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CN102765068A - Double hex socket open end wrench - Google Patents

Double hex socket open end wrench Download PDF

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Publication number
CN102765068A
CN102765068A CN2012101390123A CN201210139012A CN102765068A CN 102765068 A CN102765068 A CN 102765068A CN 2012101390123 A CN2012101390123 A CN 2012101390123A CN 201210139012 A CN201210139012 A CN 201210139012A CN 102765068 A CN102765068 A CN 102765068A
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hexagon
spanner
hexagonal
hex nut
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佩里·詹姆斯·理查森
布鲁斯·J·理查森
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Abstract

本发明的开口扳手可同时适用于英制和公制规格。两个常规的单一尺寸扳手被双尺寸六角扳手所取代,减少在使用时需要选用的扳手数。其中一六边形图样之尺寸可较佳地适用于配对公制规格的元件,另一六边形图样之尺寸可较佳地适用于英制规格的零件。两六边形图样较佳地偏移成30度角。

Figure 201210139012

The open-end wrench of the present invention can be used for both imperial and metric specifications. Two conventional single-size wrenches are replaced by dual-size hexagonal wrenches, reducing the number of wrenches required for use. The size of one hexagonal pattern is preferably suitable for matching metric components, and the size of the other hexagonal pattern is preferably suitable for matching imperial parts. The two hexagonal patterns are preferably offset at a 30-degree angle.

Figure 201210139012

Description

双六角套筒开口扳手Double hex socket open end wrench

技术领域 technical field

本发明主要用于手工工具,特别涉及开口或梅花扳手。The invention is primarily applicable to hand tools, and particularly relates to open-ended or Torx wrenches.

背景技术 Background technique

使用习知扳手扳动六角螺母时,开口须与螺母的至少两个相对面所啮合。图1中所示习知的梅花扳手10,具有一个手摇臂13和两个开口槽12和14。开口槽12和14的尺寸通常不相同。开口槽12和14接触并施力于约六角螺母外圈的2/3表面。When using a conventional wrench to turn the hex nut, the opening must engage at least two opposing faces of the nut. A known Torx wrench 10 shown in FIG. 1 has a crank arm 13 and two open slots 12 and 14 . Open slots 12 and 14 are generally not the same size. Open slots 12 and 14 contact and exert force on about 2/3 of the surface of the outer ring of the hexagon nut.

汽车往往是由不同国家制造的零部件组装而成。有些国家采用英制,而有些采用米制计量螺栓尺寸。许多机器由米制、英制大小的螺母和螺栓共同组装而成。常规的英制或米制手动扳手,只能适用于特定尺寸的螺母或螺栓,为满足不同工作中对米制、英制零部件的要求,机械工、机械师、电工和消费者不得不购买多种类单头扳手於工具组中。Cars are often assembled from components made in different countries. Some countries use the imperial system, while others use the metric system for measuring bolt sizes. Many machines are assembled from metric and imperial sized nuts and bolts. Conventional imperial or metric manual wrenches can only be used for nuts or bolts of specific sizes. In order to meet the requirements for metric and imperial parts in different jobs, mechanics, mechanics, electricians and consumers have to buy a variety of single-head wrenches. Wrench in tool set.

美国第5,048,379号专利所展示的是内含中间轴的四方传动双端套筒,用传统的连杆与任一端套筒相连接即可使用。但该项专利需要通过移动、旋转和更换套筒来实现英制米制尺寸的转化。此外,这项专利在实际操作时还需要添加连杆或特殊的扳手。U.S. Patent No. 5,048,379 shows a square transmission double-end sleeve with an intermediate shaft, which can be used by connecting the traditional connecting rod to either end sleeve. But this patent requires moving, rotating and changing the sleeve to achieve the imperial-metric size conversion. In addition, this patent requires the addition of a connecting rod or a special wrench for actual operation.

