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Hello, I tried the example on Python 3.5 and realized it was not compatible. In order to make it function on this version I modified the pytagcloud/lang/counter.pyfile to look like this
# -*- coding: utf-8 -*-
import re
from pytagcloud.lang.stopwords import StopWords
from operator import itemgetter
def get_tag_counts(text):
"""
Search tags in a given text. The language detection is based on stop lists.
This implementation is inspired by https://github.com/jdf/cue.language. Thanks Jonathan Feinberg.
"""
# words = map(lambda x:x.lower(), re.findall(r'\w+', text, re.UNICODE))
# the line above doesn't work on python 3.5
s = StopWords()
s.load_language(s.guess(map(lambda x:x.lower(), re.findall(r'\w+', text, re.UNICODE))))
counted = {}
for word in map(lambda x:x.lower(), re.findall(r'\w+', text, re.UNICODE)):
if not s.is_stop_word(word) and len(word) > 1:
if word in counted: #no has_key() method on python 3, use in instead
counted[word] += 1
else:
counted[word] = 1
return sorted(counted.items(), key=itemgetter(1), reverse=True)I leave this here because I did not find a branch for python 3 and maybe someone could find it useful
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