1799 Tennessee gubernatorial election
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 Government |
The 1799 Tennessee gubernatorial election took place from August 1–2, 1799. Incumbent Democratic-Republican governor John Sevier was re-elected to a third term almost unanimously with 99.74% of the vote, against two opponents.
For the counties that had votes, Sevier nearly won every county with 100% of the vote except Hawkins County, where he won with 92.7% of the vote.[2]
Results
[edit]| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic-Republican | John Sevier (incumbent) | 6,404 | 99.74% | |
| Democratic-Republican | George Conway | 12 | 0.19% | |
| Democratic-Republican | Joseph Anderson | 5 | 0.07% | |
| Total votes | 6,421 | 100.00% | ||
See also
[edit]References
[edit]- ^ "Tennessee gubernatorial election, 1799 Date".
- ^ "Our Campaigns - TN - Governor Race - Aug 01, 1799". www.ourcampaigns.com. Retrieved June 2, 2024.
- ^ "Tennessee gubernatorial election, 1799".
Categories:
- 1799 Tennessee elections
- Tennessee gubernatorial elections
- 1799 United States gubernatorial elections
- 1799 in Tennessee
- 1790s in Tennessee
- 1790s Tennessee elections
- 1799 elections
- 1799 elections in North America
- 1799 elections in the United States
- United States gubernatorial elections in the 1790s
- Government of Tennessee