除了需要备有许多尺寸的扳手外,机械师及其他相关人士在安装或拆卸螺母或螺栓时,往往难以确定精确的尺寸,仅通过目测来推测需要使用的扳手大小。此外,在维修汽车时,往往很难判断一个螺栓是英制还是米制的。一般情况下,机械师在发现适合螺栓或螺母大小的扳手前,要尝试各种规格大小的扳手。他们可能要尝试几次才能确定螺栓的量制和具体尺寸。如果他们选错了尺寸,尺寸小了,扳手肯定配不上;但如果稍微选大一点,扳手用起来就比较松。但如果某一材质不够坚硬(通常是螺母),那么这种尺寸的不匹配会导致顶点的转移,会增加(通常)螺母的损坏几率。In addition to the need to have many sizes of wrenches, it is often difficult for mechanics and others to determine the exact size when installing or removing nuts or bolts, and only guess the size of the wrench that needs to be used by visual inspection. Also, when servicing a car, it is often difficult to tell if a bolt is imperial or metric. Typically, a machinist will try various sizes of wrenches before finding the right size for a bolt or nut. It may take them a few tries to determine the make and exact size of the bolt. If they pick the wrong size, undersized, the wrench won't fit, but if they pick a little bigger, the wrench will be looser. But if a material is not strong enough (usually the nut), then this size mismatch will cause the vertices to shift, increasing the chance of (usually) nut damage.

附图说明 Description of drawings

图1系一立体图,显示现有技术的开口扳手;Fig. 1 is a perspective view showing an open-end wrench of the prior art;

图2系一立体图,显示本发明之实施例之双尺寸六角开口扳手;Fig. 2 is a perspective view showing a double-size hexagonal open-end wrench of an embodiment of the present invention;

图3系图2所示双尺寸六角开口扳手的侧视图,描述了两种不同尺寸内外六边形套圈的特征;Fig. 3 is a side view of the double-sized hexagonal open-end wrench shown in Fig. 2, describing the characteristics of two different sizes of inner and outer hexagonal ferrules;

图4系图2所示双尺寸六角开口扳手的又一侧视图,描述了大小不同两种规格六边形套圈的尺寸;Fig. 4 is another side view of the double-sized hexagonal open-end wrench shown in Fig. 2, describing the dimensions of the hexagonal ferrules of two different sizes;

图5所示之表单,A列英制尺寸是外六边形套圈对边距的英制分数值,D列是以米制为单位内六边形套圈对边距的可能值,栏J是指是否推荐该尺寸的内外六边形套圈组合为双尺寸套筒;In the form shown in Figure 5, the inch size in column A is the fractional value of the outer hexagonal ferrule's distance from the side, and column D is the possible value of the inner hexagonal ferrule's distance from the side in metric units. Column J refers to Is it recommended that the inner and outer hexagonal ferrules of this size be combined into a double-sized sleeve;

图6所示之表单,A列指外六边形套圈对边距的米制尺寸,列D是内六边形套圈对边距的可能英制值,J列是指是否推荐该尺寸的内外六边形套圈组合为双尺寸套筒;In the table shown in Figure 6, column A refers to the metric dimension of the outer hexagonal ferrule across the edge, column D is the possible imperial value of the inner hexagonal ferrule across the edge, and column J indicates whether the inner and outer hexagonal ferrules are recommended. The hexagonal ferrule is combined into a double-sized sleeve;

图7所示之表单与图5相似,但包含了英制内六边形套圈对边距的最大和最小值;The form shown in Figure 7 is similar to that in Figure 5, but includes the maximum and minimum values for the distance across sides of the imperial hexagon socket ring;

图8所示之表单与图6相似,但包含了米制内六边形套圈对边距的最大和最小尺寸;The form shown in Figure 8 is similar to Figure 6, but includes the maximum and minimum dimensions for the metric hexagonal socket ferrules across the flats;

图9系一端视图,显示本发明实施例之双尺寸六角开口扳手,其外六边形套圈对边距H1=11/16英寸,内六边形套圈对边距H2=17mm组合而成。适用现有技术的扳手时,17mm的扳手被误与11/16英寸相匹配,扳手与螺栓的啮合面积11/16英寸已偏大;Fig. 9 is an end view showing a double-size hexagonal open-ended wrench according to an embodiment of the present invention, the outer hexagonal ferrule with a distance across the sides H1=11/16 inches, and the inner hexagonal ferrule with a distance across the sides H2=17mm combined . When the wrench of the prior art is used, the 17mm wrench is mistakenly matched with the 11/16 inch, and the engagement area between the wrench and the bolt is too large at 11/16 inch;

图10系一立体图,显示内六边形套圈对边距的理论最小值。Fig. 10 is a perspective view showing the theoretical minimum distance across sides of the inner hexagonal ferrule.

