8000 命名空间创建失败会导致服务不可用 · Issue #1009 · PowerJob/PowerJob · GitHub
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命名空间创建失败会导致服务不可用 #1009

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AMysteryMan opened this issue Oct 11, 2024 · 3 comments
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命名空间创建失败会导致服务不可用 #1009

AMysteryMan opened this issue Oct 11, 2024 · 3 comments
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@AMysteryMan
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创建命名空间时一旦填写了已经存在的code，错误提示：
ERROR: DatalntegrityViolationException: could not execute statement; SQL in/al; constraint [uidx01 namespacel; nested exception is
org.hibernate.exception.ConstraintViolationException: could not execute statement

之后服务的其他模块也无法使用，错误提示：
ERROR：JpaSystemException: could not extract ResultSet; nested exception is org.hibernate.exception.GenericJDBCException: could not extract ResultSet
@AMysteryMan AMysteryMan added the bug Something isn't working label Oct 11, 2024
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KFCFans commented Nov 2, 2024

测试无法复现，请提供详细的复现路径

@AMysteryMan
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测试无法复现，请提供详细的复现路径

你创建应用的时候，在同一个命名空间下，appName输入一个已经存在的，然后创建，这个时候出错后，整个集群服务不可用。
比如获取命名空间或者应用列表就会报错：could not extract ResultSet; nested exception is org.hibernate.exception.GenericJDBCException: could

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KFCFans commented Nov 22, 2024

我估计和 db 有关，我自己验证是无法复现的，会被 mysql 的唯一索引卡住，数据插不进去。
不过保险起见代码层做个校验吧。

KFCFans added a commit that referenced this issue Nov 22, 2024
@KFCFans
feat: appname and namespace duplicate check #1009
5081274
@KFCFans KFCFans closed this as completed Dec 8, 2024
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