mathcal{E}\) be an error measure that can be represented in the form of either (21) or (23). Since \(\mathcal{E}(Z)\) assumes all values in \([0,+\infty ),h\) is a strictly increasing continuous function with \(h(0)=0\) and has a strictly increasing continuous inverse function \(h^{-1}:\mathbb {R}^+\rightarrow \mathbb {R}^+\). Applying \(h^{-1}\) to both parts of either (21) or (23) and setting \(Z=t\), we obtain

$$\begin{aligned} h^{-1}(\mathcal{E}(t)) = \int _0^1 \rho (t) M(d\alpha ) = \rho (t) M(0,1), \quad t \in {{\mathbb {R}}}. \end{aligned}$$

Consequently, \(M(0,1)\ne 0\) and \(\rho (t) = \frac{1}{M(0,1)}h^{-1}(\mathcal{E}(t))\). If M and \(\rho \) are replaced by \(-M\) by \(-\rho \), respectively, then \(\mathcal{E}\) in (21) remains unchanged. Consequently, without loss of generality, we may assume that \(M(0,1)>0\). Positive homogeneity of \(\mathcal{E}\) implies that

$$\begin{aligned} \rho (t)=\frac{1}{M(0,1)}\varphi \left( t_{a,b}\right) , \end{aligned}$$

where \(\varphi =h^{-1},t_{a,b}\) is given by (3), \(a=\mathcal{E}(1)>0\) and \(b=\mathcal{E}(-1)>0\). In particular, both (21) and (23) imply that

$$\begin{aligned} \mathcal{E}(Z)=\varphi ^{-1}\left( \frac{1}{M(0,1)}\int _0^1 q_{\varphi \left( aZ\right) }(\alpha )\,M(d\alpha )\right) , \quad Z\geqslant 0, \end{aligned}$$
(39)

where we used \(q_{\varphi \left( aZ\right) }(\alpha )=\varphi (q_{aZ}(\alpha ))\).

If \(M(0,\alpha )=0\) for all \(\alpha <1\), (21) reduces to \(\mathcal{E}(Z)= a\,[\sup \, Z]_+ +b\,[\sup \, Z]_-\), which is not an error measure (property E1 fails), whereas (23) simplifies to \(\mathcal{E}(Z)=\sup (Z_{a,b})\), which is a particular case of (25) with w being the Dirac delta function at 1. Otherwise there exists \(\alpha \in (0,1)\) such that \(q=M(0,\alpha )/M(0,1)>0\). Since \(\Theta \) is atomless, there exists an event \(A\in \Theta \) with \(\mathbb {P}[A]=\alpha \). Let \(0 \leqslant c \leqslant d\), and let Z be an r.v. such that \(Z(\omega )=c/a\) for \(\omega \in A\) and \(Z(\omega )=d/a\) for \(\omega \not \in A\). Then (39) implies that

$$\begin{aligned} \begin{aligned} \varphi ^{-1}\left[ q \varphi (\lambda c) + (1-q)\varphi (\lambda d)\right]&= \mathcal{E}(\lambda \,Z)= \lambda \,\mathcal{E}(Z) \\&= \lambda \varphi ^{-1}\left[ q \varphi (c) + (1-q)\varphi (d)\right] \end{aligned} \end{aligned}$$
(40)

for any \(\lambda \geqslant 0\). Expression (40) coincides with (29), and the proof of Proposition 1 implies that \(\varphi \) should be in the form of \(\varphi (y)=\varphi (1)y^p,p>0\). Consequently,

$$\begin{aligned} h(z)=\left( \frac{z}{\varphi (1)} \right) ^{1/p} = h(1) z^{1/p}, \end{aligned}$$
(41)

and

$$\begin{aligned} \rho (t)=\frac{\varphi (1)}{M(0,1)}t_{a,b}^p. \end{aligned}$$
(42)

In particular, (39) simplifies to

$$\begin{aligned} \mathcal{E}(Z)=\left( \frac{a^p}{M(0,1)}\int _0^1 q_Z(\alpha )^p\,M(d\alpha )\right) ^{1/p}, \quad Z\geqslant 0. \end{aligned}$$
(43)

Let \(0=\alpha _0\leqslant \alpha _1<\alpha _2<\alpha _3\leqslant \alpha _4=1\) be such that \(\alpha _2-\alpha _1=\alpha _3-\alpha _2\), and let

$$\begin{aligned} M_i=\frac{1}{M(0,1)}\int _{\alpha _{i-1}}^{\alpha _i} M(d\alpha ),\qquad i=1,2,3,4. \end{aligned}$$

Since \(\Theta \) is atomless, there exist events \(A,B \in \mathcal{M}\) such that \(\mathbb {P}[A]=\mathbb {P}[B]=\alpha _2\) and \(\mathbb {P}[A \cap B]=\alpha _1\). Subadditivity of \(\mathcal{E}\) implies that

$$\begin{aligned} \left[ \mathcal{E}\left( 1+\epsilon I_{\Omega /A}\right) + \mathcal{E}\left( 1+\epsilon I_{\Omega /B}\right) \right] ^p \geqslant \mathcal{E}\left( 2+\epsilon I_{\Omega /A} + \epsilon I_{\Omega /B}\right) ^p \quad \forall \epsilon >0, \end{aligned}$$

where I is an indicator function. With (43), this yields

$$\begin{aligned} 2^p\left( M_1+M_2+(1+\epsilon )^p(M_3+M_4) \right) \geqslant 2^p M_1 + (2+\epsilon )^p(M_2+M_3) + (2+2\epsilon )^p, \end{aligned}$$

which simplifies to

$$\begin{aligned}{}[(2+2\epsilon )^p - (2+\epsilon )^p] M_3\geqslant [(2+\epsilon )^p-2^p] M_2. \end{aligned}$$
(44)