发明内容 Contents of the invention

本发明提供一种扳手,能同时适用两种大小不同规格的螺母和螺栓,从而减少在组装和拆卸各种尺寸的螺母和螺栓时所需选用的扳手数。根据本发明配置的扳手能缩短根据特定规格的螺母或螺栓,确定正确尺寸扳手的所需时间。本发明通过结合具有细微差距不同尺寸的套圈,实现上述功能。The invention provides a wrench which can be used for nuts and bolts of two different sizes and specifications at the same time, thereby reducing the number of wrenches required for assembling and disassembling nuts and bolts of various sizes. The wrench configured according to the invention can shorten the time needed to determine the correct size wrench according to a specific specification of nuts or bolts. The present invention achieves the above functions by combining ferrules of different sizes with slight differences.

单独考虑标准英制尺寸扳手的话,因为其间距较大或互不相同,次小尺寸之内六边形套圈小于该尺寸之外六边形套圈筒的机会较低。标准米制尺寸的扳手的间距同样较大。然而,若将英制尺寸与米制尺寸并排比较,两种量度中的若干尺寸都仅有细微的差距,这是背景介绍的讨论中提及造成选用尺寸混乱的原因。本发明教示了利用十二角扳手的优势,即它们可同时适用两种尺寸略有不同的螺母,其中一个六边形套圈用以匹配英制尺寸的零件,而另一六边形套圈则用于匹配米制尺寸的零件。两种不同尺寸的六边形套圈的设计,让用户仅需一个扳手就能适用两种规格的六角螺母。Considering the standard imperial size wrenches alone, the chances of the next smallest size inner hexagon ferrule being smaller than the outer hexagon ferrule barrel are lower due to their larger or different pitches. Standard metric-sized wrenches also have wider spacing. However, when imperial and metric sizes are compared side by side, several sizes in both measurements differ only slightly, which is the reason for the confusion in the selection of sizes mentioned in the discussion in the background introduction. This invention teaches the advantage of using dodeca wrenches in that they can accommodate two slightly different sized nuts at the same time, with one hexagonal ferrule to match inch size parts and the other hexagonal ferrule to fit For matching parts in metric dimensions. The design of two different sizes of hexagonal ferrules allows users to use only one wrench to fit two specifications of hexagonal nuts.

本发明的较佳实例包括在垂直于轴平面内旋转螺母和螺栓的扳手,该扳手包括具有中心轴的钳口,轴线周围具有由轴线的垂直面相交而成的部分圆柱状开口,该开口一端沿较大尺寸的第一六边形侧边,另一端沿较小尺寸的第二六边形的侧边,该第二六边形偏移于第一六边形围绕之轴。A preferred embodiment of the invention comprises a wrench for rotating nuts and bolts in a plane perpendicular to the axis, the wrench comprising a jaw having a central axis with a partially cylindrical opening around the axis formed by the intersection of the perpendicular planes of the axis, the opening having one end Along the side of the first hexagon of larger size, the other end is along the side of the second hexagon of smaller size, the second hexagon is offset from the axis that the first hexagon surrounds.

本发明的优势在于开口扳手能实现降低用户改变工具的次数和加快其维修速度的双重功能。The advantage of the invention is that the open-end wrench can realize the dual functions of reducing the number of times users change tools and speeding up their maintenance.

具体实施方法Specific implementation method

图2所示是本发明实施例之一开口扳手20的立体图。扳手20包含手摇臂24,尽管可选用任意形状,但基本倾向于选用椭圆形截面。手摇臂24左端25为螺母开口26,手摇臂24将扭矩转移给外六边形套圈31和内六边形套圈32。其他种类或形状的套筒接头也能同样适用。FIG. 2 is a perspective view of an open-ended wrench 20 according to an embodiment of the present invention. The wrench 20 includes the crank arm 24, and although any shape may be used, an oval cross-section is generally preferred. The left end 25 of the rocker arm 24 is a nut opening 26 , and the rocker arm 24 transfers the torque to the outer hexagonal ferrule 31 and the inner hexagonal ferrule 32 . Other types or shapes of socket joints are equally suitable.

