%I #14 Oct 31 2019 01:24:34

%S 3,9,195,515,857,11393

%N Numbers k such that the smoothly undulating palindromic number (92*10^k - 29)/99 is a prime.

%C Prime versus probable prime status and proofs are given in the author's table.

%C No further terms < 100000. - _Ray Chandler_, Aug 17 2011

%H Patrick De Geest, <a href="http://www.worldofnumbers.com/undulat.htm#supp929">SUPP Reference Table - 929</a>

%H <a href="/index/Pri#pri_supp">Index entries for sequences related to smoothly undulating palindromic primes</a>

%e k=9 -> (92*10^9 - 29)/99 = 929292929.

%Y Cf. A062209-A062232, A059758, A032758.

%K nonn,base,more

%O 1,1

%A _Patrick De Geest_ and Hans Rosenthal (Hans.Rosenthal(AT)t-online.de), Jun 15 2001

%E Edited by _Ray Chandler_, Aug 17 2011