Dividing both parts of (44) by \(\epsilon >0\) and taking limit \(\epsilon \rightarrow 0^+\), we obtain \(p2^{p-1}M_3\geqslant p2^{p-1}M_2\), or \(M_3\geqslant M_2\). This implies that the measure \(M(d\alpha )\) has a non-decreasing density \(\omega \) on [0, 1], which can be the Dirac delta function at the ends of the interval.

By selecting \(\alpha _1=\alpha _2-\delta \) and \(\alpha _3=\alpha _2+\delta \) and by taking \(\delta \rightarrow 0^+\), we can make \(M_3\) arbitrarily close to \(M_2\). Consequently, (44) may hold only if \((2+2\epsilon )^p - (2+\epsilon )^p\geqslant (2+\epsilon )^p-2^p\). With \(\epsilon =1\), this inequality reduces to \(4^p - 2\cdot 3^p + 2^p\geqslant 0\) and implies that \(p\geqslant 1\). If \(\mathcal{E}\) can be represented in the form of (23), inequality \(p \ge 1\) along with (41) and (42) yields (25). Moreover, \(\int _0^1 w(\alpha )d\alpha =M[0,1]>0\). To prove (b), it is left to verify that w is non-negative.

Let \(a\geqslant b\) in (25)—the case \(a \leqslant b\) is treated similarly. Since \(\Theta \) is atomless, for every \(\alpha \in (0,1/2]\), there exist events \(A,B \in \mathcal{M}\) such that \(\mathbb {P}[A]=\mathbb {P}[B]=\alpha \) and \(\mathbb {P}[A \cap B]=0\). Subadditivity of \(\mathcal{E}\) implies that

$$\begin{aligned} \mathcal{E}\left( 1-2 I_A\right) + \mathcal{E}\left( 1-2 I_B\right) \geqslant \mathcal{E}\left( 2-2 I_{A\cup B}\right) . \end{aligned}$$

With (25), this yields

$$\begin{aligned} 2 \left( b^p M(0,\alpha ) + a^p M(\alpha , 1)\right) ^{1/p} \geqslant \left( (2a)^p M(2\alpha ,1)\right) ^{1/p}, \end{aligned}$$

which simplifies to

$$\begin{aligned} a^p M(\alpha , 2\alpha ) \geqslant - b^p M(0,\alpha ) \quad \forall \alpha \in (0,1/2]. \end{aligned}$$
(45)

Let \(\alpha ^*=\sup \{\alpha : w(\alpha )<0\}\). Since \(w(\alpha )\) is non-decreasing, (45) fails for \(\alpha =\alpha ^*/2\), and consequently, \(\alpha ^*=0\). Then \(\lim \limits _{\alpha \rightarrow 0} M(\alpha , 2\alpha ) \leqslant \lim \limits _{\alpha \rightarrow 0} \alpha w(2\alpha ) = 0\), so that \(\lim \limits _{\alpha \rightarrow 0} M(0, \alpha ) \geqslant 0\) by (45), which implies that w has no negative delta function at 0 as well. This finishes the proof of (b).

Finally, suppose that \(\mathcal{E}\) has the form of (21). Then an analogue of (43) for negative r.v.’s is given by

$$\begin{aligned} \mathcal{E}(Z)=\left( \frac{b^p}{M(0,1)}\int _0^1 |q_Z(\alpha )|^p\,M(d\alpha )\right) ^{1/p}, \quad Z\leqslant 0. \end{aligned}$$
(46)

Since \(q_{-Z}(\alpha )=-q_{Z}(1-\alpha )\) for almost all \(\alpha \in (0,1)\), (46) can be written as

$$\begin{aligned} \mathcal{E}(Z')=\left( \frac{b^p}{M(0,1)}\int _0^1 |q_{Z'}(\alpha )|^p\,M'(d\alpha )\right) ^{1/p}, \quad Z'\geqslant 0, \end{aligned}$$

where \(Z'=-Z\) and \(M'\) is a measure such that \(M'(a,b)=M(1-b,1-a)\) for any interval (ab). The last expression coincides with (43) and the same argument implies that \(M'(d\alpha )\) has a non-decreasing density \(\omega '\) on (0, 1). Since \(\omega '(\alpha )=\omega (1-\alpha ),\alpha \in (0,1)\), both \(\omega \) and \(\omega '\) may be non-decreasing only if \(\omega \) is constant, which along with (41) and (42) yields (2a) and proves (a).

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Grechuk, B., Zabarankin, M. Regression analysis: likelihood, error and entropy. Math. Program. 174, 145–166 (2019). https://doi.org/10.1007/s10107-018-1256-6

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