如图3所示,螺母开口26围绕着旋转轴X,并以与中心轴平行、包含18侧面F的内表面32为界。相邻侧面之间可交替形成正值角(顺时针60°)和负值角(逆时针30°)。每个正值角以V为顶点,与相邻面形成一个袋区域(pocket)P。第一组袋区域的集合(Pouter)包含定义第一个六边形图样H1的边界(各袋区域之间由破折号连接)之每一个其他的袋区域。第二组袋区域的集合(Pinner)则定义了第二个六边形图样H2的边界(各袋之间由虚线连接)。在习知的单一尺寸扳手中,两个六边形图样的大小相等,沿X轴形成30°角;依据本发明设计之扳手,其六边形图样之对边距H1、H2不相等,而可以适用于不同尺寸的螺母。As shown in FIG. 3 , the nut opening 26 surrounds the axis of rotation X and is bounded by an inner surface 32 parallel to the central axis and containing the sides F of 18 . Positive angles (60° clockwise) and negative angles (30° counterclockwise) can be alternately formed between adjacent sides. Each positive angle takes V as the vertex and forms a pocket P with the adjacent face. The first set of pocket regions (Pouter) contains every other pocket region defining the boundary of the first hexagonal pattern H1 (pouter regions are connected by dashes). The second set of pocket regions (Pinner) defines the boundary of the second hexagonal pattern H2 (the pockets are connected by dotted lines). In the known single-size wrench, the size of the two hexagonal patterns is equal, forming an angle of 30° along the X axis; in the wrench designed according to the present invention, the distances H1 and H2 to the sides of the hexagonal patterns are not equal, and Can be used for nuts of different sizes.

图4所示是本发明实施例之一扳手20的尺寸图:其具有较大的外六边形套圈对边距(HSL)和较小的内六边形套圈对边距(HSs)。内外六边形套圈的最佳方案是沿X轴相交成角度 Figure 4 is a dimensional drawing of a wrench 20 according to an embodiment of the present invention: it has a larger outer hexagonal ferrule across the edge (HS L ) and a smaller inner hexagonal ferrule across the edge (HSs ). The optimal solution for the inner and outer hexagonal ferrules is to intersect at an angle along the X axis

大六边形图样big hexagon pattern

大六边形对边距=HSL Large hexagon opposite side distance = HS L

大六边形半径=HRL Large hexagon radius = HR L

大六边形对角线长=HDL Diagonal length of large hexagon = HD L

大六边形顶点间距=PHDL(图中未标出)Large hexagon vertex spacing = PHD L (not marked in the figure)

小六边形图样small hexagon pattern

小六边形对边距=HSsSmall hexagon opposite side distance = HSs

小六边形半径=HRsSmall hexagon radius = HRs

小六边形对角线长=HDsDiagonal length of small hexagon = HDs

小六边形顶点间距=PHDsSmall hexagon vertex spacing = PHDs

关于所适用六角螺母标准尺寸、外六边形套圈对边距HSL以及内六边形套圈对边距HSS更多尺寸信息如下:More information about the standard size of the applicable hexagon nut, the distance across the flats of the outer hexagonal ring HSL and the distance across the flats of the inner hexagonal ring HS S is as follows:

六角形半径是六角形对边距离的一半(例如:面对面直径)即:HR=1/2*HSThe radius of the hexagon is half of the distance across the sides of the hexagon (for example: face-to-face diameter), that is: HR=1/2*HS

每一个六边形套圈顶点间距(PHDs)是该六边形对角线距离减去另一六边形的半径:The distance between vertices (PHDs) of each hexagonal ring is the diagonal distance of the hexagon minus the radius of the other hexagon:

对较大的外六边形图样H1:For the larger outer hexagon pattern H1:

HDL=HRL/cos 30°HD L = HR L /cos 30°

PHDL=HDL-HRsPHD L = HD L -HRs

对较小的内六边形图样H2:For the smaller hexagon pattern H2:

