%I #28 Sep 08 2022 08:45:59

%S 4,27,625,16807,1771561,62748517,6975757441,322687697779,

%T 41426511213649,12200509765705829,787662783788549761,

%U 243569224216081305397,37929227194915558802161,3177070365797955661914307,566977372488557307219621121,205442259656281392806087233013

%N a(n) = prime(n)^(n+1).

%C Subsequence of A000961, A120458.

%C First five elements are also consecutive members of A133018. - _Omar E. Pol_, Oct 20 2011

%C Third diagonal of A319075. - _Omar E. Pol_, Sep 13 2018

%H Bruno Berselli, <a href="/A197987/b197987.txt">Table of n, a(n) for n = 1..50</a>

%F a(n) = A000040(n)^(n+1). - _Omar E. Pol_, Oct 20 2011

%e The fourth prime number is 7, so a(4) = 7^(4+1) = 7^5 = 16807. - _Omar E. Pol_, Oct 20 2011

%t Table[Prime[n]^(n+1),{n,20}] (* _Harvey P. Dale_, Dec 16 2012 *)

%o (PARI) for(n=1, 16, print1(prime(n)^(n+1)", "));

%o (Magma) [NthPrime(n)^(n+1): n in [1..16]];

%Y Cf. A000961, A062457, A093360, A120458, A133018, A319075.

%K nonn,easy

%O 1,1

%A _Bruno Berselli_, Oct 20 2011