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The Intel compilers provide a flag -fpp-name=<name> which can be used to specify an alternative preprocessor of the form:
alt_fpp [ [–D<define>]..] [[-I<include directory>]..] inputfile
which prints output to STDOUT that will get captured by the compiler for further processing.
I've tried to use this with fypp, but I run into errors:
$ ifx -fpp-name=`which fypp` -DNAME=\"Ivan\" fypp_example.F90
error: Failed to open file '@/tmp/ifxargBf8BjW' for read [FyppFatalError]
error: [Errno 2] No such file or directory: '@/tmp/ifxargBf8BjW' [FileNotFoundError]
$ ifx -fpp-name=fypp -Qlocation,fpp,/home/ivan/.local/bin -DNAME=\"Ivan\" fypp_example.F90
error: Failed to open file '@/tmp/ifxarg6DL4Me' for read [FyppFatalError]
error: [Errno 2] No such file or directory: '@/tmp/ifxarg6DL4Me' [FileNotFoundError]
It seems like the compiler prepends @ to the path, but otherwise it seems it could work. If you'd like to experiment, here is the toy code:
! fypp_example.F90
#:def hello(name)
print *, "Hello ${name}$"
#:enddef
#:if defined('NAME')
$:hello(NAME)
#:else
print *, "Hello World"
#:endif
end
Do you have any previous experience with such usage, or should I raise an issue at the Intel Fortran forum?
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