MU and MBB are essentially the same. #399

utcke · 2025-03-06T18:05:11Z

Q_MU is the arithmetic mean of the pixel intensities in I. Assuming n by m pixels, this will be

Q_MU = 1/(m*n) \sum_i=1^n\sum_j=1^m I_i,j

Q_MBB is the mean of all regions V in I. Assuming that n and m are both divisible by 32, we get

Q_MBB = 1/(m/32n/32) \sum_a=1^n/32\sum_b=1^m/32 1/(3232) \sum_i=1^32\sum_j=1^32 I_(a-1)*32+i,(b-1)*32+j

which will give the exact same result.

In case n or m are not evenly divisible by 32, we would still get very similar results.

So I'm not sure how much sense it makes to keep both.

Provide feedback