HDs=HRs/cos 30°HDs=HRs/cos 30°

PHDs=HDs-HRL PHDs=HDs-HR L

大小六边形尺寸的表面接触(Surface Contact)长度分别为:The surface contact lengths of the large and small hexagons are:

SCL=PHDL/sin 30°SC L =PHD L /sin 30°

SCs=PHDs/sin 30°SCs=PHDs/sin 30°

依据本发明,上述尺寸可用于确定如何组合不同尺寸的扳手,构成各种规格的扳手。双六角扳手与螺母的吻合面F要足够大,才能在不损害螺栓角的同时套住并转动六角螺母。内六边形套圈的对边距HSs被缩小,其六边形套圈顶点间距PHDs也会缩短,扳手与螺母的吻合长度及吻合面积也会相应减少。(相反的是,若减少内六边形套圈的对边距HSs,外六边形套圈的顶点间距PHDL则会增大,与螺母的吻合面积也会相应扩大,如下图9所示。)内六边形套圈H2的标准单尺寸双六角扳手,与同尺寸的外六边形套圈理想的吻合面积至少要达80%。换言之,如图5、6、7、和8所示的I列数值最好不超过20%。内六边形套圈对边距实际超过最小尺寸的最优方案的替代选择是如图5、6、7、和8所示的F列数值,即内六边形对边距与外六边形对边距之比不低于97%。According to the present invention, the above dimensions can be used to determine how to combine wrenches of different sizes to form wrenches of various specifications. The mating surface F of the double hex wrench to the nut needs to be large enough to trap and turn the hex nut without damaging the bolt angle. The distance HSs across sides of the inner hexagonal ferrule is reduced, the distance PHDs between the vertices of the hexagonal ferrule will also be shortened, and the matching length and matching area between the wrench and the nut will be correspondingly reduced. (Conversely, if the distance across sides HSs of the inner hexagonal ferrule is reduced, the pitch distance PHDL of the outer hexagonal ferrule will increase, and the matching area with the nut will also expand accordingly, as shown in Figure 9 below. ) The standard single-size double hexagonal wrench with the inner hexagonal ferrule H2, and the ideal matching area of the outer hexagonal ferrule of the same size should reach at least 80%. In other words, the column I values shown in Figures 5, 6, 7, and 8 preferably do not exceed 20%. The alternative selection of the optimal scheme in which the distance across the inner hexagonal ferrule actually exceeds the minimum size is the value in column F shown in Figures 5, 6, 7, and 8, that is, the distance between the opposite sides of the inner hexagon and the outer hexagon The ratio of shape to side distance is not less than 97%.

图5所示A列的外六边形对边距的英制尺寸与D列的内六边形对边距的米制尺寸,用于组合成双尺寸扳手,J列是否勾选则对应该匹配是否可行,例如,图5中第8行匹配的是11/16英寸和17mm两个相近尺寸的扳手:11/16英寸(A列数值)等于0.688英寸(B列数值),而17mm(D列数值)等于0.669英寸(E列数值);所以11/16英寸较大,成为外六边形对边距HSL(A列数值),17mm成为内六边形对边距(D列数值)。套用上面的公式,内六边形对边距与外六边形对边距之比为97.4%,满足不低于97%的优选值,根据本发明实例的分析,第8行J列的勾选也表明:第8行的11/16英寸和17mm可用于匹配成双尺寸扳手。As shown in Figure 5, the inch size of the outer hexagonal distance in column A and the metric size of the inner hexagonal distance in column D are used to combine into a double-size wrench. Whether column J is checked or not corresponds to whether it should match Feasible, for example, row 8 in Figure 5 matches two wrenches of similar size, 11/16 inch and 17mm: 11/16 inch (column A value) is equal to 0.688 inch (column B value), and 17mm (column D value ) is equal to 0.669 inches (the value in column E); so 11/16 inches is larger, which becomes the outer hexagonal width HSL (value in column A), and 17mm becomes the inner hexagonal width (value in column D). Applying the above formula, the ratio of the inner hexagon to the outer hexagon is 97.4%, which satisfies the preferred value of not less than 97%. The selection also indicates that the 11/16" and 17mm on row 8 can be used to match a pair of wrenches.

