[go: up one dir, main page]
More Web Proxy on the site http://driver.im/
login

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

A179858
Least positive primitive root of A139035(n).
1
3, 5, 5, 7, 3, 5, 5, 19, 3, 7, 5, 6, 17, 7, 6, 5, 3, 13, 3, 5, 7, 3, 5, 11, 5, 3, 3, 11, 5, 5, 5, 5, 6, 14, 3, 3, 3, 17, 5, 3, 3, 6, 13, 5, 7, 3, 5, 11, 5, 19, 3, 5, 5, 3, 6, 10, 5, 5, 14, 6, 3, 7, 5, 5, 7, 5, 3, 3, 11, 5, 5, 3, 5, 6, 7, 3, 5, 7, 3, 7, 5, 5, 5, 17
OFFSET
1,1
COMMENTS
If p is a prime, then a is called a semiprimitive root if it has order (p-1)/2 and there is no x for which a^x is congruent to -1 (mod p). So +- a^k, 0 <= k <= (p-3)/2 is a complete set of nonzero residues (mod p). A primitive root has order p-1, so a number cannot be both a primitive root and a semiprimitive root.
A139035 are the primes for which 2 is a semiprimitive root. This sequence gives the smallest positive primitive root corresponding to each term of A139035, so each term is greater than or equal to 3.
LINKS
EXAMPLE
Since A139035(13)=311, 2 is a semiprimitive root of 311 so j=0,...,154, {+-2^j} is a complete set of residues (congruent to {1,...,310}). The corresponding member of this sequence is a(13)=17 because 17 is the smallest positive integer a for which {a^k}, k=0,...,309 is a complete set of residues.
MATHEMATICA
PrimitiveRoot /@ Reap[For[p = 3, p < 3000, p = NextPrime[p], rp = MultiplicativeOrder[2, p]; rm = MultiplicativeOrder[-2, p]; If[rp != p-1 && rm == p-1, Sow[p]]]][[2, 1]] (* Jean-François Alcover, Sep 03 2016, after Joerg Arndt's code for A139035 *)
CROSSREFS
Sequence in context: A197631 A266567 A282624 * A141501 A277776 A103988
KEYWORD
nonn
AUTHOR
Vladimir Shevelev, Jan 11 2011
EXTENSIONS
More terms from Jean-François Alcover, Sep 03 2016
STATUS
approved