In this section, the notions of cut sets, strong cut sets of SVNMS are defined. Some properties of cut sets are proposed. We also investigate decomposition theorem and representation theorem of SVNMS based on cut sets.
4.1. Decomposition Theorem
Definition 9. Let,andwith. Theset of truth value function generated byis defined as follows:The strongset of truth value function generated byis defined as follows:Theset of indeterminacy value function generated byis defined as follows:The strongset of indeterminacy value function generated byis defined as follows:Theset of falsity value function generated byis defined as follows:The strongset of falsity value function generated byis defined as follows: Next, we can define the
sets as follows:
The sets, sets, sets of SVNMS satisfy the following properties:
Theorem 1. Let,with. Then,
- (1)
,,;
- (2)
,,;
- (3)
,,;
- (4)
,,;
- (5)
,,;
- (6)
,,,,.
Proof.
(1) Since , we have . From , it follows that . Thus, . Thus, . Therefore, for . Since , we have . From , it follows that . Thus, . Thus, . Hence, for .
(2) From , we can obtain . Then, , that is, . Thus, . Hence, . On the other hand, since , we have , that is, . Then, . Thus, . Hence, . Based on the above facts, we can check that for .
Since , we have . Then, , that is, ,. Then, . Hence, . On the other hand, from , we have . Thus, , that is, . Thus, . Thus, . Therefore, we can check that for .
(3) From , we have . Thus, , that is, or . Thus, or . Hence, . On the other hand, since , we have or . Thus, or , that is, . Thus, . Hence, . Using the above facts, we can check that for .
Since , we have , that is, . Thus, or . Thus, or . Hence, . On the other hand, from , we have or . Thus, or , that is, . Thus, . Hence, . Therefore, we can check that for .
(4) From , we have , that is, . Thus, for all , that is, for all . Hence, . On the other hand, from , it follows that for all . Then, for all , that is, . Then, . Thus, . Based on the above facts, we can check that for .
Since , we have , that is, . Thus, for all , that is, for all . Thus, . On the other hand, from , we have for all . Thus, for all , that is, . Thus, . Hence, . Therefore, we can check that for .
(5) The proof of (5) is similar to Theorem 1 (4).
(6) The proof of (6) is obvious from Definition 9.
The sets of SVNMS satisfy the following properties. □
Theorem 2. Let,with. Then,
- (1)
,,
,,
,;
- (2)
,,,,
,,,;
- (3)
;
- (4)
;
- (5)
,,
,,
,,
,;
- (6)
,,
,,
,,
,;
- (7)
,,,
,,,
,;
- (8)
,,,
,,,
,;
- (9)
,,,,
,,,,
where e, , .
Proof. The proofs of (1)~(4) are obtained directly from Definition 9. We denote,
where
.
where
.
(5) From , we have , , , that is, and , and , and . Thus, , , and , , , that is, , . Hence, . On the other hand, since , we have , , that is, , , and , , . Thus, and , and , and . Hence, ,, . So, . Therefore, for .
(6) Since , we have or , that is, or . Thus, or , or , or , that is, , ,. Thus, . Therefore, for .
(7) From
, we have
, that is,
for all
. Thus,
for all
. Hence,
. On the other hand, for any
, we have
for all
, that is,
for all
. Thus,
Hence,
. Therefore,
for
.
(8) The proof of (8) is similar to that of (6).
(9) Since
, we have
for all
, that is,
Thus,
, that is,
. Thus,
. On the other hand, from
, we have
, that is,
for all
. Thus,
for all
. Thus,
for all
. Hence,
. Therefore,
for
. □
Remark 3. In property (6), “” cannot be strengthened as “”. For example, let,as follows:If we choose,,, then,Obviously,.
In order to get the decomposition theorem of SVNMS, we also need to introduce the following important concepts.
Definition 10. Let,,So,is a complete lattice, andis the biggest element,is the smallest element.
Definition 11. Let,,. And for any,
Then, is a SVNMS on the universe , so we have the definition as follows:
Definition 12. Suppose,, the dot product (truncated product) ofandis defined asThat is.
Now, we can discuss the decomposition theorem of SVNMS based on the definitions and operational properties above.
Theorem 3. Letbe a SVNMS. Then for any, we have Proof. With regard to , we just need to prove for all . That is, for . Since , we have . Indeed, taking , we have , otherwise, . Thus, . Similarly, and .
Therefore, = = for . □
Next, we use an example to illustrate the idea of the decomposition theorem of SVNMS.
Example 1. Let,as follows:We show howcan be represented by180 special SVNMSs usingsets. According to Definition 9, 11 and 12, we have:where,,;where,,;where,,;where,,;where,,;where,,.
Similarly, we can get the rest of the results with special SVNMSs. It is obvious to see, Definition 13. Suppose,is a mapping, a neutrosophic nested setcan be defined inif it satisfies the following conditions:
- (1)
;
- (2)
.
Remark 4. Letbe a set which composed of all neutrosophic nested sets,, then, allsets ofare neutrosophic nested sets.
Theorem 4. Let,,, for anysatisfy
, then
- (1)
;
- (2)
, where,,;
- (3)
(I),
(II);
- (4)
.
Proof.
(1) Since
for all
, we have
Thus,
.
(2) From
, we can obtain
(3) (
I) Suppose
, then,
So,
. On the other hand, since
, we have
. Thus,
. That is,
. Thus,
. Thus,
. Therefore,
. Based on the above facts, we can obtain
.
(II) Since for any , we have
. On the other hand, from we have . It follows that there exists , such that , , , that is, . Indeed, , then, . Thus, . Thus,
. Therefore, we can obtain
- (4)
From
, we have
for
. Applying (3) (I), we get
Therefore,
Remark 5. (1) The significance of Theorem 3 (Decomposition Theorem): A SVNMS can be composed of neutrosophic nested sets which consist of self-decomposed cut sets or strong cut sets. (2) The significance of Theorem 4 (Generalized Decomposition Theorem): A collection of family sandwiched between cut or strong cut sets of a SVNMS must be neutrosophic nested sets, and such nested sets can also compose the original SVNMS.