OFFSET
1,2
COMMENTS
Numbers k such that b(k) is an integer, where b(n) = Sum_{k=0..n} (2*n+k)!/((2*n-2*k)!*(3*k+1)!) (= A001608(6*n+2)/(6*n+2)).
LINKS
Don Zagier, Problems posed at the St Andrews Colloquium, 1996, See "Fifth Day: Sequences and recursions, problem 2".
EXAMPLE
n | b(n)
--+--------------------------
0 | 1 (= 2/2)
1 | 5/4 (= 10/8)
2 | 51/14
3 | 277/20
4 | 1497/26
5 | 4045/16 (= 8090/32)
6 | 43721/38
7 | 118141/22 (= 236282/44)
8 | 638471/25 (= 1276942/50)
9 | 6900995/56
KEYWORD
nonn,more
AUTHOR
Seiichi Manyama, Mar 02 2019
STATUS
approved