Talk:Boron monohydride

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This compound may have 2 unpaired electrons (triplet state), see borylene and thus is a diradical. Then the formula should become HB: (see carbene). Does λ¹ indicate this is a boron(I) compound? Simon de Danser (talk) 18:07, 27 September 2020 (UTC)[reply]

@SimonDeDanser: λ¹ does indicate that the atom has only 1 bond. This is the lambda convention.[1] However we would normally write this as λ¹ to avoid strange Unicode. Graeme Bartlett (talk) 00:09, 28 September 2020 (UTC)[reply]

Our article and a reference say this is closed shell, and so singlet state. Do you have references that mention triplet/diradical state? Graeme Bartlett (talk) 00:06, 28 September 2020 (UTC)[reply]

It's funny that the symbol is litterally HB, now we need to transform BH3 to H3B (H=B=H=H), as they are funny (If you know, you know!) HydroBoron (talk) 18:41, 16 June 2024 (UTC)[reply]

In Hill notation the elements are in alphabetical order of their symbols, so it would use BH. But some writers do use HB. HydroBoron, I am surprised you registered an account just to express your joy at this "joke". Graeme Bartlett (talk) 23:14, 16 June 2024 (UTC)[reply]