图6所示A列的外六边形对边距的米制尺寸与D列的内六边形对边距的英制尺寸,用于组合成双尺寸扳手,J列是否勾选则对应该匹配是否可行,例如,图6中第7行匹配的是外六边形套圈H1对边距HSL 13mm(A列数值),内六边形套圈H2对边距HSS0.5英寸(E列数值),而13mm等于0.512英寸(B列数值),仅比0.5大了0.012。第一组六边形套圈适用于13mm规格的螺栓和螺母,第二组六边形套圈适用于0.5英寸规格的螺栓和螺母。As shown in Figure 6, the metric size of the outer hexagonal distance in column A and the inch size of the inner hexagonal distance in column D are used to combine into a double-size wrench. Whether the column J is checked or not corresponds to whether it should match It is feasible, for example, the 7th line in Figure 6 matches the outer hexagonal ferrule H1 with a distance across the sides of HSL 13mm (the value in column A), and the inner hexagonal ferrule H2 with the distance across the sides HS S 0.5 inches (the value in column E) , and 13mm is equal to 0.512 inches (value in column B), which is only 0.012 larger than 0.5. The first set of hexagonal ferrules is suitable for 13mm gauge bolts and nuts, and the second set of hexagonal ferrules is suitable for 0.5 inch gauge bolts and nuts.

此外,如图7和8的列表所示,两个相近的英制或米制尺寸的六边形套圈也能组合成双尺寸扳手。图7和8中没有双英制尺寸或双米制尺寸的组合能够满足F列的比例值高于97%或P列的比例值低于20%。但11/16英寸与11/8英寸的扳手区别不大,所以双英制和双米制组合在大尺寸扳手中的实用性更高。Additionally, as shown in the listings of Figures 7 and 8, two similar imperial or metric sized hexagonal ferrules can also be combined to form a dual size wrench. No combination of dual imperial or dual metric sizes in Figures 7 and 8 can satisfy column F values above 97% or P column values below 20%. However, there is not much difference between 11/16-inch and 11/8-inch wrenches, so the combination of double imperial and double metric is more practical in large-size wrenches.

如上所述,若减少内六边形图样的对边距HSs,外六边形图样的顶点间距(point to hex distance,PHDL)则会增大于超过第一顶点间距HRL,与螺栓的接触面积(SCL)也会相应扩大。因此,内六边形H2的对边距越小,扳手外六边形H1所产生的转动力越大。如图9所示,即使误选适用对边距17mm规格螺母的扳手,图5第8行所示扳手增加的接触面积SC(SurfaceContact)明显高于一般适用11/16英寸规格螺母的单一尺寸扳手。当内外六边形套圈沿X轴相交成角度

Figure BDA00001608351800061
时,扳手的转动力达到最大值,但其他角度同样可行。As mentioned above, if the opposite side distance HSs of the inner hexagon pattern is reduced, the vertex distance (point to hex distance, PHDL) of the outer hexagon pattern will increase beyond the first vertex distance HRL, and the contact area with the bolt ( SCL) will be expanded accordingly. Therefore, the smaller the distance across sides of the inner hexagon H2 is, the greater the turning force generated by the outer hexagon H1 of the wrench is. As shown in Figure 9, even if a wrench suitable for 17mm nuts is selected by mistake, the increased contact area SC (SurfaceContact) of the wrench shown in row 8 of Figure 5 is significantly higher than that of a single-size wrench generally suitable for 11/16-inch nuts . When the inner and outer hexagonal rings intersect along the X axis to form an angle
Figure BDA00001608351800061
, the turning force of the wrench is at its maximum, but other angles are equally possible.

如果螺栓、螺母和扳手都由坚硬的材料制成,六边形顶点间距差占标准间距的比重最好不高于20%或者当外六边形套圈对边距HSL可能大于图7中第7,9,10行以及图8中第8至18行中所列双尺寸六角扳手的匹配值时,内六边形对边距占外六边形对边距的比例不低于97%。如图10所示,内外六边形尺寸的理论最大差值或内六边形套圈的理论最小尺寸是当内六边形的对角线长HDs等于外六边形的半径HRL时,外六边形的半径HRL等于外六边形对角线长乘以sine 60°。仅当内外六边形套圈沿X轴相交成角度

Figure BDA00001608351800062
时,(HDL)*(86.6%)才能取得理论极值。If the bolts, nuts and wrenches are all made of hard materials, the proportion of the hexagonal vertex spacing difference to the standard spacing should preferably not be higher than 20% or when the outer hexagonal ring opposite side distance HSL may be greater than the HSL in Figure 7 Lines 7, 9, and 10 and the matching values of the double-sized hexagonal wrench listed in lines 8 to 18 in Figure 8, the ratio of the inner hexagon to the outer hexagon to the edge is not less than 97%. As shown in Figure 10, the theoretical maximum difference between the inner and outer hexagon sizes or the theoretical minimum size of the inner hexagon ferrule is when the diagonal length HDs of the inner hexagon is equal to the radius HRL of the outer hexagon, the outer hexagon The radius HRL of the hexagon is equal to the length of the diagonal of the outer hexagon multiplied by sine 60°. Only when the inner and outer hexagonal rings intersect along the X axis to form an angle
Figure BDA00001608351800062
, (HDL)*(86.6%) can obtain the theoretical extreme value.

依据本发明所提出的实例,在实用领域中,本领域普通技术人员可依据发明思路做相应修改。例如,若选用内外方形套筒,依据本发明设计的方形扳手同样可适用于方形螺栓和螺母。因此,以下权利要求涵盖所有对发明做出的符合本理念,属于发明范围及精神的修改。According to the examples proposed in the present invention, in the practical field, those skilled in the art can make corresponding modifications according to the idea of the invention. For example, if the inner and outer square sockets are selected, the square wrench designed according to the present invention is also suitable for square bolts and nuts. Accordingly, the following claims cover all modifications of the invention that are within the scope and spirit of the invention.

Claims (10)

1. a spanner rotates hex bolts and nut with what, and this spanner comprises:
Jaw is applicable to the first size hex nut, and when a different time, is applicable to the second size hex nut of difference.
2. spanner as claimed in claim 1, wherein said first size hex nut are measured with imperial measure, and said second size hex nut system is measured with metric system tolerance.
3. spanner as claimed in claim 1, wherein said first size hex nut and the said second size hex nut are measured with imperial measure and are had a different size.
4. spanner as claimed in claim 1, wherein said first size hex nut and the said second size hex nut are with the quilt measurement of metric system tolerance and have different size.
5. a spanner is used to rotate hex nut and bolt, and this spanner comprises:
Jaw with central shaft, and
One cylindric opening; Be positioned at around this axis; A this cylindric opening and a vertical Plane intersects that has with axis; This cylindric opening has a plurality of sides around first hexagon along large-size, and other sides around second hexagon of reduced size, and wherein this second hexagon is offset from the axle that first hexagon centers on.
6. spanner as claimed in claim 5, wherein said second hexagon becomes 30 degree angles with said first hexagon along said axle offset.
7. spanner as claimed in claim 6, the opposite of wherein said first hexagon distance be HSL, and the opposite of said second hexagon is apart from being HSs, HSs is greater than HS LMultiply by 60 ° of sine.
8. spanner as claimed in claim 7, wherein said distance H Ss is at least distance H S L97%.
9. spanner as claimed in claim 7, wherein said second hexagon is compared with one of the HSs with same size hexagon, and the decrement of its summit spacing (Point-to-HexPHDs) is less than 20% in a single size spanner.
10. Wrench comprises:
First square aperture with metric size, and
Second square aperture with second imperial sizing, said first square aperture is offset from this second square aperture rotatably.
CN2012101390123A 2011-05-05 2012-05-07 Double hex socket open end wrench Pending CN102765068A (en)

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CN107756300A (en) * 2013-11-15 2018-03-06 施耐宝公司 Sleeve driving improves
US10442060B2 (en) 2013-11-15 2019-10-15 Snap-On Incorporated Socket drive improvement
US11173580B2 (en) 2013-11-15 2021-11-16 Snap-On Incorporated Socket drive improvement
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US12157206B2 (en) 2013-11-15 2024-12-03 Snap-On Incorporated Socket drive improvement
US12162120B2 (en) 2013-11-15 2024-12-10 Snap-On Incorporated Socket drive improvement

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